Chapter 4 — Stoichiometry 1 2 STOICHIOMETRY John C. Kotz Paul M. Treichel John Townsend http://academic.cengage.com/kotz - the study of the quantitative aspects of chemical reactions. Chapter 4 Chemical Equations and Stoichiometry John C. Kotz • State University of New York, College at Oneonta © 2009 Brooks/Cole - Cengage 3 Gravimetric Analysis • • • 4 Determining the Formula of an Organic Compound by Combustion A 0.123 g impure sample of the mineral thenardite contains Na2SO4 (142.0 g/1 mol). What is the mass percent of Na2SO4 in the mineral? Na2SO4 + BaCl2(aq) → 2 NaCl(aq) + BaSO4(s) Collect and dry BaSO4 (233.4 g/mol); mass of BaSO4 = 0.177 g 0.177g BaSO 4 ! © 2009 Brooks/Cole - Cengage 1molBaSO 4 1molNa 2SO 4 142.0g Na 2SO 4 ! ! 233.4g BaSO 4 molBaSO 4 molNa 2SO 4 ! 100% = 87.5% 0.123g mineral PLAY MOVIE © 2009 Brooks/Cole - Cengage See Active Figure 4.7 Chapter 4 — Stoichiometry 2 Using Stoichiometry to Determine a Formula 5 6 What’s wrong with this technique? Caproic acid, which is responsible for the foul odor of dirty socks, is composed of C, H, and O atoms (CxHyOz). Combustion of 0.225 g produces 0.512 g CO2 and 0.209 g H2O. What is the empirical formula? 1.00 L of water was added to 0.10 mol of CuSO4⋅5H2O to make a 0.10M solution. CxHyOz + excess O2 → x CO2 + y/2 H2O • Determine mass of C in CO2, mass of H in H2O • Calculate mass of O by difference • Calculate moles of C, H, O 1.00 L of 0.100 M CuSO4 All the water didn’t fit! Ans: C3H6O © 2009 Brooks/Cole - Cengage 25.0 g or 0.100 mol of CuSO4⋅5H2O © 2009 Brooks/Cole - Cengage 7 8 Preparing a Solution PROBLEM: Dissolve 5.00 g of NiCl2•6 H2O in enough water to make 250. mL of solution. Calculate molarity. Step 1: Calculate moles of NiCl2• 6H2O Molar mass of NiCl2 •6H2O includes 6 H2O! ! 1 mol $ 5.00 g # & = 0.0210 mol " 237.7 g % Distilled water is added to fill the flask with solution just to the mark on the flask. Step 2: Calculate molarity 250 mL volumetric flask 0.0210 mol = 0.0841 M 0.250 L PLAY MOVIE © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage 0.435 g KMnO4 The KMnO4 is first dissolved in a small amount of water. A mark on the neck of a volumetric flask indicates the volume of exactly 250 mL at 25°C. Chapter 4 — Stoichiometry 3 The Nature of a CuCl2 Solution: Ion Concentrations 9 10 PROBLEM: You have 50.0 mL of 3.0 M NaOH and you want 0.50 M NaOH. What do you do? CuCl2(aq) → Cu2+(aq) + 2 Cl-(aq) How much water do we add? If [CuCl2] = 0.30 M, then [Cu2+] = 0.30 M [Cl-] = 2 x 0.30 M 0.050L of moles of NaOH in ORIGINAL solution = moles of NaOH in FINAL solution © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage 11 Preparing Solutions by Dilution You have 50.0 mL of 3.0 M NaOH and you want 0.50 M NaOH. What do you do? Cinitial • Vinitial = Cfinal • Vfinal 0.050L of Where C = concentration in M or wt % M1V1 = M2V2 3.0 mol/L × 0.050L = 0.50 mol/L × V2 L where V2 = FINAL volume V2 = 0.30L ANS: add 250 mL of water to 50.0 mL of 3.0 M NaOH; dilute to final volume of 300 mL Note: V2 = 300 mL; volume of water added ≠ 300 mL © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage 12 Chapter 4 — Stoichiometry 4 13 Preparing a Solution by Dilution 14 SOLUTION STOICHIOMETRY • Zinc reacts with acids to produce H2 gas. • Have 10.0 g of Zn • What volume of 2.50 M HCl is needed to convert the Zn completely? Zn + 2 HCl → ZnCl2 + H2 0.100 M K2Cr2O7 Use a 5.00-mL pipet to withdraw 5.00 mL of a 0.100 M K2Cr2O7 solution. Add the 5.0- mL sample of 0.100 M K2Cr2O7 solution to a 500-mL volumetric flask. Fill the flask to the mark with distilled water to give 0.00100 M K2Cr2O7 solution. 10.0 g Zn × © 2009 Brooks/Cole - Cengage 1 mol Zn 2 mol HCl 1 L HCl × × = 0.122 L HCl 65.4 g mol Zn 2.50 mol HCl © 2009 Brooks/Cole - Cengage 15 ACID-BASE REACTIONS Titrations How much acetic acid is contained in a sample of vinegar? Titrate the acid with a known concentration of base: HC2H3O2(aq) + NaOH(aq) → NaC2H3O2 (aq) + H2O acid © 2009 Brooks/Cole - Cengage base 16 Setup for titrating an acid with a base Flask containing aqueous sample of sample being analyzed (a) Buret containing aqueous NaOH of accurately known concentration. © 2009 Brooks/Cole - Cengage (b) Solution of NaOH is added slowly to the sample being analyzed. (c) When the amount of NaOH added from the buret exactly equals the amount of H+ supplied by the acid being analyzed, the dye (indicator) changes color. Chapter 4 — Stoichiometry 5 17 Must standardize the solution of NaOH — i.e., accurately determine its concentration. 18 Use standardized NaOH to determine the amount of an acid in an unknown. Use a primary standard which is a monoprotic acid, e.g. KHC8H4O4, potassium hydrogen phthalate (KHP) Apples contain malic acid, C4H6O5, a diprotic acid C4H6O5 + 2 NaOH → Na2C4H4O5 + 2 H2O – Solid, pure, non-hydroscopic 4.83 g of KHP (204.2 g/mol) requires 35.62 mL of NaOH for titration to an equivalence point. What is NaOH concentration? 76.80 g of apple requires 34.56 mL of 0.664 M NaOH for titration. What is weight % of malic acid in the apple? Balanced equation: KHP + NaOH → H2O + KNaP 4.83g KHP × 0.03456 L × 1 mol KHP 1 mol NaOH × = 0.02365 mol NaOH 204.2 g mol KHP 0.664 mol NaOH 1 mol malic acid 134.1 g malic acid × × L 2 mol NaOH mol malic acid = 0.0200 76.80 g apple = 2.00% malic acid in apple 0.02365 mol NaOH = 0.664 M NaOH 0.03562 L © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage 19 Spectrophotometry 20 An Absorption Spectrophotometer Sample absorbs light in green-blue part of spectrum and transmits light in the remaining wavelengths. The sample would appear red to orange to your eye. © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage Chapter 4 — Stoichiometry 6 21 22 Spectrophotometry Spectrophotometry • BEER-LAMBERT LAW relates amount of light absorbed and the path length and solute concentration. • Amount of light absorbed by a sample depends on path length and solute concentration. Absorbance ∝ path length × concentration A=abc A = absorbance a = molar absorptivity b = path length c = concentration • There is a linear relation between A and c for a given path length and compound. Different concs of Cu2+ • This means you can find unknown solution concentration if A is measured. Same concs but different path lengths © 2009 Brooks/Cole - Cengage © 2009 Brooks/Cole - Cengage 23 Spectrophotometry • To use the Beer-Lambert law you must first calibrate the instrument at a specific wavelength, using a cell with a specific path length. Use the calibration curve to determine the unknown conc of a solution using the same cell at the same wavelength. © 2009 Brooks/Cole - Cengage
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