Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 109690, 7 pages http://dx.doi.org/10.1155/2013/109690 Research Article Abundant Explicit and Exact Solutions for the Variable Coefficient mKdV Equations Xiaoxiao Zheng,1 Yadong Shang,1,2 and Yong Huang3 1 School of Mathematics and Information Science, Guangzhou University, Guangzhou, Guangdong 510006, China Key Laboratory of Mathematics and Interdisciplinary Sciences of Guangdong, Higher Education Institutes, Guangzhou University, Guangzhou, Guangdong 510006, China 3 School of Computer Science and Educational Software, Guangzhou University, Guangzhou, Guangdong 510006, China 2 Correspondence should be addressed to Yadong Shang; [email protected] Received 30 October 2013; Accepted 7 December 2013 Academic Editor: Dianchen Lu Copyright © 2013 Xiaoxiao Zheng et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. This paper is concerned with the variable coefficients mKdV (VC-mKdV) equation. First, through some transformation we convert VC-mKdV equation into the constant coefficient mKdV equation. Then, using the first integral method we obtain the exact solutions of VC-mKdV equation, such as rational function solutions, periodic wave solutions of triangle function, bell-shape solitary wave solution, kink-shape solitary wave solution, Jacobi elliptic function solutions, and Weierstrass elliptic function solution. Furthermore, with the aid of Mathematica, the extended hyperbolic functions method is used to establish abundant exact explicit solution of VC-mKdV equation. By the results of the equation, the first integral method and the extended hyperbolic function method are extended from the constant coefficient nonlinear evolution equations to the variable coefficients nonlinear partial differential equation. 1. Introduction It is well known that the KdV equation plays an important role in the soliton theory. Many properties of the KdV equation, such as symmetry, BaΜcklund transformation, infinite conservation laws, Lax pairs, and Painleve analysis, have been studied. Miura transformation links the KdV equation with the mKdV equation. Therefore, as the KdV equation, mKdV equation is also important in mathematical physics field. In recent years, some authors considered the constant coefficients mKdV equation [1β4]. However, in practical applications, the coefficients of nonlinear evolution equations vary with time and space. Therefore, the exact solution of the variable coefficient nonlinear evolution equations has a greater application value. This paper will discuss the variable coefficients mKdV equation (VC-mKdV): π’π‘ + π (π‘) π’π₯ + π (π‘) π’2 π’π₯ + π (π‘) π’π₯π₯π₯ = 0, (1) where π(π‘), π(π‘), and π(π‘) are arbitrary function of variable π‘. More recently, some properties of the variable coefficients mKdV equation have been studied [5β18]. The aim of this paper is to apply the first integral method and the extended hyperbolic function method for constructing a series of explicit exact solutions to the VC-mKdV equation (1), such as rational function solutions, periodic wave solutions of triangle functions, bell-shape solitary wave solution, kink-shape solitary wave solution, Jacobi elliptic function solutions, Weierstrass elliptic function solution, and many exact explicit solutions in form of the rational function of hyperbolic function and the rational function of triangle function. The rest of this paper is organized as follows. In Section 2, the outline of the first integral method will be given. In Section 3 we introduce a transformation to transform the VC-mKdV equation (1) into a constant coefficients mKdV equation. Section 4 is the main part of this paper; the methods are employed to seek the explicit and exact solutions 2 Abstract and Applied Analysis of the VC-mKdV equation (1). In the last section, some conclusion is given. 3. A Transformation to the VC-mKdV Equation 2. The First Integral Method In order to transfer (1) into the form of (3), we firstly do some transformations for (1). Since (1) is a variable coefficients equation and we need to transform it to the constant coefficients mKdV equation, we introduce a transformation The first-integral method, which is based on the ring theory of commutative algebra, was first proposed by Professor Feng Zhaosheng [19] in 2002. The method has been applied by Feng to solve Burgers-KdV equation, the compound BurgersKdV equation, an approximate Sine-Gordon equation in (π + 1)-dimensional space, and two-dimensional Burgers-KdV equation [20β24]. In the recent years, many authors employed this method to solve different types of nonlinear partial differential equations in physical mathematics. More information about these applications can be found in [25] and references therein. The most advantage is that the first integral method has not many sophisticated computation in solving nonlinear algebra equations compared to other direct algebra method. For completeness, we briefly outline the main steps of this method. The main steps of this method are summarized as follows. Given a system of nonlinear partial differential equations, for example, in two independent variables, π (π’π‘ , π’π₯ , π’π₯π₯ , π’π₯π‘ , . . .) = 0. (2) Using traveling wave transformation π’(π₯, π‘) = π(π), π = ππ₯ + ππ‘ + π0 and some other mathematical operations, the systems (2) can be reduced to a second-order nonlinear ordinary differential equation: σΈ σΈ σΈ π· (π, π , π ) = 0. (3) By introducing new variables π = π(π), π = πσΈ (π) or making some other transformations, we reduce ordinary differential equation (3) to a system of the first order ordinary differential equation: π’ (π₯, π‘) = π (π, π) π (π₯, π‘) , (7) where π = π(π₯, π‘), π = π(π₯, π‘). Through this transformation, we hope that (1) be changed into the form of constant coefficients mKdV equation: ππ + 24π2 ππ + ππππ = 0. (8) In order to obtain the above transformation equation, substituting (7) into (1) and assuming ππ₯ = 0, and simultaneously on both side of the formulas by dividing π(π‘)ππ₯3 , we have πππ3 ππ₯ π2 ππ2 ππ π π πππ₯ + + ( 3π‘ + π₯π₯π₯ + )π πππ₯3 πππ₯2 πππ₯ π ππ₯3 π πππ₯3 π +( + 2π 3ππ₯π₯ ππ₯ π π π + π‘ + π₯π₯π₯ + 2π₯π₯ + ) ππ (9) πππ₯2 πππ₯3 ππ₯3 ππ₯ π ππ₯3 π 3ππ₯ ππ‘ 3π ππ + ( 2π₯π₯ + ) πππ + ππππ = 0. 3 πππ₯ ππ₯ ππ₯ π Comparing the coefficients of (9) with (8), such as π2 ππ , π, ππ₯ , and so on, we have ππππ₯ = 0, πππ₯3 (10) π2 π = 24, πππ₯2 (11) π πππ₯ ππ‘ + π₯π₯π₯ + = 0, 3 3 πππ₯ π ππ₯ π πππ₯3 π (12) (In general π = 1 or π = 2), where ππ (π) (π = 0, 1, . . . , π) are real polynomials of π. According to the Division theorem from ring theory of commutative algebra, there exists polynomials πΌ(π), π½(π) of variable π in R[π] such that 2π 3ππ₯π₯ ππ₯ π π π + π‘3 + π₯π₯π₯ + 2π₯π₯ + = 0, 2 3 πππ₯ πππ₯ ππ₯ ππ₯ π ππ₯3 π (13) ππ‘ = 1, πππ₯3 (14) ππ = [πΌ (π) + π½ (π) π] π (π, π) . ππ 3ππ₯π₯ 3ππ₯ + = 0. ππ₯2 ππ₯ π (15) πσΈ = π πσΈ = π» (π, π) . (4) Suppose that the first integral of (4) has a form as follows: π π (π, π) = βππ (π) ππ = 0. (5) π=0 (6) We determine polynomials πΌ(π), π½(π), ππ (π) (π = 0, 1, 2, . . .) from (6), furthermore, obtain π(π, π). Then substituting π = π(π), π = πσΈ (π) or other transformations into (5), exact solutions to (2) are established, through solving the resulting first-order integrable differential equation. From (11) and (14), we have ππ₯ =ΜΈ 0 and π= 24πππ₯2 , π2 π= ππ‘ . ππ₯3 (16) Abstract and Applied Analysis 3 Substituting (16) into (10), (12), (13), and (15), we obtain 24ππ₯ = 0, ππ₯ π ππ₯3 ππ‘ + ππ₯π₯π₯ ππ‘ + ππ‘ ππ₯3 π ππ₯3 πππ₯ solution to the system (26), and its first integral is an irreducible polynomial in R[π , π]: (17) = 0, (18) (20) Form (18), we have ππ‘ =ΜΈ 0. Also from (20), we have ππ₯π₯ = 0 and ππ₯π₯π₯ = 0. From (17) and (18), we have that π can only be a constant. For simplicity, we take π = πΆ. Substituting this into (19), we obtain π = πΉ (π₯ β β« π (π‘) ππ‘) . (22) (23) where πΆ1 is an arbitrary constant. Thus we get s transform between VC-mKdV equation (1) with constant coefficients mKdV equation (8). 4. Explicit and Exact Solutions of the VC-mKdV Equation σΈ 3 π = βππ β ππ + πΈ. Collecting all the terms with the same power of π together and equating each coefficient to zero yield a set of nonlinear algebraic equations as follows: π2σΈ (π ) = π½ (π ) π2 (π ) , (29) π1σΈ (π ) = π½ (π ) π1 (π ) + πΌ (π ) π2 (π ) , (30) π0σΈ (π ) = π½ (π ) π0 (π ) + πΌ (π ) π1 (π ) π1 (π ) (βππ 3 β ππ + πΈ) = πΌ (π ) π0 (π ) . (31) (32) Because ππ (π ), (π = 1, 2) are polynomials, from (29) we can deduce deg[π2 (π )] = 0, π½(π ) = 0; that is π2 (π ) is a constant. For simplicity, we take π½(π ) = 0, π2 (π ) = 1. Then we determine π0 (π ), π1 (π ), and πΌ(π ). From (30), we have deg[π1 (π )] β 1 = deg[πΌ(π )] or π1 (π ) = πΌ(π ) = 0. In what follows we will discuss these two situations. In this case, (30) and (32) are satisfied. From (31), we can derive π0 (π ) = (π/2)π 4 + ππ 2 β 2πΈπ + π, where π is an integral constant. Substituting π2 (π ), π1 (π ), π0 (π ) into (27), one obtains that π σΈ = ±ββ π 4 π β ππ 2 + 2πΈπ β π. 2 (33) Based on the discussion for different parameters, we can obtain the solutions of the nonlinear ordinary differential equation (33). (25) (a) For π = πΈ = 0, (33) admits the following three general solutions: where π = π/π3 , π = 8/π2 , and πΈ is arbitrary integration constant. Let π = π(π), π = π σΈ ; (25) can be converted to a system of nonlinear ODEs as follows: π σΈ = π, = (πΌ (π ) + π½ (π ) π) (π2 (π ) π2 + π1 (π ) π + π0 (π )) . (28) (24) Integrating (24) once with respect to π, we obtain πσΈ σΈ + ππ3 + ππ = πΈ, + π1 (π ) πσΈ + π0σΈ (π ) π (1) In the case of πΌ(π ) = 0, π1 (π ) = 0. We firstly obtain explicit and exact solutions of the constant coefficients mKdV equation (8) and then obtain explicit and exact solutions of the constant coefficients mKdV equation (1). In the view of (8), we suppose π = ππ + ππ + π0 , and then we have ππσΈ + 24ππ2 πσΈ + π3 πσΈ σΈ σΈ = 0. ππ = π2σΈ (π ) π3 + 2π2 (π ) ππσΈ + π1σΈ (π ) π2 ππ +2π2 (π ) (ππ 3 + ππ β πΈ) , Substituting (23) into (16), we have π = β« π (π‘) ππ‘ + πΆ1 , where ππ , π = 0, 1, 2 are polynomial of π . According to the Division theorem, there exists polynomials πΌ(π ), π½(π ) of variable π in R[π ] such that (21) For simplicity, we take π = π₯ β β« π (π‘) ππ‘. (27) π=0 πππ₯4 π + ππ₯3 ππ‘ π + ππ₯π₯π₯ ππ‘ π + 2ππ₯π₯ ππ‘ ππ₯ + 3ππ₯π₯ ππ₯ ππ‘ = 0, ππ‘ ππ₯3 π (19) 3 (ππ₯π₯ π + ππ₯ ππ₯ ) = 0. ππ₯2 π 2 π (π (π) , π (π)) = βππ (π ) ππ = 0, (26) Now we employ the Division theorem to seek the first integral to (26). Suppose that π = π (π), π = π(π) are the nontrivial π 1 = ± β 2π cschββππ, π π 2 = ± β β π 3 = ± ππ > 0 2π sechββππ, π 1 ββπ/2π , π = 0. π < 0, π > 0 (34) 4 Abstract and Applied Analysis Combining (7), (22), (23), (34), and π(π₯, π‘) = πΆ, π = π(π), one can get the following three sets of explicit exact solutions to (1): π’1 (π₯, π‘) = ± ππΆβ π π cschβ 3 π, 4π π π’2 (π₯, π‘) = ± πΆββ π’3 (π₯, π‘) = ± π = β (ββ ππ > 0, π π sechββ 3 π, 4π π ππ < 0, πΆπ 2π [π (π₯ β β« π (π‘) ππ‘) + π0 ] , (35) π = 0, where π = π(π₯ β β« π(π‘)ππ‘) + π(β« π(π‘)ππ‘ + πΆ1 ) + π0 , πΆ, πΆ1 are arbitrary parameters, and π0 is an arbitrary constant. (b) For πΈ = 0, π = π2 /2π, we can obtain the following four sets of explicit exact solutions to (33) π 4 = ±β π π tanβ β π, π 2 ππ > 0, π 5 = ±β π π cotβ β π, π 2 ππ > 0, π π π 6 = ±β β tanh β π, π 2 π 7 = ±β β π π coth β π, π 2 While π < 0, the above equation possesses a Weierstrass elliptic function doubly periodic wave type solution: ππ < 0, Combining (7), (22), (23), (40), π = π 2 , π(π₯, π‘) = πΆ, and π = π(π), we derive that (1) admits a Weierstrass elliptic function doubly periodic wave type solution: π’8 (π₯, π‘) = ±πΆβ β (± π 9 = ±β π 10 = ±β Combining (7), (22), (23), (36), and π(π₯, π‘) = πΆ, π = π(π), we can get the following four explicit exact solutions of (1): π’5 (π₯, π‘) = ±πΆβ π π cotββ 3 π, 8π 2π ππ > 0, ππ < 0, π π coth β 3 π, 8π 2π ππ < 0, π’7 (π₯, π‘) = ±πΆββ π 11 = ±β β π π = ±ββ π 4 β π. 2 (38) πσΈ = ±ββ π 13 = ±β π 3 π β ππ. 2 (39) 2 (π + 1) π π2 β 1 2π 2 (π + 1) π 1 β π2 β 1 β π sd π 2π 2 π= π 14 = ±β Let π = π 2 ; (38) becomes 2 β dn 2 + ππ π 2 (1 + π) β = ±β β nd 2 + ππ π π=β (c) For πΈ = π = 0, from (33) we have π2 β 1 2π 1 + π βπ β π nc π π 2 π= π 12 where π = π(π₯ β β« π(π‘)ππ‘) + π(β« π(π‘)ππ‘ + πΆ1 ) + π0 , πΆ, πΆ1 are arbitrary parameters, and π0 is an arbitrary constant. σΈ π=β (37) π π π’6 (π₯, π‘) = ±πΆββ tanh β 3 π, 8π 2π (41) 1 β π β1 β π cn π π 2 ππ < 0. ππ > 0, 1 π, βππ2 , 0) , ππ where π = π(π₯ββ« π(π‘)ππ‘), πΆ, πΆ1 are arbitrary parameters, and π0 is an arbitrary constant. π= π π tanββ 3 π, 8π 2π (40) (d) For πΈ = 0, π =ΜΈ 0, we obtain elliptic function solutions for (33) as follows: (36) π’4 (π₯, π‘) = ±πΆβ π 8π π, β , 0) . 8 π π2 β 1 2π 2 (1 + π) β sc π + 2π π π=β 2 (π + 1) . π (42) Abstract and Applied Analysis 5 Combining (7), (22), (23), the above result (42), and π(π₯, π‘) = πΆ, π = π(π), we can get the following six Jacobi elliptic doubly periodic wave solutions of (1): π’9 (π₯, π‘) = ±β 3 sides of (30) to (32), we can obtain an overdetermined system of nonlinear algebraic equations: 2π΄ 2 = π΅1 3 π β π βπ β π π cn 8π 2π3 π΄ 1 = π΅0 4πΆ4 β 2π = π΄ 2 π΅1 π3 β π6 π= 16π4 3πΆ3 = π΄ 1 π΅1 + π΄ 2 π΅0 2π3 + π π π’10 (π₯, π‘) = ± dnβ π 2 π3 2πΆ2 β 2π = π΄ 1 π΅0 + π΄ 0 π΅1 π + π3 π=β 4π βππ΄ 2 = π΅1 πΆ4 π’11 (π₯, π‘) = ±β β 3 πΆ1 = π΄ 2 π΅0 β 2πΈ βππ΄ 1 = π΅1 πΆ3 + πΆ4 π΅0 3 π + π βπ β π π nc 8π 2π3 π2 β π6 π= 16π4 βππ΄ 0 β ππ΄ 2 = π΅1 πΆ2 + π΅0 πΆ3 πΈπ΄ 2 β ππ΄ 1 = π΅1 πΆ1 + π΅0 πΆ2 πΈπ΄ 1 β ππ΄ 2 = π΅1 πΆ0 + π΅0 πΆ1 (43) π3 + π β 2π3 + π π’12 (π₯, π‘) = ±β β π nd 4π π3 π=β π3 + π 4π π2 β π6 16π4 3 By analyzing all kinds of possibilities, we have the following. (b) While π΅0 =ΜΈ 0, πΆ0 = 0, it also leads to a contradiction. (c) While π΅0 = 0, πΆ0 =ΜΈ 0, we can derive that π΄ 1 = πΆ1 = πΆ3 = 0, πΈ = 0, 3 π + π β π + 2π π’14 (π₯, π‘) = ±β sc π 4π3 π3 π=β πΈπ΄ 0 = π΅0 πΆ0 . (a) While π΅0 = πΆ0 = 0, it leads to a contradiction. π6 β π2 β π β π3 π’13 (π₯, π‘) = ±β sd π 16π4 2π3 π= (44) π + π3 , 4π3 πΆ2 = βπ, πΆ0 = β In this case, we assume that deg[πΌ(π )] = π1 , deg[π0 (π )] = π2 ; then we have deg[π1 (π )] = π1 + 1. Now, by balancing the degrees of both sides of (32), we can deduce that π2 = 4. By balancing the degrees of both sides of (31), we can also conclude that π1 = 1 or π1 = 0. If π1 = 0, assuming that πΌ(π ) = π΄ 0 , π1 (π ) = π΄ 1 π + π΄ 2 , π0 (π ) = πΆ4 π 4 + πΆ3 π 3 + πΆ2 π 2 + πΆ1 π + πΆ0 and substituting them into (30)β(32), by equating the coefficients of the different powers of π on both sides of (30) to (32), we can get that πΌ(π ) = π1 (π ) = 0. This is contradicting with our assumption. It indicates that π1 =ΜΈ 0. While π1 = 1, assuming that π0 (π ) = πΆ4 π 4 + πΆ3 π 3 + πΆ2 π 2 + πΆ1 π + πΆ0 , π1 = π΄ 2 π 2 + π΄ 1 π + π΄ 0 , πΌ(π) = π΅1 π + π΅0 , then substituting these representations into (30)β(32), and by equating the coefficients of the different powers of π on both π΄22 = β2π, π , 2 π΄0 = π π΄ . π 2 (45) Setting (45) in (27) yields where π = π(π₯ β β« π(π‘)ππ‘) + π(β« π(π‘)ππ‘ + πΆ1 ) + π0 , πΆ, πΆ1 are arbitrary parameters, and π0 is an arbitrary constant. (2) In the case of deg[π1 (π )] β 1 = deg[πΌ(π )]. π2 , 2π πΆ4 = β π 2 ββ2π ππ =± ππ. + (π/π) 2 (46) Solving (46), we can obtain solutions π 4 , π 5 , π 6 , and π 7 again. Consequently, we obtain explicit exact solutions π’4 , π’5 , π’6 , and π’7 to (1). Here we will not list them one by one. We obtain various of explicit and exact solutions of (1) by using the extended hyperbolic functions method presented in [26] by author. we can get the following explicit exact solutions to (1): π 15 = ±β β 2 π sinh (π) + π cosh (π) , π π cosh (π) + π sinh (π) (47) when π = 2, where π, π, and π are arbitrary constants π 16 = ±β 2 (π2 β π2 ) π 1 , π cosh (π) + π sinh (π) (48) 6 Abstract and Applied Analysis when π = β1, where π, π, and π are arbitrary constants such that (π2 β π2 ) π > 0 π 17 = ± β 1 π2 β π2 β π2 2π π cosh (π) + π sinh (π) ± ββ (49) 1 π sinh (π) + π cosh (π) , 2π π cosh (π) + π sinh (π) + π π 18 (50) (51) when π = 1, where π, π, and π are arbitrary constants π 20 = ±β β 2 π cosh (π) β π sinh (π) , π π cosh (π) + π sinh (π) (52) when π = β2, where π, π, and π are arbitrary constants. Combining (7), (22), (23), the above result (47)β(52), and π(π₯, π‘) = πΆ, π = π(π), the VC-mKdV equation (1) has explicit and exact solitary wave solutions: π’15 (π₯, π‘) = ± ππ (π sinh (π) + π cosh (π)) , 2 (π cosh (π) + π sinh (π)) (53) where π, π, π, and π are arbitrary constants such that π = 2π3 , π = π(π₯ β β« π(π‘)ππ‘) + π(β« π(π‘)ππ‘ + πΆ1 ) + π0 π’16 (π₯, π‘) = ± 1 πβπ2 β π2 , 2 π cosh (π) + π sinh (π) (54) where π, π, π, and π are arbitrary constants such that π = βπ3 , π = π (π₯ β β« π(π‘)ππ‘) + π (β« π(π‘)ππ‘ + πΆ1 ) + π0 π’17 (π₯, π‘) = ± 1 πβπ2 β π2 β π2 4 π cosh (π) + π sinh (π) 1 π sinh (π) + π cosh (π) ± ββ , 2π π cosh (π) + π sinh (π) + π (55) where π, π, π, and π are arbitrary constants such that 2π = π3 , π = π (π₯ β β« π(π‘)ππ‘) + π (β« π(π‘)ππ‘ + πΆ1 ) + π0 π’18 (π₯, π‘) = ± πβπ2 β π2 β π2 2 (π cosh (π) + π sinh (π)) 1 π cosh (π) β π sinh (π) , ± ββ 2π π cosh (π) + π sinh (π) + π π 1 , π cosh (π) + π sinh (π) (57) ππ (π cosh (π) β π sinh (π)) , 2 (π cosh (π) + π sinh (π)) (58) where π, π, π, and π are arbitrary constants such that π = β2π3 , π = π (π₯ β β« π(π‘)ππ‘) + π (β« π(π‘)ππ‘ + πΆ1 ) + π0 . 5. Summary and Conclusions when π = β1/2, where π, π, and π are arbitrary constants π 19 2 (π2 + π2 ) π’20 (π₯, π‘) = ± 1 π cosh (π) β π sinh (π) ± ββ , 2π π cosh (π) + π sinh (π) + π 2 (π2 + π2 ) 1 = ±β β , π π cosh (π) + π sinh (π) π’19 (π₯, π‘) = ±β β where π, π, π, and π are arbitrary constants such that π = π3 , π = π (π₯ β β« π(π‘)ππ‘) + π (β« π(π‘)ππ‘ + πΆ1 ) + π0 when π = 1/2, where π, π, and π are arbitrary constants 1 π2 β π2 β π2 =±β 2π π cosh (π) + π sinh (π) where π, π, π, and π are arbitrary constants such that β2π = π3 , π = π (π₯ β β« π(π‘)ππ‘) + π (β« π(π‘)ππ‘ + πΆ1 ) + π0 (56) In summary, motivated by [27], we establish a transform from VC-mKdV equation to the constant coefficient mKdV equation firstly. Then we employ the first integral method and the extended hyperbolic function method to uniformly construct a series of explicit exact solutions for VC-mKdV equations. Abundant explicit exact solutions to VC-mKdV equations are obtained through an exhaustive analysis and discussion for different parameters. The exact solutions obtained in this paper include that of the solitary wave solutions of kink-type, singular traveling wave solutions, periodic wave solutions of triangle functions, Jacobi elliptic function doubly periodic solutions, Weierstrass elliptic function doubly periodic wave solutions, and so forth. In particular, the six explicit exact Jacobi elliptic function doubly periodic solutions π 9 βπ 14 and Weierstrass elliptic function doubly periodic wave solution π 8 are uniformly obtained. Some known results of previous references are enriched greatly. The results indicate that the first integral method and extended hyperbolic function method are very effective methods to solve nonlinear differential equation. The methods also are readily applicable to a large variety of other nonlinear evolution equations in physical mathematics. Acknowledgments This work is supported by the NSF of China (40890150, 40890153), the Science and Technology Program (2008B080701042) of Guangdong Province, and the Natural Science foundation of Guangdong Province (S2012010010121). The authors would like to thank Professor Feng Zhaosheng for his helpful suggestions. References [1] R. Hirota, βExact solution of the modified Korteweg-de Vries equation for multiple collisions of solitons,β Journal of the Physical Society of Japan, vol. 33, no. 5, pp. 364β374, 1972. [2] K. R. Helfrich, W. K. Melville, and J. W. Miles, βOn interfacial solitary waves over slowly varying topography,β Journal of Fluid Mechanics, vol. 149, pp. 305β317, 1984. Abstract and Applied Analysis [3] H. Ono, βSoliton fission in anharmonic lattices with reflectionless inhomogeneity,β Journal of the Physical Society of Japan, vol. 61, no. 12, pp. 4336β4343, 1992. [4] A. H. Khater, O. H. El-Kalaawy, and D. K. 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