Lesson 11: Angle Problems and Solving Equations

Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7โ€ข3
Lesson 11: Angle Problems and Solving Equations
Student Outcomes
๏‚ง
Students use vertical angles, adjacent angles, angles on a line, and angles at a point in a multi-step problem to
write and solve simple equations for an unknown angle in a figure.
Lesson Notes
Lesson 11 continues where Lesson 10 ended and incorporates slightly more difficult problems. At the heart of each
problem is the need to model the angle relationships in an equation and then solve for the unknown angle. The
diagrams are all drawn to scale; students should verify their answers by using a protractor to measure relevant angles.
Classwork
Opening Exercise (8 minutes)
Students describe the angle relationship in the diagram and set up and solve an equation that models it. Have students
verify their answers by measuring the unknown angle with a protractor.
Note to Teacher:
You may choose or offer a
choice of difficulty to students
in the Opening Exercise.
Opening Exercise
a.
In a complete sentence, describe the angle relationship in the diagram. Write an
equation for the angle relationship shown in the figure and solve for ๐’™. Confirm your
answers by measuring the angle with a protractor.
The angles marked by ๐’™°, ๐Ÿ—๐ŸŽ°, and ๐Ÿ๐Ÿ’° are angles on a line
and have a sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
14°
x°
๐’™ + ๐Ÿ—๐ŸŽ + ๐Ÿ๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ
๐’™ + ๐Ÿ๐ŸŽ๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ
๐’™ + ๐Ÿ๐ŸŽ๐Ÿ’ โˆ’ ๐Ÿ๐ŸŽ๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐ŸŽ๐Ÿ’
๐’™ = ๐Ÿ•๐Ÿ”
b.
โƒก๐‘ช๐‘ซ and โƒก๐‘ฌ๐‘ญ are intersecting lines. In a complete sentence, describe the angle relationship in the diagram.
Write an equation for the angle relationship shown in the figure and solve for ๐’š. Confirm your answers by
measuring the angle with a protractor.
F
The adjacent angles marked by ๐’š° and ๐Ÿ“๐Ÿ° together form the
angle that is vertically opposite and equal to the angle
measuring ๐Ÿ๐Ÿ’๐Ÿ•°.
147°
C
D
๐’š + ๐Ÿ“๐Ÿ = ๐Ÿ๐Ÿ’๐Ÿ•
51°
๐’š + ๐Ÿ“๐Ÿ โˆ’ ๐Ÿ“๐Ÿ = ๐Ÿ๐Ÿ’๐Ÿ• โˆ’ ๐Ÿ“๐Ÿ
๐’š = ๐Ÿ—๐Ÿ”
Lesson 11:
y°
E
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
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This work is licensed under a
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Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
c.
7โ€ข3
In a complete sentence, describe the angle relationship in the diagram. Write an equation for the angle
relationship shown in the figure and solve for ๐’ƒ. Confirm your answers by measuring the angle with a
protractor.
The adjacent angles marked by ๐Ÿ“๐Ÿ—°, ๐Ÿ’๐Ÿ°, ๐’ƒ°, ๐Ÿ”๐Ÿ“°, and
๐Ÿ—๐ŸŽ° are angles at a point and together have a sum of
๐Ÿ‘๐Ÿ”๐ŸŽ°.
๐Ÿ“๐Ÿ— + ๐Ÿ’๐Ÿ + ๐’ƒ + ๐Ÿ”๐Ÿ“ + ๐Ÿ—๐ŸŽ = ๐Ÿ‘๐Ÿ”๐ŸŽ
59°
๐’ƒ + ๐Ÿ๐Ÿ“๐Ÿ“ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ“
65°
๐’ƒ = ๐Ÿ๐ŸŽ๐Ÿ“
41°
b°
d.
The following figure shows three lines intersecting at a point. In a complete sentence, describe the angle
relationship in the diagram. Write an equation for the angle relationship shown in the figure and solve for ๐’›.
Confirm your answers by measuring the angle with a protractor.
The angles marked by ๐’›°, ๐Ÿ๐Ÿ“๐Ÿ–°, and ๐’›° are angles on a line
and have a sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
๐’› + ๐Ÿ๐Ÿ“๐Ÿ– + ๐’› = ๐Ÿ๐Ÿ–๐ŸŽ
z°
๐Ÿ๐’› + ๐Ÿ๐Ÿ“๐Ÿ– = ๐Ÿ๐Ÿ–๐ŸŽ
158°
z°
๐Ÿ๐’› + ๐Ÿ๐Ÿ“๐Ÿ– โˆ’ ๐Ÿ๐Ÿ“๐Ÿ– = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ–
๐Ÿ๐’› = ๐Ÿ๐Ÿ
๐’› = ๐Ÿ๐Ÿ
e.
Write an equation for the angle relationship shown in the figure and solve for ๐’™. In a complete sentence,
describe the angle relationship in the diagram. Find the measurements of โˆ ๐‘ฌ๐‘ท๐‘ฉ and โˆ ๐‘ช๐‘ท๐‘จ. Confirm your
answers by measuring the angle with a protractor.
โˆ ๐‘ช๐‘ท๐‘จ, โˆ ๐‘ช๐‘ท๐‘ฌ, and โˆ ๐‘ฌ๐‘ท๐‘ฉ are angles on a line and their measures have a
sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
๐Ÿ“๐’™ + ๐Ÿ—๐ŸŽ + ๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ”๐’™ + ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ”๐’™ + ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ
๐Ÿ”๐’™ = ๐Ÿ—๐ŸŽ
๐Ÿ
๐Ÿ
( ) ๐Ÿ”๐’™ = ( ) ๐Ÿ—๐ŸŽ
๐Ÿ”
๐Ÿ”
๐’™ = ๐Ÿ๐Ÿ“
โˆ ๐‘ฌ๐‘ท๐‘ฉ = ๐Ÿ๐Ÿ“°
โˆ ๐‘ช๐‘ท๐‘จ = ๐Ÿ“(๐Ÿ๐Ÿ“°) = ๐Ÿ•๐Ÿ“°
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
163
This work is licensed under a
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Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7โ€ข3
Example 1 (4 minutes)
Example 1
The following figure shows three lines intersecting at a point. In a complete sentence, describe the angle relationship in
the diagram. Write an equation for the angle relationship shown in the figure and solve for ๐’™. Confirm your answers by
measuring the angle with a protractor.
The angles ๐Ÿ–๐Ÿ”°, ๐Ÿ”๐Ÿ–°, and the angle between them, which is vertically opposite and
equal in measure to ๐’™, are angles on a line and have a sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
๐Ÿ–๐Ÿ” + ๐’™ + ๐Ÿ”๐Ÿ– = ๐Ÿ๐Ÿ–๐ŸŽ
68°
86°
๐’™ + ๐Ÿ๐Ÿ“๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ
๐’™ + ๐Ÿ๐Ÿ“๐Ÿ’ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ’
x°
๐’™ = ๐Ÿ๐Ÿ”
Exercise 1 (5 minutes)
Exercise 1
The following figure shows four lines intersecting at a point. In a complete sentence, describe the angle relationships in
the diagram. Write an equation for the angle relationship shown in the figure and solve for ๐’™ and ๐’š. Confirm your
answers by measuring the angle with a protractor.
The angles ๐’™°, ๐Ÿ๐Ÿ“°, ๐’š°, and ๐Ÿ’๐ŸŽ° are angles on a line and have a
sum of ๐Ÿ๐Ÿ–๐ŸŽ°; the angle marked ๐’š° is vertically opposite and equal
to ๐Ÿ—๐Ÿ”°.
25°
๐’š = ๐Ÿ—๐Ÿ”, vert. โˆ s
x°
๐’™ + ๐Ÿ๐Ÿ“ + (๐Ÿ—๐Ÿ”) + ๐Ÿ’๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ
๐’™ + ๐Ÿ๐Ÿ”๐Ÿ = ๐Ÿ๐Ÿ–๐ŸŽ
๐’™ + ๐Ÿ๐Ÿ”๐Ÿ โˆ’ ๐Ÿ๐Ÿ”๐Ÿ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ”๐Ÿ
y°
40°
96°
๐’™ = ๐Ÿ๐Ÿ—
Example 2 (4 minutes)
Example 2
In a complete sentence, describe the angle relationships in the diagram. You may label the diagram to help describe the
angle relationships. Write an equation for the angle relationship shown in the figure and solve for ๐’™. Confirm your
answers by measuring the angle with a protractor.
The angle formed by adjacent angles ๐’‚° and ๐’ƒ° is vertically opposite to the
๐Ÿ•๐Ÿ•° angle. The angles ๐’™°, ๐’‚°, and ๐’ƒ° are adjacent angles that have a sum
of ๐Ÿ—๐ŸŽ° (since the adjacent angle is a right angle and together the angles
are on a line).
๐’ƒหš
๐’‚หš
๐’™ + ๐Ÿ•๐Ÿ• = ๐Ÿ—๐ŸŽ
๐’™ + ๐Ÿ•๐Ÿ• โˆ’ ๐Ÿ•๐Ÿ• = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ•๐Ÿ•
๐’™ = ๐Ÿ๐Ÿ‘
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
164
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7โ€ข3
Exercise 2 (4 minutes)
Exercise 2
In a complete sentence, describe the angle relationships in the diagram. Write an equation for the angle relationship
shown in the figure and solve for ๐’™ and ๐’š. Confirm your answers by measuring the angles with a protractor.
The measures of angles ๐’™ and ๐’š have a sum of ๐Ÿ—๐ŸŽ°; the measures of angles ๐’™ and
๐Ÿ๐Ÿ• have a sum of ๐Ÿ—๐ŸŽ°.
๐’™ + ๐Ÿ๐Ÿ• = ๐Ÿ—๐ŸŽ
๐’™ + ๐Ÿ๐Ÿ• โˆ’ ๐Ÿ๐Ÿ• = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐Ÿ•
๐’™ = ๐Ÿ”๐Ÿ‘
27°
x°
(๐Ÿ”๐Ÿ‘) + ๐’š = ๐Ÿ—๐ŸŽ
๐Ÿ”๐Ÿ‘ โˆ’ ๐Ÿ”๐Ÿ‘ + ๐’š = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ”๐Ÿ‘
๐’š = ๐Ÿ๐Ÿ•
y°
Example 3 (5 minutes)
Example 3
In a complete sentence, describe the angle relationships in the diagram. Write an equation for the angle relationship
shown in the figure and solve for ๐’™. Find the measures of โˆ ๐‘ฑ๐‘จ๐‘ฏ and โˆ ๐‘ฎ๐‘จ๐‘ญ. Confirm your answers by measuring the
angle with a protractor.
The sum of the degree measurements of โˆ ๐‘ฑ๐‘จ๐‘ฏ, โˆ ๐‘ฎ๐‘จ๐‘ฏ, โˆ ๐‘ฎ๐‘จ๐‘ญ, and the arc
that subtends โˆ ๐‘ฑ๐‘จ๐‘ญ is ๐Ÿ‘๐Ÿ”๐ŸŽ°.
๐Ÿ๐Ÿ๐Ÿ“ + ๐Ÿ๐’™ + ๐Ÿ—๐ŸŽ + ๐Ÿ‘๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ‘๐Ÿ๐Ÿ“ + ๐Ÿ“๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ‘๐Ÿ๐Ÿ“ โˆ’ ๐Ÿ‘๐Ÿ๐Ÿ“ + ๐Ÿ“๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ‘๐Ÿ๐Ÿ“
๐Ÿ“๐’™ = ๐Ÿ’๐Ÿ“
๐Ÿ
๐Ÿ
( ) ๐Ÿ“๐’™ = ( ) ๐Ÿ’๐Ÿ“
๐Ÿ“
๐Ÿ“
๐’™=๐Ÿ—
๐’Žโˆ ๐‘ฑ๐‘จ๐‘ฏ = ๐Ÿ(๐Ÿ—°) = ๐Ÿ๐Ÿ–°
H
J
2x°
G
3x°
225° A
F
๐’Žโˆ ๐‘ฎ๐‘จ๐‘ญ = ๐Ÿ‘(๐Ÿ—°) = ๐Ÿ๐Ÿ•°
Exercise 3 (4 minutes)
Exercise 3
In a complete sentence, describe the angle relationships in the diagram. Write an equation for the angle relationship
shown in the figure and solve for ๐’™. Find the measure of โˆ ๐‘ฑ๐‘ฒ๐‘ฎ. Confirm your answer by measuring the angle with a
protractor.
The sum of the degree measurements of โˆ ๐‘ณ๐‘ฒ๐‘ฑ, โˆ ๐‘ฑ๐‘ฒ๐‘ฎ, โˆ ๐‘ฎ๐‘ฒ๐‘ด, and the arc that subtends
โˆ ๐‘ณ๐‘ฒ๐‘ด is ๐Ÿ‘๐Ÿ”๐ŸŽ°.
๐Ÿ“๐’™ + ๐Ÿ๐Ÿ’ + ๐’™ + ๐Ÿ—๐ŸŽ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ”๐’™ + ๐Ÿ๐Ÿ๐Ÿ’ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ”๐’™ + ๐Ÿ๐Ÿ๐Ÿ’ โˆ’ ๐Ÿ๐Ÿ๐Ÿ’ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ๐Ÿ๐Ÿ’
๐Ÿ”๐’™ = ๐Ÿ๐Ÿ’๐Ÿ”
๐Ÿ
๐Ÿ
( ) ๐Ÿ”๐’™ = ( ) ๐Ÿ๐Ÿ’๐Ÿ”
๐Ÿ”
๐Ÿ”
๐’™ = ๐Ÿ’๐Ÿ
J
L
G
24°
x°
5x° K
M
๐’Žโˆ ๐‘ฑ๐‘ฒ๐‘ฎ = ๐Ÿ’๐Ÿ°
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
165
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7โ€ข3
Example 4 (5 minutes)
Example 4
In the accompanying diagram, the measure of โˆ ๐‘ซ๐‘ฉ๐‘ฌ is four times the
measure of โˆ ๐‘ญ๐‘ฉ๐‘ฎ.
a.
Label โˆ ๐‘ซ๐‘ฉ๐‘ฌ as ๐’š° and โˆ ๐‘ญ๐‘ฉ๐‘ฎ as ๐’™°. Write an equation that
describes the relationship between โˆ ๐‘ซ๐‘ฉ๐‘ฌ and โˆ ๐‘ญ๐‘ฉ๐‘ฎ.
A
C
F
x°
๐’š = ๐Ÿ’๐’™
B
50°
y°
D
G
b.
Find the value of ๐’™.
E
๐Ÿ“๐ŸŽ + ๐’™ + ๐Ÿ’๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ“๐ŸŽ + ๐Ÿ“๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ“๐’™ + ๐Ÿ“๐ŸŽ โˆ’ ๐Ÿ“๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ“๐ŸŽ
๐Ÿ“๐’™ = ๐Ÿ๐Ÿ‘๐ŸŽ
๐Ÿ
๐Ÿ
( ) (๐Ÿ“๐’™) = ( ) (๐Ÿ๐Ÿ‘๐ŸŽ)
๐Ÿ“
๐Ÿ“
๐’™ = ๐Ÿ๐Ÿ”
c.
Find the measures of โˆ ๐‘ญ๐‘ฉ๐‘ฎ, โˆ ๐‘ช๐‘ฉ๐‘ซ, โˆ ๐‘จ๐‘ฉ๐‘ญ, โˆ ๐‘ฎ๐‘ฉ๐‘ฌ, and โˆ ๐‘ซ๐‘ฉ๐‘ฌ.
๐’Žโˆ ๐‘ญ๐‘ฉ๐‘ฎ = ๐Ÿ๐Ÿ”°
๐’Žโˆ ๐‘ช๐‘ฉ๐‘ซ = ๐Ÿ๐Ÿ”°
๐’Žโˆ ๐‘จ๐‘ฉ๐‘ญ = ๐Ÿ’(๐Ÿ๐Ÿ”°) = ๐Ÿ๐ŸŽ๐Ÿ’°
๐’Žโˆ ๐‘ฎ๐‘ฉ๐‘ฌ = ๐Ÿ“๐ŸŽ°
๐’Žโˆ ๐‘ซ๐‘ฉ๐‘ฌ = ๐Ÿ๐ŸŽ๐Ÿ’°
d.
What is the measure of โˆ ๐‘จ๐‘ฉ๐‘ฎ? Identify the angle relationship used to get your answer.
โˆ ๐‘จ๐‘ฉ๐‘ฎ = โˆ ๐‘จ๐‘ฉ๐‘ญ + โˆ ๐‘ญ๐‘ฉ๐‘ฎ
โˆ ๐‘จ๐‘ฉ๐‘ฎ = ๐Ÿ๐ŸŽ๐Ÿ’ + ๐Ÿ๐Ÿ”
โˆ ๐‘จ๐‘ฉ๐‘ฎ = ๐Ÿ๐Ÿ‘๐ŸŽ
๐’Žโˆ ๐‘จ๐‘ฉ๐‘ฎ = ๐Ÿ๐Ÿ‘๐ŸŽ°
To determine the measure of โˆ ๐‘จ๐‘ฉ๐‘ฎ, you need to add the measures of adjacent angles โˆ ๐‘จ๐‘ฉ๐‘ญ and โˆ ๐‘ญ๐‘ฉ๐‘ฎ.
Exit Ticket (6 minutes)
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
166
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
Name ___________________________________________________
7โ€ข3
Date____________________
Lesson 11: Angle Problems and Solving Equations
Exit Ticket
Write an equation for the angle relationship shown in the figure and solve for ๐‘ฅ. Find the measures of โˆ ๐‘…๐‘„๐‘† and โˆ ๐‘‡๐‘„๐‘ˆ.
221°
Q
R
3x°
S
4x°
U
T
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
167
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7โ€ข3
Exit Ticket Sample Solutions
Write an equation for the angle relationship shown in the figure and solve for ๐’™. Find the measures of โˆ ๐‘น๐‘ธ๐‘บ and โˆ ๐‘ป๐‘ธ๐‘ผ.
๐Ÿ‘๐’™ + ๐Ÿ—๐ŸŽ + ๐Ÿ’๐’™ + ๐Ÿ๐Ÿ๐Ÿ = ๐Ÿ‘๐Ÿ”๐ŸŽ
221°
Q
R
๐Ÿ•๐’™ + ๐Ÿ‘๐Ÿ๐Ÿ = ๐Ÿ‘๐Ÿ”๐ŸŽ
3x°
๐Ÿ•๐’™ + ๐Ÿ‘๐Ÿ๐Ÿ โˆ’ ๐Ÿ‘๐Ÿ๐Ÿ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ‘๐Ÿ๐Ÿ
๐Ÿ•๐’™ = ๐Ÿ’๐Ÿ—
๐Ÿ
๐Ÿ
( ) ๐Ÿ•๐’™ = ( ) ๐Ÿ’๐Ÿ—
๐Ÿ•
๐Ÿ•
๐’™=๐Ÿ•
4x°
S
U
T
๐’Žโˆ ๐‘น๐‘ธ๐‘บ = ๐Ÿ‘(๐Ÿ•°) = ๐Ÿ๐Ÿ°
๐’Žโˆ ๐‘ป๐‘ธ๐‘ผ = ๐Ÿ’(๐Ÿ•°) = ๐Ÿ๐Ÿ–°
Problem Set Sample Solutions
In a complete sentence, describe the angle relationships in each diagram. Write an equation for the angle relationship(s)
shown in the figure, and solve for the indicated unknown angle. You can check your answers by measuring each angle
with a protractor.
1.
Find the measures of โˆ ๐‘ฌ๐‘จ๐‘ญ, โˆ ๐‘ซ๐‘จ๐‘ฌ, and โˆ ๐‘ช๐‘จ๐‘ซ.
โˆ ๐‘ฎ๐‘จ๐‘ญ, โˆ ๐‘ฌ๐‘จ๐‘ญ, โˆ ๐‘ซ๐‘จ๐‘ฌ, and โˆ ๐‘ช๐‘จ๐‘ซ are angles on a line and their measures have a sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
๐Ÿ”๐’™ + ๐Ÿ’๐’™ + ๐Ÿ๐’™ + ๐Ÿ‘๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ
D
๐Ÿ๐Ÿ๐’™ + ๐Ÿ‘๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ
E
๐Ÿ๐Ÿ๐’™ + ๐Ÿ‘๐ŸŽ โˆ’ ๐Ÿ‘๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ‘๐ŸŽ
๐Ÿ๐Ÿ๐’™ = ๐Ÿ๐Ÿ“๐ŸŽ
4x°
๐’™ = ๐Ÿ๐Ÿ. ๐Ÿ“
6x°
30°
๐’Žโˆ ๐‘ฌ๐‘จ๐‘ญ = ๐Ÿ(๐Ÿ๐Ÿ. ๐Ÿ“°) = ๐Ÿ๐Ÿ“°
๐’Žโˆ ๐‘ซ๐‘จ๐‘ฌ = ๐Ÿ’(๐Ÿ๐Ÿ. ๐Ÿ“°) = ๐Ÿ“๐ŸŽ°
C
F
2x°
A
G
๐’Žโˆ ๐‘ช๐‘จ๐‘ซ = ๐Ÿ”(๐Ÿ๐Ÿ. ๐Ÿ“°) = ๐Ÿ•๐Ÿ“°
2.
Find the measure of ๐’‚.
Angles ๐’‚°, ๐Ÿ๐Ÿ”°, ๐’‚°, and ๐Ÿ๐Ÿ๐Ÿ”° are angles at a point and have a sum of
๐Ÿ‘๐Ÿ”๐ŸŽ°.
๐’‚ + ๐Ÿ๐Ÿ๐Ÿ” + ๐’‚ + ๐Ÿ๐Ÿ” = ๐Ÿ‘๐Ÿ”๐ŸŽ
126°
๐Ÿ๐’‚ + ๐Ÿ๐Ÿ“๐Ÿ = ๐Ÿ‘๐Ÿ”๐ŸŽ
a°
๐Ÿ๐’‚ + ๐Ÿ๐Ÿ“๐Ÿ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ๐Ÿ“๐Ÿ
๐Ÿ๐’‚ = ๐Ÿ๐ŸŽ๐Ÿ–
๐Ÿ
๐Ÿ
( ) ๐Ÿ๐’‚ = ( ) ๐Ÿ๐ŸŽ๐Ÿ–
๐Ÿ
๐Ÿ
๐’‚ = ๐Ÿ๐ŸŽ๐Ÿ’
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
a°
26°
168
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
3.
7โ€ข3
Find the measures of ๐’™ and ๐’š.
Angles ๐’š° and ๐Ÿ”๐Ÿ“° and angles ๐Ÿ๐Ÿ“° and ๐’™° have a sum of ๐Ÿ—๐ŸŽ°.
๐’™ + ๐Ÿ๐Ÿ“ = ๐Ÿ—๐ŸŽ
๐’™ + ๐Ÿ๐Ÿ“ โˆ’ ๐Ÿ๐Ÿ“ = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐Ÿ“
x°
๐’™ = ๐Ÿ”๐Ÿ“
25°
65°
๐Ÿ”๐Ÿ“ + ๐’š = ๐Ÿ—๐ŸŽ
y°
๐Ÿ”๐Ÿ“ + ๐’š = ๐Ÿ—๐ŸŽ
๐Ÿ”๐Ÿ“ โˆ’ ๐Ÿ”๐Ÿ“ + ๐’š = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ”๐Ÿ“
๐’š = ๐Ÿ๐Ÿ“
4.
H
Find the measure of โˆ ๐‘ฏ๐‘จ๐‘ฑ.
Adjacent angles ๐’™° and ๐Ÿ๐Ÿ“° together are vertically opposite from and are
equal to angle ๐Ÿ–๐Ÿ°.
๐’™ + ๐Ÿ๐Ÿ“ = ๐Ÿ–๐Ÿ
E
๐’™ + ๐Ÿ๐Ÿ“ โˆ’ ๐Ÿ๐Ÿ“ = ๐Ÿ–๐Ÿ โˆ’ ๐Ÿ๐Ÿ“
J
x°
15°
A
81°
F
๐’™ = ๐Ÿ”๐Ÿ”
๐’Žโˆ ๐‘ฏ๐‘จ๐‘ฑ = ๐Ÿ”๐Ÿ”°
5.
G
Find the measures of โˆ ๐‘ฏ๐‘จ๐‘ฉ and โˆ ๐‘ช๐‘จ๐‘ฉ.
The measures of adjacent angles โˆ ๐‘ช๐‘จ๐‘ฉ and โˆ ๐‘ฏ๐‘จ๐‘ฉ have a sum of the
measure of โˆ ๐‘ช๐‘จ๐‘ฏ, which is vertically opposite from and equal to the
measurement of โˆ ๐‘ซ๐‘จ๐‘ฌ.
F
D
20°
๐Ÿ๐’™ + ๐Ÿ‘๐’™ + ๐Ÿ•๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ“๐’™ = ๐Ÿ๐Ÿ๐ŸŽ
๐Ÿ
๐Ÿ
( ) ๐Ÿ“๐’™ = ( ) ๐Ÿ๐Ÿ๐ŸŽ
๐Ÿ“
๐Ÿ“
๐’™ = ๐Ÿ๐Ÿ
A
E
H
3x°
2x°
C
B
๐’Žโˆ ๐‘ฏ๐‘จ๐‘ฉ = ๐Ÿ‘(๐Ÿ๐Ÿ°) = ๐Ÿ”๐Ÿ”°
๐’Žโˆ ๐‘ช๐‘จ๐‘ฉ = ๐Ÿ(๐Ÿ๐Ÿ°) = ๐Ÿ’๐Ÿ’°
6.
The measure of โˆ ๐‘บ๐‘ท๐‘ป is ๐’ƒ°. The measure of โˆ ๐‘ป๐‘ท๐‘น is five more than two times โˆ ๐‘บ๐‘ท๐‘ป. The measure of โˆ ๐‘ธ๐‘ท๐‘บ is
twelve less than eight times the measure of โˆ ๐‘บ๐‘ท๐‘ป. Find the measures of โˆ ๐‘บ๐‘ท๐‘ป, โˆ ๐‘ป๐‘ท๐‘น, and โˆ ๐‘ธ๐‘ท๐‘บ.
โˆ ๐‘ธ๐‘ท๐‘บ, โˆ ๐‘บ๐‘ท๐‘ป, and โˆ ๐‘ป๐‘ท๐‘น are angles on a line and their
measures have a sum of ๐Ÿ๐Ÿ–๐ŸŽ°.
S
(๐Ÿ–๐’ƒ โˆ’ ๐Ÿ๐Ÿ) + ๐’ƒ + (๐Ÿ๐’ƒ + ๐Ÿ“) = ๐Ÿ๐Ÿ–๐ŸŽ
b°
๐Ÿ๐Ÿ๐’ƒ โˆ’ ๐Ÿ• = ๐Ÿ๐Ÿ–๐ŸŽ
๐Ÿ๐Ÿ๐’ƒ โˆ’ ๐Ÿ• + ๐Ÿ• = ๐Ÿ๐Ÿ–๐ŸŽ + ๐Ÿ•
๐Ÿ๐Ÿ๐’ƒ = ๐Ÿ๐Ÿ–๐Ÿ•
๐Ÿ
๐Ÿ
( ) ๐Ÿ๐Ÿ๐’ƒ = ( ) ๐Ÿ๐Ÿ–๐Ÿ•
๐Ÿ๐Ÿ
๐Ÿ๐Ÿ
๐’ƒ = ๐Ÿ๐Ÿ•
(8bโˆ’12)°
Q
P
T
(2b+5)°
R
๐’Žโˆ ๐‘บ๐‘ท๐‘ป = (๐Ÿ๐Ÿ•°) = ๐Ÿ๐Ÿ•°
๐’Žโˆ ๐‘ป๐‘ท๐‘น = ๐Ÿ(๐Ÿ๐Ÿ•°) + ๐Ÿ“° = ๐Ÿ‘๐Ÿ—°
๐’Žโˆ ๐‘ธ๐‘ท๐‘บ = ๐Ÿ–(๐Ÿ๐Ÿ•°) โˆ’ ๐Ÿ๐Ÿ° = ๐Ÿ๐Ÿ๐Ÿ’°
Lesson 11:
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
169
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 11
NYS COMMON CORE MATHEMATICS CURRICULUM
7.
7โ€ข3
Find the measures of โˆ ๐‘ฏ๐‘ธ๐‘ฌ and โˆ ๐‘จ๐‘ธ๐‘ฎ.
โˆ ๐‘จ๐‘ธ๐‘ฎ, โˆ ๐‘จ๐‘ธ๐‘ฏ, and โˆ ๐‘ฏ๐‘ธ๐‘ฌ are adjacent angles whose measures have a
sum of ๐Ÿ—๐ŸŽ°.
E
๐Ÿ๐’š + ๐Ÿ๐Ÿ + ๐’š = ๐Ÿ—๐ŸŽ
H
C
2y°
๐Ÿ‘๐’š + ๐Ÿ๐Ÿ = ๐Ÿ—๐ŸŽ
21°
๐Ÿ‘๐’š + ๐Ÿ๐Ÿ โˆ’ ๐Ÿ๐Ÿ = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐Ÿ
A
๐Ÿ‘๐’š = ๐Ÿ”๐Ÿ—
๐Ÿ
๐Ÿ
( ) ๐Ÿ‘๐’š = ( ) ๐Ÿ”๐Ÿ—
๐Ÿ‘
๐Ÿ‘
๐’š = ๐Ÿ๐Ÿ‘
Q
B
y°
G
F
D
๐’Žโˆ ๐‘ฏ๐‘ธ๐‘ฌ = ๐Ÿ(๐Ÿ๐Ÿ‘°) = ๐Ÿ’๐Ÿ”°
๐’Žโˆ ๐‘จ๐‘ธ๐‘ฎ = (๐Ÿ๐Ÿ‘°) = ๐Ÿ๐Ÿ‘°
8.
The measures of three angles at a point are in the ratio of ๐Ÿ โˆถ ๐Ÿ‘ โˆถ ๐Ÿ“. Find the measures of the angles.
โˆ ๐‘จ = ๐Ÿ๐’™, โˆ ๐‘ฉ = ๐Ÿ‘๐’™, โˆ ๐‘ช = ๐Ÿ“๐’™
๐Ÿ๐’™ + ๐Ÿ‘๐’™ + ๐Ÿ“๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ๐ŸŽ๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ
๐Ÿ
( ) ๐Ÿ๐ŸŽ๐’™ = ( ) ๐Ÿ‘๐Ÿ”๐ŸŽ
๐Ÿ๐ŸŽ
๐Ÿ๐ŸŽ
๐’™ = ๐Ÿ‘๐Ÿ”
โˆ ๐‘จ = ๐Ÿ(๐Ÿ‘๐Ÿ”°) = ๐Ÿ•๐Ÿ°
โˆ ๐‘ฉ = ๐Ÿ‘(๐Ÿ‘๐Ÿ”°) = ๐Ÿ๐ŸŽ๐Ÿ–°
โˆ ๐‘ช = ๐Ÿ“(๐Ÿ‘๐Ÿ”°) = ๐Ÿ๐Ÿ–๐ŸŽ°
9.
The sum of the measures of two adjacent angles is ๐Ÿ•๐Ÿ°. The ratio of the smaller angle to the larger angle is ๐Ÿ โˆถ ๐Ÿ‘.
Find the measures of each angle.
โˆ ๐‘จ = ๐’™, โˆ ๐‘ฉ = ๐Ÿ‘๐’™
๐’™ + ๐Ÿ‘๐’™ = ๐Ÿ•๐Ÿ
๐Ÿ’๐’™ = ๐Ÿ•๐Ÿ
๐Ÿ
๐Ÿ
( ) (๐Ÿ’๐’™) = ( ) (๐Ÿ•๐Ÿ)
๐Ÿ’
๐Ÿ’
๐’™ = ๐Ÿ๐Ÿ–
โˆ ๐‘จ = (๐Ÿ๐Ÿ–°) = ๐Ÿ๐Ÿ–°
โˆ ๐‘ฉ = ๐Ÿ‘(๐Ÿ๐Ÿ–°) = ๐Ÿ“๐Ÿ’°
10. Find the measures of โˆ ๐‘ช๐‘ธ๐‘จ and โˆ ๐‘ฌ๐‘ธ๐‘ฉ.
B
E
๐Ÿ’๐’™ + ๐Ÿ“๐’™ = ๐Ÿ๐ŸŽ๐Ÿ–
4x°
๐Ÿ—๐’™ = ๐Ÿ๐ŸŽ๐Ÿ–
๐Ÿ
๐Ÿ
( ) ๐Ÿ—๐’™ = ( ) ๐Ÿ๐ŸŽ๐Ÿ–
๐Ÿ—
๐Ÿ—
๐’™ = ๐Ÿ๐Ÿ
F
18°
C
5x°
Q
D
๐’Žโˆ ๐‘ช๐‘ธ๐‘จ = ๐Ÿ“(๐Ÿ๐Ÿ°) = ๐Ÿ”๐ŸŽ°
๐’Žโˆ ๐‘ฌ๐‘ธ๐‘ฉ = ๐Ÿ’(๐Ÿ๐Ÿ°) = ๐Ÿ’๐Ÿ–°
Lesson 11:
A
Angle Problems and Solving Equations
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G7-M3-TE-1.3.0-08.2015
170
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.