3.4 Day 2 Factoring Polynomial Expressions.notebook 3-4 Day 2 Factoring Polynomial Expressions November 12, 2015 Steps for factoring: 1. Factor out GCF 2. What's left? I can... Factor polynomial expressions - Quadratic or Quartic? Factor normally - Are there 4 terms? Factor by grouping - Is it a sum or difference of perfect cubes? Jun 16-7:53 AM Factor by Grouping: 4 terms x3 – 2x2 – 9x + 18 Jun 16-7:53 AM Example 1: a) 8r3 - 64r2 + r - 8 Step 1: Group the first two terms and the second two terms together with a plus sign between them. (x3 – 2x2) + (– 9x + 18) Step 2: Factor out the GCF from each group. x2(x – 2) + -9(x - 2) b) 12x3 + 2x2 - 30x - 5 Notice, these are the same Step 3: Re group. Put GCF's in one group, and the "left-overs" in a second group. (x2 - 9)(x - 2) Jun 16-7:53 AM Sum of Cubes: adding 2 terms that are perfect cubes (ex: 8, 27, 64, 125, x3, 8x3, ...) Jun 16-7:53 AM How to use this formula: a3 + b3 = (a + b)(a2 – ab + b2) x3 + 8 You will use this formula to factor: Step 1: Break down both terms: a3 + b3 = (a + b)(a2 – ab + b2) (x)3 + (2)3 Step 2: Label the first term a and the second term b: (x)3 + (2)3 a Step 3: Plug into formula: b (a + b)(a – ab + b2) 2 (x + 2)((x)2 – (x)(2) + (2)2) Step 4: Simplify: (x + 2)(x2 – 2x + 4) Jun 16-7:53 AM Jun 16-7:53 AM 1 3.4 Day 2 Factoring Polynomial Expressions.notebook Example 2: Factor completely 27a3 + 125 November 12, 2015 Difference of Cubes: subtracting 2 terms that are perfect cubes (ex: 8, 27, 64, 125, x3, 8x3, ...) You will use this formula to factor: a3 - b3 = (a - b)(a2 + ab + b2) Almost exactly the same as the SUM of cubes, just different signs Jun 16-7:53 AM Example 3: Factor Completely a3 - b3 = (a - b)(a2 + ab + b2) 8x3 – 1 Jun 16-7:53 AM Example 4: Factor Completely a) 5x3 – 40 b) 2x3 + 128 Jun 16-7:53 AM Jun 16-7:53 AM DON'T FORGET: 1. Factor out GCF 2. What's left? - Quadratic or Quartic? Factor normally - Are there 4 terms? Factor by grouping - Is it a sum or difference of perfect cubes? Jun 16-7:53 AM 2
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