Years IIT-JEE CHAPTERWISE SOLVED PAPERS MATHEMATICS Information contained in this work has been obtained by Career Point from sources believed to be reliable. However, neither Career Point nor its authors guarantee the accuracy or completeness of any information published herein, and neither Career Point nor its authors shall be responsible for any errors, omissions, or damages arising out of use of this information. This work is published with the understanding that Career Point and its authors are supplying information but are not attempting to render any professional services. If such services are required, the assistance of an appropriate professional should be sought. CAREER POINT CP Tower, Road No.-1, IPIA, Kota (Raj.) Email : [email protected] Copyright © 2016, by Career Point Ltd. No part of this publication may be reproduced or distributed in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise or stored in a database or retrieval system without the prior written permission of the Publishers. The program listings (if any) may be entered, stored and executed in a computer system, but they may not be reproduced for publication. This edition can be exported from India only by the publisher. Published by Career Point Ltd. CP Tower, Road No.-1, IPIA, Kota (Raj.) Email : [email protected] Preface Whenever a student decides to prepare for any examination, her/his first and foremost curiosity about the type of questions that he/she has to face. This becomes more important in the context of competitive examinations where there is neck-to-neck race. We feel great pleasure to present before you this book. We have made an attempt to provide chapter wise questions asked in IIT-JEE / JEE Advanced from 1978 to 2016 along with solutions. Solutions to the questions are not just sketch rather have been written in such a manner that the students will be able to under the application of concept and can answer some other related questions too. We firmly believe that the book in this form will definitely help a genuine, hardworking student. We have tried our best to keep errors out of this book. Comment and criticism from readers will be highly appreciated and incorporated in the subsequent edition. We wish to utilize the opportunity to place on record our special thanks to all team members of Content Development for their efforts to make this wonderful book. Career Point Ltd. CONTENTS Chapter Page No. 1. Logarithm and their Properties ♦ Answers ♦ Solutions 1‐4 2 3 2. Theory of Equations ♦ Answers ♦ Solutions 5‐22 10 11 3. Sequences & Series ♦ Answers ♦ Solutions 23‐42 29 30 4. Complex Numbers ♦ Answers ♦ Solutions 43‐70 50 51 5 Permutation & Combination ♦ Answers ♦ Solutions 71‐80 75 76 6. Binomial Theorem ♦ Answers ♦ Solutions 81‐92 84 85 7. Probability ♦ Answers ♦ Solutions 93‐124 103 105 8. Determinants ♦ Answers ♦ Solutions 125‐140 129 130 9. Matrices ♦ Answers ♦ Solutions 141‐152 145 146 10. Functions ♦ Answers ♦ Solutions 153‐170 158 159 11. Limits ♦ Answers ♦ Solutions 171‐180 174 175 Cont.... Chapter Page No. 12. Continuity & Differentiability ♦ Answers ♦ Solutions 181‐204 188 189 13 Differentiation ♦ Answers ♦ Solutions 205‐214 208 209 14. Tangent & Normal ♦ Answers ♦ Solutions 215‐224 217 218 15. Monotonicity ♦ Answers ♦ Solutions 225‐234 228 229 16. Maxima & Minima ♦ Answers ♦ Solutions 235‐252 240 241 17. Indefinite Integration ♦ Answers ♦ Solutions 253‐262 255 256 18. Definite Integration ♦ Answers ♦ Solutions 263‐304 274 275 19. Area under the curve ♦ Answers ♦ Solutions 305‐328 310 311 20. Differential Equation ♦ Answers ♦ Solutions 329‐346 333 334 21. Point & Straight Lines ♦ Answers ♦ Solutions 347‐368 353 354 22. Circle ♦ Answers ♦ Solutions 369‐398 376 377 23. Parabola ♦ Answers ♦ Solutions 399‐418 404 405 Cont... Chapter ,, Page No. 24. Ellipse ♦ Answers ♦ Solutions 419‐432 422 423 25. Hyperbola ♦ Answers ♦ Solutions 433‐442 436 437 26. Vectors ♦ Answers ♦ Solutions 443‐482 455 457 27. 3D Geometry ♦ Answers ♦ Solutions 483‐498 489 490 28. Trigonometric ratio & Identities ♦ Answers ♦ Solutions 499‐506 501 502 29. Trigonometric Equations ♦ Answers ♦ Solutions 507‐520 511 512 30. Inverse Trigonometric Functions ♦ Answers ♦ Solutions 521‐528 523 524 31. Properties of Triangles ♦ Answers ♦ Solutions 529‐550 534 535 32. Height & Distance ♦ Answers ♦ Solutions 551‐560 553 554 33. Mathematical Induction ♦ Solutions 561‐572 563 34. Miscellaneous ♦ Answers ♦ Solutions 35. Model Test Papers ♦ Practice Test‐1 [Paper‐1] ♦ Practice Test‐1 [Paper‐2] ♦ Practice Test‐2 [Paper‐1] ♦ Practice Test‐2 [Paper‐2] 573‐578 575 576 579‐608 579 585 591 599 Chapter 1 Logarithm and their Properties ONLY ONE CORRECT ANSWER 1. 2. The least value of the expression [1980] 2 log10 x – logx (0.01), for x > 1, is : (A) 10 (B) 2 (C) – 0.01 (D) None of these If log0.3 (x – 1) < log0.09 (x – 1), then x lies in the interval : [1985, 2M] (A) (2, ∞) (B) (1, 2) (C) (– 2, – 1) (D) None of these 3 3. ONE OR MORE THAN ONE CORRECT ANSWERS The equation x 4 (log 2 x ) 2 + log 2 x – 5 4 = 2 has : [1987, 2M] (A) at least one real solution (B) exactly three real solutions (C) exactly one irrational solution (D) complex roots 4. The number log2 7 is : (A) an integer (B) a rational number (C) an irrational number (D) a prime number 5. The number of solutions of log4 (x – 1) = log2 (x – 3) is : (A) 3 (B) 1 (C) 2 (D) 0 6. 1. If 3x = 4x – 1, then x = 2 log 3 2 (A) 2 log 3 2 − 1 (C) 1 1 − log 4 3 [2013] 2 (B) 2 − log 2 3 (D) 2 log 2 3 2 log 2 3 − 1 ANALYTICAL & DESCRIPTIVE QUESTIONS 1. 2. Solve for x the following equation : log(2x + 3) (6x2 + 23x + 21) = 4 – log(3x + 7) (4x2 + 12x + 9) [1987, 3M] The value of 1 1 1 1 6 + log 3 4− 4− 4− ... 3 2 3 2 3 2 23 2 is [2012] [1990, 2M] [2001] Let (x0, y0) be the solution of the following equations (2x)ln 2 = (3y)ln 3 3l n x = 2 l n y [2011] Then x0 is 1 1 (A) (B) 6 3 1 (C) (D) 6 2 2 TOPIC- WISE JEE Advanced Questions with Solutions ANSWERS ¾ Only One Correct Answer 1. (D) 2. (A) 3. (B) ¾ One or More than One Correct Answers 1. (A,B,C) ¾ Analytical & Descriptive Question 1. x = − 1 4 2. 4 4. (C) 5. (B) 6. (C) 3 LOGARITHM AND THEIR PROPERTIES SOLUTIONS Only One Correct Answer 1. Here, 2 log10 x – logx (10)(–2) = 2 log10x + 2 logx 10 1 = 2 log10 x + 2 log10 x ⇒ log2 x = 1, – 2, – ⇒ x = 2, 4. 1 = 2 log10 x + log10 x 1 1/ 3 2 , 1 3 1 4 Let x = log2 7 ⇒ 2x = 7. Which is only possible for irrational number. …(1) using, A.M. ≥ G.M., we get log10 x + 1 log10 x 2 ⇒ log10 x + 5. 1/ 2 1 ≥ log10 x. log10 x 1 ≥2 log10 x ⇒ log4 (x – 1) = 2 log4 (x – 3) ⇒ log4 (x – 1) = log4 (x – 3)2 ⇒ (x – 3)2 = x – 1 …(2) ⇒ x2 + 9 – 6x = x – 1 ⇒ x2 – 7x + 10 = 0 or 2 log10 x – logx (0.01) ≥ 4 2. ∴ least value is 4. ⇒ x2 – 5x – 2x + 10 = 0 log0.3 (x – 1) < log0.09 (x – 1) Here, x – 1 > 0 ⇒ (x – 2) (x – 5) = 0 ⇒ x(x – 5) – 2(x – 5) = 0 ⇒ x = 2, or x = 5 Hence, x = 5 [x = 2 makes log (x – 3) undefined]. Therefore, (B) is the answer. and log(0.3) (x – 1) < log(0.3) 2 (x – 1) ⇒ x > 1 and log0.3 (x – 1) < 1 log0.3 (x – 1) 2 ⇒ x > 1 and log(0.3) (x – 1) < 0 3 ln x = 2 ln y x ∈ (2, ∞) ⇒ ⇒ ln x . ln 3 = lny . ln 2 = ln y = ln x 2 3 5 (log2 x)2 + log2 x – = logx 4 4 2 3 5 1 (log2 x)2 + log2 x – = 4 4 2 log 2 x ⇒ 3(log2 x)3 + 4(log2 x)2 – 5(log2 x) – 2 = 0 Put, log2 x = y ⇒ 3y3 + 4y2 – 5y – 2 = 0 ⇒ (y – 1) (y + 2) (3y + 1) = 0 ⇒ y = 1, – 2, – (2x)ln 2 = (3y)ln 3 ln 2 . ln x – ln 3 ln y = (ln 3)2 – (ln 2)2 .....(1) ⇒ x > 1 and x > 2 3 5 (log 2 x ) 2 + log 2 x – 4 x4 6. ln 2 (ln 2 + ln x) = ln 3 (ln 3 + ln y) ⇒ x > 1 and x – 1 > 1 3. log4 (x – 1) = log2 (x – 3) = log 41/ 2 (x – 3) 1 3 ln3 ln 2 .....(2) Solving (1) & (2) ln x = – ln 2 ⇒ x = 1 2 One or More than One Correct Answers 1. 3x = 4x – 1 Take log3 both sides x = (x – 1) log3 4 x = (x – 1) 2log3 2 x (1 – 2log3 2) = – 2log3 2 4 TOPIC- WISE JEE Advanced x= = = 2 log 3 2 2 log 3 2 − 1 2. 2 2 − log 2 3 1 1 − log 4 3 Let x = 4− x2 = 4 – 1 1 3 2 4− 1 3 2 x x= − 1 + 1 + 4.3 2 .12 2 6 2 log(2x + 3) (6x2 + 23x + 21) = 4 – log(3x + 7) (4x2 + 12x + 9) x= 8 −1 + 17 = 6 2 3 2 ⇒ log(2x + 3) (2x + 3).(3x + 7) 4 6 + log3/2 = 6 + log3./2 9 =6–2=4 = 4 – log(3x + 7) (2x + 3)2 ⇒ 1 + log(2x + 3) (3x + 7) = 4 – 2 log(3x + 7) (2x + 3) Put log(2x + 3) (3x + 7) = y ⇒ y+ 2 –3=0 y ⇒ y2 – 3y + 2 = 0 ⇒ (y – 1) (y – 2) = 0 ⇒ y = 1 or y = 2 ⇒ log(2x + 3) (3x + 7) = 1 or log(2x + 3) (3x + 7) = 2 ⇒ 3x + 7 = 2x + 3 or (3x + 7) = (2x + 3)2 ⇒ x=–4 or 3x + 7 = 4x2 + 12x + 9 4x2 + 9x + 2 = 0 4x2 + 8x + x + 2 = 0 (4x + 1) (x + 2) = 0 x = – 2, – 1 . 4 ∴ x = – 2, – 4, – 4− 3 2 x2 + x – 12 2 = 0 Analytical & Descriptive Question 1. 3 2 Questions with Solutions 1 4 But, log exists only when, 6x2 + 23x + 21 > 0. 4x2 + 12x + 9 > 0, 2x + 3 > 0 and 3x + 7 > 0 ⇒ x>– 3 2 ∴ x=– 1 is the only solution. 4 3 2 −2 1 3 2 ...
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