Graphs of Harmonic Motion 1. The following graph represents a 0.40 kg mass oscillating horizontally on a spring. a) Determine the amplitude, period, and frequency from graph. The amplitude of this graph is 4 cm. I determined this by looking and the maximum and minimum values, which were 4 and -4. This meant the total distance traveled by the mass was 8 cm. The amplitude is half that number, 4 cm. The period of this graph is 2 s. I just went from the first max (t = .5) to the second max (t = 2.5). Since f = 1/T, f = ½ Hz. b) Write the equations for the sinusoidal curves using sine or cosine. From Friday, and yesterday’s videos, I know y = Amplitude*trig(ωt). Since, the graph starts at a minimum amplitude, it is a sine function. I learned this in precalc/alg II, whatever. But, when t = 0, sin (0) = 0. This matches with the initial point on the graph. This is how I know it is a sine function. I found the amplitude was 4 cm in part (a). To find ω, use the equation ω = 2πf. So, ω = 2π(1/2) = 3.14. I have cut and pasted the way this equation shows up on the formula sheet. The equation is: y = 4sin(3.14t). Or if you leave π in your answer, y = 4sin(πt). c) Determine the spring constant for the spring. 0.4 2 = 2π√ . We found out the other day this is very hard for us to solve. The correct answer is 3.94 N/m. 𝑘 d) Calculate the maximum acceleration of the mass. kx = ma 3.94(0.04) = 0.4a a = 0.394 m/s2 4 cm = 0.04 m Graphs of Harmonic Motion 2. The following graph represents a pendulum swinging to and fro. a) Determine the amplitude, period, and frequency from graph. To find the amplitude, I found the maximum values are 4 and the minimum values are –2. This is a difference of 6 cm. Half of that is the amplitude, 3 cm. Also, if you see the red line I drew right through the middle of the function? This is like the “new x-axis”. From that line, the amplitude is 3 cm each way. Period is 3 s. Frequency is 1/3 Hz. b) Write the equations for the sinusoidal curves using sine or cosine. This curve begins at a maximum (or minimum) value. This represents a cosine curve. To find ω, use the equation ω = 2πf. So, ω = 2π(1/3) = 2.09. I have cut and pasted the way this equation shows up on the formula sheet. 2 The equation is: y = 3cos(2.09t). Or, if you leave π in your answer 𝑦 = 3cos( 𝜋𝑡). 3 c) Determine the length of the pendulum. 𝐿 3 = 2π√ 10 L = 2.282 m Graphs of Harmonic Motion 3. A 0.80 kg mass vibrates according to the equation, 𝑥 = 0.3cos(8.0𝑡), where x is in meters and t is in seconds. Determine the a) Amplitude The amplitude is 0.3 m b) Period ω=8 T = 2π/8 = π/4 = 0.785 s c) Frequency f = 8/2π = 4/π = 1.2732 d) Spring constant 0.8 0.785= 2π√ . The correct answer is 51.2 N/m. 𝑘 e) Total distance the mass travels during 1 period. For one cycle, the mass will travel 0.3m four times. The answer is 1.2 m. Graphs of Harmonic Motion 𝜋 4. A pendulum swings according to the equation, 𝑥 = 2.4sin( 𝑡), where x is in meters and t is in 4 seconds. Determine the a) Amplitude 2.4 m b) Period ω = π/4 T = 2π/(π/4) = 8 s c) Frequency f = 1/8 Hz d) Length of the pendulum. 𝐿 8 = 2π√ 10 L = 16.2278 m e) Total distance the bob travels during 1 period. 4(2.4) = 9.6 m
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