Chapter 17 Complex Aqueous Equilibria Common Ion Effect Buffers Titrations Predict using LeChatelier’s Principle CH3COOH(aq) H+(aq) + CH3COO−(aq) Consider the equilibrium involving the weak acid at 298K shown above. What will happen to the pH if some solid CH3COONa is added while the temperature is held constant? 1. The p pH will increase 2. The pH will decrease 3 The pH will not be effected 3. effected. 4. There is not enough information to determine the effect on the pH. pH Chem 112 MJ Bojan 2 Test the prediction by doing an experiment. DEMO: CH3COOH(aq) H+(aq) + CH3COO−(aq) pH = Add CH3COONa(s): CH3COONa (aq) → Na+(aq) + CH3COO−(aq) pH = What happened to [CH3COO−]? Common Ion Effect: if a system is at equilibrium and it is disturbed by adding a strong electrolyte with a common ion, the ionization of the weak electrolyte will be reduced. d d [CH3COOH]? [H+]? Chem 112 3 MJ Bojan What happens when a strong acid is added to a weak acid and to a mixture of the acid and its conjugate base? CH3COOH(aq) COOH( ) H+(aq) ( ) + CH3COO−(aq) ( ) pH 0 1M CH3COOH(aq) 0.1M Add HCl Mixture 0.1M CH3COOH 0.1M CH3COONa pH Add HCl Add NaOH Add NaOH How does the addition of strong acid or base effect the pH of the weak acid? of the mixture? Example of the Common Ion effect A Buffer is a solution that “resists” a change g in p pH E.g. E g blood contains substances that keep its pH fixed at 7.3 important for life functions Buffer solutions consist of either: http://chemcollective.org/activities/tutorials/buffers/buffers3 Chem 112 MJ Bojan 5 How do Buffers work? When strong acid or base is added, the ratio of weak acid: weak base does not change much. If a small amount of hydroxide y is added to an equimolar solution of HA in NaA,, the HF reacts with the OH− to make A− and water. Buffer after adding OH Buffer with [HA] = [A] OH [HA] [A] Buffer after adding H+ Similarly, if acid is added, the A− reacts with it to form HA and water water. H+ [HA] [A] http://chemcollective.org/activities/tutorials/buffers/buffers3 [HA] [A] 6 Quantitatively C l l t th Calculate the pH H off a solution l ti th thatt iis 0 0.1M 1M CH3COOH and 0.1M CH3COONa Chem 112 MJ Bojan 7 We can derive an expression that will enable us to calculate the p pH of a buffer solution. Consider the equilibrium constant expression for the dissociation of a generic acid, HX: HX(aq) H+(aq) + X−(aq) This is the Henderson–Hasselbalch Henderson Hasselbalch equation. equation Chem 112 MJ Bojan 8 Calculating the pH of a Buffer What is the pH of a buffer that is 0.12 M in lactic acid, CH3CH(OH)COOH, and 0.10 M in sodium lactate? Ka for f lactic l ti acid id iis 1 1.4 4 × 10−44. Chem 112 MJ Bojan 9 Calculating the pH of a Buffer Calculate the pH of a solution that is 0.1M NH3 and 0.2M NH4Cl. Kb for NH3 is 1.8 × 10−5. Chem 112 MJ Bojan 10 When Strong Acids or Bases Are Added to a Buffer… Buffer reaction occurs. occurs Follow a 2-step process to determine pH 1. neutralization 2. pH determination neutralization A(aq) + H+(aq) → HA(aq) Calculate [HA] and [A] Buffer HA + A pH determination neutralization HA(aq) + OH(aq) → A(aq) + H2O() Equilibrium calculation Stoichiometry calculation Chem 112 11 MJ Bojan Finding the pH after adding g Acid or Base to a Buffer Strong 1. Determine how the neutralization reaction affects the amounts of the weak acid and its conjugate base in solution. 2. Use the Henderson–Hasselbalch equation to determine the new pH of the solution. Add 0.020 0 020 mol OH pH =??? Add 0.020 0 020 mol H+ Buffer: 0.300 M CH3COOH 0.300 M CH3COONa pH =??? pH = 4.74 Chem 112 12 MJ Bojan Calculating pH changes in Buffers A buffer is made by adding 0.300 mol HC2H3O2 and 0.300 mol NaC2H3O2 to enough water to make 1.00 L of solution. The pH of the buffer is 4.74. Calculate the pH of this solution after 0.020 mol of NaOH is added. Chem 112 13 MJ Bojan Finding the pH after adding g Acid or Base to a Buffer Strong 1. Determine how the neutralization reaction affects the amounts of the weak acid and its conjugate base in solution. 2. Use the Henderson–Hasselbalch equation to determine the new pH of the solution. Add 0.020 0 020 mol OH Buffer: 0.280 M CH3COOH 0.320 M CH3COONa pH = 4.80 4 80 Chem 112 Add 0.020 0 020 mol H+ Buffer: 0.300 M CH3COOH 0.300 M CH3COONa pH = 4.74 4 74 MJ Bojan Buffer: 0.320 M CH3COOH 0.280 M CH3COONa pH = 4.68 4 68 14 Choosing a Buffer pH range of a buffer: range of pH over which the buffer acts effectively effectively. optimal pH: Chem 112 Buffer region MJ Bojan 15 Buffer Capacity: volume of acid or base that can be added before the pH of the buffer changes appreciably. Whi h solution Which l ti will ill have h the th greatest t t buffer b ff capacity? it ? 1M CH3COOH/CH3COONa 0.1M CH3COOH/CH3COONa Chem 112 MJ Bojan 16 Titration A pH meter or indicators are used to determine when the solution has reached the equivalence point: In this technique a known concentration of base (or acid) is slowly added to a solution of acid (or base). Chem 112 MJ Bojan 17 The titration of a strong acid with a strong base can be described byy a p plot of p pH vs. amount of base added. Chem 112 MJ Bojan 18 Quantitative determination of the pH for an acid Acid Base Titration is a two step process 1. Neutralization What is in solution after neutralization? 2. Find the pH A) strong acid/base B) weak/acid base equilibrium calculation buffer solution Chem 112 MJ Bojan 19 Sample calculation of pH during the titration of a Strong Acid with a Strong Base Titrate 0.1M HCl with 0.2M NaOH starting with 50 mL of HCl solution. Calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 20 mL NaOH, c. 25 mL NaOH, d. 30 mL NaOH a. Initial concentration of strong acid: (0mL of NaOH added) Chem 112 MJ Bojan 20 Sample calculation of pH during the titration of a Strong Acid with a Strong Base Titrate 0.1M HCl with 0.2M NaOH starting with 50 mL of HCl solution. Calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 20 mL NaOH, c. 25 mL NaOH, d. 30 mL NaOH b. concentration of solution after adding 20mL of NaOH: Chem 112 MJ Bojan 21 Sample calculation of pH during the titration of a Strong Acid with a Strong Base Titrate 0.1M HCl with 0.2M NaOH starting with 50 mL of HCl solution. Calculate pH when 25 mL of NaOH is added. Equivalence point is where moles of acid = moles of base c. concentration of solution after adding 25mL of NaOH : Chem 112 MJ Bojan 22 Sample calculation of pH during the titration of a Strong Acid with a Strong Base Titrate 0.1M HCl with 0.2M NaOH starting with 50 mL of HCl solution. Calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 20 mL NaOH, c. 25 mL NaOH, d. 30 mL NaOH d. concentration of solution after adding 30mL of NaOH: Chem 112 MJ Bojan 23 The titration of a weak acid with a strong base can be described byy a plot p of p pH vs. amount of base added. Chem 112 MJ Bojan 24 Calculating the pH during the Titration of a Weak Acid with a Strong Base is still a two step process. g pp Sol’n with HA and A HA and A neutralization HA(aq) + OH HA(aq) OH(aq) → A(aq) (aq) + H H2O() Stoichiometry calculation Determine [HA], [A] [HA], [A pH determination (buffer) Equilibrium calculation At each point below the equivalence point, the pH of the solution during titration is determined from the the solution during titration is determined from the amounts of the acid and its conjugate base present at that particular time. Buffer solutions are encountered during titrations! Chem 112 25 MJ Bojan Sample calculation of pH during the titration of a Weak Acid with a Strong Base Titrate 0.1M CH3COOH (Ka = 1.8 x 10−5) with 0.2M NaOH starting with 50 mL of CH3COOH solution and calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 12.5 mL NaOH, c. 25mL d. 30 mL NaOH a. Initial concentration of weak acid: (0mL of NaOH added) Chem 112 MJ Bojan 26 Sample calculation of pH during the titration of a Weak Acid with a Strong Base Titrate 0.1M CH3COOH (Ka = 1.8 x 10−5) with 0.2M NaOH starting with 50 mL of CH3COOH solution and calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 12.5 mL NaOH, c. 25mL d. 30 mL NaOH b. Half way to equivalence (12.5mL of NaOH added) Chem 112 MJ Bojan 27 Sample calculation of pH during the titration of a Weak Acid with a Strong Base Titrate 0.1M CH3COOH (Ka = 1.8 x 10−5) with 0.2M NaOH starting with 50 mL of CH3COOH solution and calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 12.5 mL NaOH, c. 25 mL NaOH d. 30 mL c. At the equivalence point (25mL of NaOH added) Chem 112 MJ Bojan 28 Sample calculation of pH during the titration of a Weak Acid with a Strong Base Titrate 0.1M CH3COOH (Ka = 1.8 x 10−5) with 0.2M NaOH starting with 50 mL of CH3COOH solution and calculate pH when the following quantities of NaOH are added: a. 0 mL NaOH, b. 12.5 mL, c. 25mL d. 30 mL NaOH d. Beyond the equivalence point; excess strong base (30 mL of NaOH added) Chem 112 MJ Bojan 29 The initial pH of a weak acid and pH at equivalence after titration with ith a strong t base b d depends d on th the value l off Ka off the th weak k acid. id Chem 112 MJ Bojan 30 INDICATORS are organic molecules that have different colors for the acid and conjugate base. InH+(aq) In(aq) + H+(aq) Some of the more common acid-base indicators Name pH interval for Color change Acid color Base color Methyl y violet 1 - 2 Yellow Violet Methyl yellow 1.5 - 2.5 Red Yellow Methyl orange 2.5 - 4.0 Red Yellow Methyl red 4 2 - 6.3 4.2 63 Red Yellow Bromthymol blue 6.0 - 7.6 Yellow Blue Thymol blue 8.0 - 9.6 Yellow Blue Phenolphthalein 8.5 - 10 Colorless Pink Alizarin yellow G 10.1-12.0 Yellow Chem 112 Red MJ Bojan 31 Choose an indicator that will change in the range of the equivalence point. Chem 112 MJ Bojan 32 Titration curve of a Weak Base with a Strong Acid shows how p pH changes g with bases added. Strong acid - strong base: The pH at the equivalence point indicator of choice is: Strong acid - weak base: base: The pH at the equivalence point indicator of choice is: Chem 112 MJ Bojan 33 Summary of expectations for pH at q in acid base titrations. equivalence Titrating a strong acid (base) with a strong base (acid) pH at equivalence Tit ti a weak Titrating k acid id with ith a strong t base b pH at equivalence Titrating a weak base with a strong acid pH at equivalence Chem 112 MJ Bojan 34 Titrations of Polyprotic yp Acids Chem 112 MJ Bojan 35 Find the pH of this solution? A buffer solution is 0.20M in HPO42− and 0.10M in H2PO4−. What is the [H+] in this solution? H3PO4: Ka1 = 7.5 10−3 Ka2 = 6.2 10−8 12 Ka3 = 1 10−12 A. B. C. D. E. 3.7 10−3 M 3.7 10−4 M 3.1 10−8 M 3.1 10−9 M 5.0 10−13 M Chem 112 MJ Bojan 36
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