4.x2-/*4,!=2x-l 7, 1:L. y =5

Math t82 - Collaboradve Activity - Review for Exam #1
Verify the general solution of the differentlal equation. Then find the particular solution
that satisfres the initial condition.
1. Solution
i y2 -9x2 - C
Differential equation
t
yy' -9x
-0
Initial Condition:
f(t)
=+
Set-up an integral that represents the area of the shaded region bounded by the graphs.
Do notevaluate.
3. !-x2,
2.
Je
+y=2, /n0
Sketctr the region bounded by the graphs of the algebraic frrnctions and find the area
of
the region.
4.x2-/*4,!=2x-l
5.
y -sinr, y =3sinx, x -0, x * trt
Find the volume of the sotid generated by revolving the reglon bounded by the graphs of
the equations about the given axis.
6. y
7.
y
=.[4,, ! =0, r =6 aboutthex-axis (usedisksorwashers)
j
-i.*, * -2, ! =0 aboutthey-axis (usedisksorwashers)
8. .y -
I
7, I
9. y *er,
n0, x *1,
)c
*2
aboutthey'axis (use cylindrical shells)
! *0, I =0, x =1 abouttheline x -4 (usemethodofyourchoice)
L0.y =x3, !
*8, r =0 abouttheline.y=9
(usemethodofyourchoice)
Find the arclength of the graph over the given interval.
1:L.
y
=5-2{7, lsx,s4
Find the area of the surdace generated by revolving the curve about they'axis.
12,
y*2x+5, lsxs4
fnqJ+1
t$f -
Colla.boraJr\p
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i
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ri ,*ri(.i -("'i"'{
i
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"
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.
o
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+,
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: ltert*
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o
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ro
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v.
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u=
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a
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rral
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u=
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durQdX
t
du = dx
rr,,s,*
!*IN*
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lpa=[0
la.
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\
t?
-i*.*=,*
atr(
€)i
= Ii
5
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ct
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dy
ti.-')i
=$a--r)g =E"Llf 'l1f
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a
-- ,-
( T-.t)
,g
us,(
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ao9rr=L
=
(,T-=)
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\
I
I
Qo
oA
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I
:
Jtr
x = {lrrdx
,sn[l^,
/[
(z'
a.Rv
+
r-\
z-)
'tt
(, Y) =
a<rFrr
G):
lc.(3n