Chemical bonding Inorganic materials chemistry and functional materials Helmer Fjellvåg and Anja Olafsen Sjåstad Lectures at CUTN spring 2016 Chemical bonding - electronegativity OLD Size of atoms Nuclear charge (protons) Z No. of electrons Z Shielding Attractive forces nucleus – electrons Repulsive forces electron – electron Effective nuclear charge .... ”how strongly does the nucleus attract electrons” Depends on how well do inner electrons shield outer electrons Na Mg ----- Si -----Cl: increasing effective nuclear charge consequence: reduction in atomic size (atomic radius) Chemical bonding - electronegativity Zeff = Z – s s = Slater shielding constant Net attraction experienced – values of effective nuclear charge OLD Chemical bonding - electronegativity OLD Trends – ionization enthalpies; 1st, 2nd, 3rd,... Cations are formed In compounds; more oxidation states may be feasible Increasing DHionization Huge increase when noble gas electron configuration is broken A2+(g) = A3+(g) + e- Cf. change in effective nuclear charge A+(g) = A2+(g) + eA(g) = A+(g) + e1 eV = 96 kJ/mol Rule of thumb: noble gas configuration is never broken: HENCE: Alkali(I) Alkaline earths (II) etc. Chemical bonding - electronegativity Electronaffinity: Eea OLD A(g) + e- = A-(g) Eea is defined as the negative enthalpy change for this reaction EXAMPLE: F(g) + e- = F- (g) DH = -328 kJ/mol Eea = +328 kJ/mol A positive electron affinity implies an exothermic reaction Why O lower value than S, Cl ? e – e repulsions... DH values: Chemical bonding – oxidation numbers OLD Simple rules, extremely useful in chemistry The most electronegative elements; oxygen (-II), fluorine (-I) exceptions compounds between oxygen and fluorine; like OF2.... Never break a closed noble gas electron shell; hence alkali(+I), alkaline earth(+II),.. Group 13, 14, 15 possibility of [ns2] lone pair for the heavier group elements Tl(III) [s0] and Tl(I) [s2]; Pb(IV) [s0] and Pb(II) [s2]; these lone pairs may have be stereoactive Bi(V) [s0] and Bi(III) [s2]: d-elements; many oxidation states; jumps of 1 in ox.state possible QUESTIONS What is the oxidation state for the cations in: BaO2 CsO2 Mn3O4 Pb3O4 TiS2 FeS2 Several functional oxides show mixed valence state => not integer ox.state numbers Can be tuned by substitution/doping YBa2Cu3O7 LaMnO3.15 (La,Sr)FeO3 Chemical bonding Chemical bonding Chemical bonding is in reality a mixture of two or three of the (extreme) components ionic, covalent and metallic OLD Chemical bonding - trends Chemical bonding - electronegativity OLD The difference in Pauling electronegativity between atoms A and B is defined by: where Ed is the dissociation energies of A–B, A–A and B–B bonds in eV. Example: Difference in Pauling electronegativity between H and Br is 0.76 Dissociation energies: H–Br = 3.79 eV H–H = 4.52 eV Br–Br = 2.00 eV Chemical bonding - electronegativity Mulliken electronegativity On an absolute scale (kJ or eV) Arithmetic mean of first ionization enthalpy and electron affinity of involved atoms Pauling Are given in relative units (as Pauling electronegativity) by (E in eV): Mulliken Chemical bonding - electronegativity Sanderson electronegativity method of calculation based on the reciprocal of the atomic volume. Based on concept of electronegativity equalization = electrons distribute themselves in such a way that Mulliken electronegativity differences are minimized. This is analogous to equalization of chemical potential in macroscopic thermodynamics. S = Sanderson electronegatiivty D = electron density or atomic volume of an atom Da = density or volume based on interpolation between noble gas elements Pauling Electronegativity is a measure of the attractive forces between the effective nuclear charge and an outermost electron, hence, it also relates to the compactness of the atom (i.e. its volume; electron density) Sanderson Chemical bonding - electronegativity Sanderson electronegativity Principle of electronegativity equalization: When atoms combine in a chemical compound, they get adjusted to take the intermediate electronegativity (of the compound) This electronegativity is given as the geometric mean. Example for NaF: The values for SNa etc are tabulated Two assumptions: - NaF is 75% ioinc (quite reasonable; group 1 and 17) - Electronegativity changes linearly with charge. Then: the change in electronegativity DSc of at atom aquiring a unit positive or Negative charge is given by Partial charge, d, is defined then as where Chemical bonding - electronegativity Chemical bonding – electronegativity - examples Sanderson electronegativity; examples BaI2: Tabulated values: SBa = 0.78, SI = 3.84, DSc(Ba) = 1.93; DSc(I) = 4.08 DSBa = 2.26 – 0.78 = 1.48 DSI = 2.26 – 3.84 = -1.58 Calculated charges are then dBa = 1.48/1.93 = 0.78 and dI = 1.58/4.08 = -0.39 which implies 39% ionic The radius of the atoms (cations and anions) depends on their charge: Uses rc = 1.98Å and B = 0.78 for Ba And rc = 1.33Å and B = 1.384 for I Calculated size of the atoms/ions are: Barium: 1.71Å Iodine: 1.87Å Sum 1.71Å + 1.87Å = 3.58Å corresponds well to the experimental value of 3.59Å Chemical bonding – electronegativity - Sanderson The numbers should not be considered as accurate, however, they show the main trends! Size of anion depends on chemical environment The charge on chlorine is never as negative as -1 ! Chemical bonding – electronegativity - Sanderson OXIDES: the charge on oxygen is far less negative than -2 ! Chemical bonding - electronegativity Electronegativity – remarks on oxidation states Many atoms in inorganic chemistry may take more than one oxidation state; e.g. group 13, 14, 15, 16, 17 and the d-elements. The simple concept with a single value for the electronegativity is “valid” for "normal" situations, but not when more oxidation states are feasible Electronegativity is not an invariable atomic property Detailed data exist for a few elements where analysis been possible. For delements, tabulated electronegativities are averages for more oxidation states. In general: electronegativity increases with oxidation number. The chemical implication is seen in the crystal structures; in the acidity of oxides and acid strength of oxoacids (dissociation constants) CrO3 acidic and low melting point; Cr2O3 amphoteric and high melting point; HnClOm oxoacids pKa = 8 – 5p (p = nb. non-protonated O-atoms) Acid strength of cations in water Chemical consequences Chemical bonding – reactivity – example acid/basic oxides H3 O+ + OLD Acidic versus basic (hydr)oxides MOnx- Acidic oxide Very electronegative cation H e e +d H2O : H O M on SURFACE BULK H Electropositive cation Mn+ + OH- Basic oxide 19 Rule of thumb: DC (el.neg) > 1.4 between M and O basic Chemical bonding – reactivity – example acid/basic oxides Basic Amphoteric Acidic OLD 20 Chemical bonding – polarization – example acidity of cations OLD B3+(aq) ??? Does NOT exist as such But as B(OH)3 Al3+(aq) ? Z2/r Forms at pH7 Example 0-0.04 hydrated cation NaI (H2O)6+ 0.04-0.22 hydroxide, oxide, or oxidehydroxide AlIII (H2O)3(OH)3 oxidehydroxide or hydroxo anion SeVI O3(OH)- oxoanion BrVII [Al(H2O)6]3+ Cationic acid Protolysis: [Al(H2O)6]3+ 0.22-0.8 2+ + [Al(H2O)5(OH)] + H > 0.8 O4 - 21 Chemical bonding – polarization – example oxoacids 1) Oxoacids: The acid strength increases with the number of nonprotonated O-atoms bonded to the central cation H–O–N=O m=1 m=2 H–O–N generalize the formula to: (HO)nXOm RULE: or RULE: m = 0; pKa = 8 m = 2; pKa = 1 m = 1; pKa = 2 m = 3; pKa = 8 Alternative evaluation of pKa value: pKa = 8 - 5p 2) Electronegativity and size of central atom for the oxoanion also affects the acidity 22 Chemical bonding - electronegativity Van Vechten electronegativity scale Restricted to ANB8-N compounds Following the 8-N rule Dielectrically defined Quantum mechanical foundation Additional ionic component to the band gap Heteropolar energy; homopolar energy and «ionic energy» Tetrahedral structures Elements, AB compounds... Chemical bonding - electronegativity Van Vechten electronegativity scale Dielectricaly defined sp3 electronegativities Chemical bonding - electronegativity Van Vechten electronegativity scale Correlation with Pauling electronegativity Chemical bonding - electronegativity Van Vechten electronegativity scale Critical ionicity CN = 6 CN = 4 Scale for ionicity Chemical bonding – examples compounds; radius ratio rules Radius – ratio rules Sphere packings rK/rA Geometry CN cube (8) Octaedral (6) Tetrahedral (4) 1.000 0.732 0.414 0.225 Trigonal planar (3) 0.155 Linear (2) Chemical bonding – size of ions/atoms - trends Size, charge, spin states - trends Isolectronic series: Na(I), Mg(II), Al(III), Si(IV) Effect of oxidation nb: V(II) V(IIII) Effect of spin state: Fe(III)HS Fe(III)LS V(IV) V(V) Octahedral site: eg orbitals 28 Chemical bonding – examples compounds; cation constant AlF3 AlF3 is most ionic of these three examples; 3D strutcure; corner shared octahedra AlCl3 AlCl3 is more covalentCN(Al) still 6. Now a 2D structure. Lower Tm than the fluoride. AlBr3 Is molecular; consists of dimers; Al2Br6 with edge shared tetrahedra. CN=4 (cf. radius ratio rule) Low melting point. OLD Chemical bonding – examples compounds; anion oxygen H Li Electrondensity 3 11 Na K 19 37 Rb 55 Cs Na2O Fr MgO 87 Be 4 12 Mg 20 Ca Sr 38 56 Ba 5 B Al 13 31 Ga 49 In Tl 81 1 He 6 C Si 14 Ge 32 50 Sn 82 Pb 7 N P 15 33 As 51 Sb Bi 83 8 O S 16 Se 34 Te 52 9 F Cl 17 Br 35 53 I Ne Ar Kr 2 10 18 36 Xe 54 Na(I), Mg(II), Al(III), Si(IV) 86 84 85 isoelectronic [Ne] Rn Poare At Increasing Z2/r Al2O3 more polar covalent Normale oksider O oksidasjonstall (cf. Fajan-2 rules) We observed more electron Oksidasjonstall –1 i peroksider density inbetween cation and anion. 30 SiO2 88 Ra Chemical bonding – examples compounds; anion oxygen H Li 3 11 Na K 19 37 Rb 55 Cs Na2O Fr 87 Be 4 12 Mg 20 Ca Sr 38 56 Ba 5 B Al 13 31 Ga 49 In Tl 81 1 He 6 C Si 14 Ge 32 50 Sn 82 Pb 7 N P 15 33 As 51 Sb Bi 83 8 O S 16 Se 34 Te 52 84 Po 9 F Cl 17 Br 35 Ne Ar Kr 53 I At 85 2 Decreasing radius ratio Change in coordination 10 18 36 Xe 54 86 Rn 88 RaAl O 2 3 ClO2 P4O10 Normale oksider O oksidasjonstall -2 «ionic» CN = 4 Polar covalent Oksidasjonstall –1 i peroksider MgO SiO2 S3O9 31 Chemical bonding – examples compounds; anion fluorine Increasing covalent character 11 12 Na Mg NaF MgF2 Al 13 Si 14 P 15 PF3 AlF3 SiF4 PF5 S 16 SF4 Cl 17 ClF5 SF6 molecular 32 Chemical bonding – examples structure – thermal stability Relative melting(boling point Termal stability versus oxidation state & structure Ionic Layered or Structure 3D network Chain Molecule Polymer Dimer,.. Oxidation number (for central cation) (Here: maximum expected for en given group) The drop in stability reflects differences In the long range crystal structure Again a result of size of cations and bonding 33 Chemical bonding – examples Cations with stereoactive lone pairs (i.e. hybridized; not pure s-character...) may stabilize non-centrosymmetric structures; e.g. PZT Pb(Zr,Ti)O3 PbO2 Ox.state +IV Ox. state +II Pb3O4 PbO2.2PbO PbO yellow orthorhombic 491 oC brown PbO red tetragonal 34 Chemical bonding – examples and questions How will you compare/describe the chemical bonding in: - MgO, BaO, NiO, ZnO? NaH, MgH2, SiH4, HCl? Na4C, SiC, CO2? Mg2Si, Si, GaAs? LaAlO3, LaFeO3, LaNiO3? NaAlH4, Li3AlH6, LiBH4? Na4SiO4, FePO4, Na2SO4, LiClO4? QUESTIONS: Consider AgO. It is diamagnetic. How will you explain that based on likely oxidation states and local geometry for the Ag-cations? Consider Cr8O21. This compound conistst of Cr(III) and Cr(VI) as cations. Provide a formula highlighting the oxidation states. What geormetry do you expect for the Cr(III) and Cr(VI) coordination polyhedra with oxygen? Chemical bonding – charge neutrality Pauling's rules are five rules published in 1929 for predicting and rationalizing structures of ionic compounds 1. Minimum size to fit into a void/hole; rattling is not a stable situation Rcation/Ranion 2. For a given cation, the electrostatic bond strength to each coordinated anion is s = z/n , with z = cation charge and n = cation coordination number. The atomic arrangement of a stable ionic structure preserves local electroneutrality. Hence, the sum of the electrostatic bonds strengths to an anion equals the anion charge. In Li2O, Li has four oxygen atoms in tetrahedral surroundings; s = ¼ The O-atom has eight neighbouring Li-cations; hence x = 8 x ¼ = 2 equal to O-charge 3. The sharing of edges and faces by anion polyhedra decreases the stability Corner sharing more stable > edge sharing > face sharing 4. When different cations, those of high valence and low coordination number tend not to share polyhedra Chemical bonding – examples Other routes to non-centrosymmetry; piezo/pyro/ferroelectrics By hybridization (d0 cations); by rattling (size; see e.g. t-factor) Perovskite type BaTiO3 183 K < T Paraelectric to ferroelectric (T < 393 K) Chemical bonding – charge neutrality - examples AaBb compounds of regular type (ionic/covalent – insulator/semiconductor) a . CN(A) = b . CN(B) TiO2: Ti in octahedral holes; CN(Ti) = 6; CN(O) = 3 SiO44- tetrahedra are building bricks in silicates. Highly charge Si(IV); only corner sharing acceptable How many SiO4-tetrahedra may share the same O-atom/corner? Electrostatic bond strength (ebs) s = 4/4 = 1 Charge of O-atom is -2; hence maximum 2 surrounding Si-cations Maximum 2 SiO4-tetrahedra can share the same O-atom/corner Wüstite Fe1-xO; stoichiometric FeO is metastable; instead some Fe(II) oxidizes to Fe(III) and the non-stoichiometric wüstite forms. The Fe(III) atoms are smaller in size and has higher charge Will take tetrahedral interstices in the ccp of O-anions Such interstital Fe(III) will repel the Fe(II) at regular octahedral sites. Defect clusters (complexes) are formed; Fe-vacancies cluster around the Fe(III) interstitials Chemical bonding – charge neutrality - solid solutions Aliovalent (heterovalent) substitution – in ionic compounds AOx Defect formation; charge compensation Too much positive charge Substitution by higher valence cations (B) into AOx Cation vacancies Interstitial anions Too much negative charge Substitution by lower valence cations (C) Anion vacancies Interstitial cations Side note: Similar patterns can be made for anion substitution; but are not included here as aliovalent anion substitution occurs to lesser extent in solid solutions Chemical bonding – charge neutrality - solid solutions - diffusion Interstitial anions – ionic conductitivity Possible interstitial site AB2 with A6B8 neighbors octahedral site (in ccp of A atoms) The interstitial site can typically be filled with anions; AB2+d = dominating defect for CaF2-type phases Possible route for anion transport PbF2+d (Y, Zr)O2-d Chemical bonding – charge neutrality - solid solutions - diffusion Interstitial anions – ionic conductitivity (Y, Zr)O2-d YSZ: yttria stabilized zirconia Solid solution; Y(III) on Zr(IV) site O-vacancies Technologcal issue: phase compatibility Interface reactions - interdiffusion The interstitial site can typically be filled with anions; AB2+d = dominating defect for CaF2-type phases Possible route for anion transport PbF2+d Chemical bonding – defects - diffusion Mint Voct Moct Mint Activation energies for creation of Frenkel defects for movement of cations What will be the transport mechanism of diffusing cations; in NaBr and in AgBr (consider ionicity)? Chemical bonding – bond valence Calculation of bond valence is a useful method for evaluating oxidation states and certain structural aspects of compounds. The valence V of an atom = sum of individual bond valences vi surrounding the atom: The individual vi bond valences are calculated from observed bond lengths, Ri. Ri is observed bond length R0 tabulated parameter for (ideal) bond length when element i has valence 1, and b is an empirical constant, typically 0.37Å The bond valence model is an extension of the electron counting rules; its strength lies in simplicity and robustness. It does not require a prior knowledge of the atomic positions and so can be used to construct chemically plausible structures given only the composition. However, the bond valence model has limitations. It is restricted to compounds with localized bonds; it does not apply to metals or aromatic compounds where the electrons are delocalized. Chemical bonding - examples Software for bond valence calculations: http://www.ccp14.ac.uk/solution/bond_valence/ More details on bond strength and bond valence: see slides http://www.mrl.ucsb.edu/~seshadri/2011_218/2011_218_BondValenceSums.pdf Chemical bonding - examples http://www.mrl.ucsb.edu/~seshadri/2011_218/2011_218_BondValenceSums.pdf Chemical bonding - examples High-Tc superconductors - cuprates Planes; square pyramidal units YBCO = YBa2Cu3O7 TC = 92 K Chains; square planar units Chemical bonding - examples Evident from the formula (Y0.33Ba0.67)CuO3−0.67 there are oxygen vacancies in the O-substructure. In YBCO these vacancies are ordered. The YBCO structure does never have any O-atoms in the positions described as vacancies Where are the new vacancies located; how does the Cu-coordination polyhedra change; and what happens with the electronic properties (superconductivity)? In YBa2Cu3O6 the average Cu-oxidation state is 1.67. This stoichiometry is consistent with the formal description YBa2Cu(I)Cu(II)2O6. Look up crystal structure and bond valence data: Calculate B.V. For the Cu-atoms. Chemical bonding – elements - structure (8-N) rule Carbon group: N = 4 4 bonds Nitrogen group: N = 5 3 bonds How to obtain a filled octet.... Can be achieved in different ways allotropic forms of the elements Diamond sp3 N N Graphite: sp2 + pz Nitrogen: triple bond White phosphorus Molecular P4 Three single bonds Layered red and black 48 phosphorus Chemical bonding - compounds Compounds with «unusual» compositions; how to explain them? Zintl phases; group 1 and 2 + an element from group 13, 14, 15 or 16 Typically diamagnetic Typically semiconductors or poor conductors Example: NaSi Na must have oxidation state +I. On average silicon is then –I. How possible? Silicon forms a tetrahedron; Si44Charge compensated by 4 Na+ Na4Si4 NOTE: Si44- is isoelectronic to P4 NaSi is a polyanion compound Chemical bonding - examples The (8-N)-rule provides the number of bonds in a compound (N = number of valence electrons of the element which builds the compound) Example: Phosphorus (P): N = 5; (8 - N) = 8 - 5 = 3. Hence, phosphorus has 3 bonds, i.e. white phosphorus exists as a P4-tetrahedron Polyanion compounds (and polycation): The (8 - N)-rule is then expanded (8 - VEC) = number of bonds VEC = valence electron concentration = [m × e(M) + x × e(X)]/x for a compound MmXx where e(M) and e(X) equals the number of valence electrons of the elements M and X, respectively Example NaSi: VEC = [4 × 1 + 4 × 4]/4 = (4 + 16)/4 = 5 Si44- behaves like an element of the 5th main group (group 15) The crystal structure correspond to that of white phosphorus Bonds: (8 - VEC) = 3; for each silicon atom 3 bonds exists Chemical bonding - examples Example NaTl VEC = [1 × 1 + 1 × 3]/1 = 4 The electronegative part of the structure (the polyanion) behaves like an element of the 4th main group (group 14). The crystal structure of the polyanion (Tl-) is of diamond type (8 - VEC) = (8 - 4) = 4 For each Tl-atom 4 bonds exists The Tl- polyanion has a 3D-structure based on 2e-bonds between each Tl-atom Chemical bonding - examples Checking out on MgB2 VEC = [1 × 2 + 2 × 3]/2 = 4 The electronegative part of the structure (polyanion) behaves like an element of the 4th main group (group 14). If behaving like a Zintl phase; then The crystal structure of the polyanion (B22-) is of diamond type (8 - VEC) = (8 - 4) = 4 This is not the case: For each B-atom 3 bonds exists + one electron This is, however, corresponding to graphene The band near the Fermi level is mainly derived from boron orbitals: sp 2 (σ) states and pz(π) states. The σ bands are 2D in character and form cylindrical Fermi surfaces, whereas the π bands have more of a 3D character. Chemical bonding - examples Note; this also covers small polyanions BaO2 with peroxide anion O22VEC = [1 × 2 + 2 × 6]/2 = 7 The electronegative part of the structure (polyanion) behaves like an element of the 7th main group (group 17); the halogenes (like F2) HgCl Is a polycation compound with Hg-Hg bonding; forming a dimer Hence; Hg2Cl2 is a better chemical formulation QUESTION: Do you expect different crystal structure for TiS2 and FeS2? Consider oxidation states: Ti(IV) Fe(IV) or not?? S(-II) answer: layered structure for TiS2 with Ti(IV) and S(-II) Polyanion for FeS2 with Fe(II) and S22 Why so? Fe(IV) too strong oxidizing agent to coexist with reduced S(-II) Chemical bonding - examples Oxygen species... O22- peroxide O24Li(s) + O2(g) (4Na + O2 O2- superoxide (hyperoxide) 2Li2O(s) 2Na2O) 2Na + O2 Na2O2 ( 2K + O2 K2O2 ) K + O2 KO2 Rb + O2 RbO2 Cs + O2 CsO2 Chemical bonding - examples ½+½ S = Sms = 1 Ground stated 2S+1=3; triplet Paramagnetic Oxygen O2 MO-diagram ½-½ S = Sms = 0 Exited state 2S+1=0; singlet Diamagnetic O2 O2- O22- O2 oxygen O2- superoxide O22- peroxide Bond order: 2 1.5 1 Has longer O-O bonds Chemical bonding – intermolecular forces Intermolecular forces Consider here molecules and forces acting between them. Also relevant for 1D-chain structures and 2D-layered structures Some such forces relevant for certain 3D regular structures Induced dipole forces [dispersion forces] Dipole – dipole interactions Ion – dipole interactions Hydrogen bonding as a special case Chemical bonding – intermolecular forces – 1D chain structure - example CrO3 1D-Ca3Co2O6 2D-LiCoO2 Quasi 2DLa2CoO4 3D-LaCoO3 Chemical bonding – intermolecular forces – 2D layer structure - example Layered double hydroxides Graphite (and h-BN) MoS2 Layered silicates Oxyhalides – FeOCl Layered Materials Perovskite related materials Metal halides MoCl2 – CrCl3 III-VI layered Semiconductors – GaSe Chemical bonding – intermolecular forces Dispersion forces Average electron density Instantaneous electron density giving a temporary dipole Continuous generation of instantaneous dipoles Approximation: Forces are proportional to number of electrons of atom Instantaneous attraction between two molecules And reversal of polarity in the next instant Physical consequence: Increasing mellting and Boiling point for molecules (in a given series) More complicated in reality Geometry is also parameter SF6 versus dekan C10H22 Tm: -51 oC versus -30 oC Chemical bonding – intermolecular forces - example Melting point – structure covalent molecules At room temperature: 9 Colorless gas -219°C 17 Yellow gas -101°C 35 Brown liquid F Cl Br I Tm 53 At 85 Structure -7°C Lustreous solid *sublimes Metalic +114°C* +302oC Increasing strength of induced dipoles F2(s) Cl2(s) Br2(s) I2(s) Molecular; X2 two atomic molecules Only weak dispersion forces 61 Chemical bonding – intermolecular forces Dipole – dipole forces Molecules may have a permanent dipole moment Origin in electronegativity differences Will have shift in electron density; with positive and negative partial charges EXAMPLE: CO versus N2 The are isoelectronic molecules (14 electrons); But 5 K difference in both Tm and Tb Must consider dipole – dipole PLUS dispersion forces EXAMPLE: Tb for HBr is 206 K 36 electrons Tb for HCl is 188 K 18 electrons Stronger dispersion forces in HBr Permanent No permanent dipole dipole Canellation owing to symmetry Dominates over stronger Dipole – dipole forces in HCl. Chemical bonding – intermolecular forces - Hydrogen bonding H2O – water/ice 97 % of all water on earth is salt water. 2% is ice, mainly in Antarktica 100 Importance of hydrogen bonding for melting and boling point 60 40 o Temperatur ( ) Hydrogen bonding Mainly electrostatic component -O-H OLow el.density shared ONLY for hydrogen in combination with the most electronegative elements; F, O, (N),.. ANOMALY for H2O 80 20 0 Trend: Dispersion forcesr dominant -20 -40 -60 -80 -100 0 6 H2O2 H2S4 H2Se H82Te 10 X Axis Title 63 Chemical bonding – intermolecular forces - Hydrogen bonding H2O – dihydrogenoxide… In solid state: The O-atom of H2O has tetrahedral surroundings of H-atoms (corresponding to O-lone pairs) In liquid state: short range correlations Hydrogen bonds 64 Chemical bonding – intermolecular forces QUESTIONS Consider the variation in boling point of H2X (X = O, S, Se, Te) How do you expect that this compares with (a) The series HX; X = F, Cl, Br, I (b) The series XH4; X = C, Si, Ge, Sn, P Make skematic drawings Chemical bonding – ionic bonding NOT USED Ionic radius The ionic radius is not a fixed property of a given ion, but varies with: - coordination number (increases with increasing CN) - spin state (HS ion larger than LS ion) Ionic radii are sufficiently transferable to allow periodic trends to be recognized: s- and p-block: radius increases with Z for any vertical group s d Poorer shielding p Isoelectronic series of cations, radius decreases with increasing charge: Na+, Mg2+, Al3+ and Si4+ Cation radius decreases with increasing oxidation state: V2+, V3+, V4+, V5+ Lanthanide contraction and d-element contraction due to poorer shielding (comparing ions with same charge) of d- and f-electrons Chemical bonding – ionic bonding – ionic radii NOT USED A major review of high quality crystallographic data, led to the publication of a revised set of ionic radii in 19761. These values are today the preferred once. Li+ F- F- Li+ Electron density contour map of LiF Variation in electron density along the connecting line between Li and F nuclei in LiF. P = Pauling radius of Li+; G = Goldschmidt radius; M = minimum in electron density; Pauling's reference of rion(O2−) = 140 pm still in use (in Shannon referred to as crystal radius “CR”) Shannon: value as reference of oxide anion is rion(O2−) = 126 pm (“IR”) 1: Shannon R.D. Acta Cryst. A32 751-767 (1976) – reference is avaiable on Fronter. NOT USED Chemical bonding – ionic bonding Characteristics of ionic bonding: - Non-directional Ions have as high coordination number as possible ideally: charged, non-compressible, non-polarizable spheres Lattice energy for NaCl: Energy needed to break NaCl(s) Na+(g) + Cl(g) 1) Long range electrostatic attractive and repulsive forces: Cl Na Na 2) Short range repulsive forces due to overlap of electron clouds 1) long range electrostatic forces: Electrostatic energy of a pair of monovalent Ions such as Na+ and Cl: Ee e e 40 r e2 40 r NOT USED Chemical bonding – ionic bonding Lattic energy - Ionic structures Ee e e 40 r e2 40 r r Opposite charges attract each other, same charges repell each other Electrostatic energy of a 3D lattice of cations and anions depends on atomic arrangement = the geometry (expressed via the Madelung constant, ) e2 2 2 e Geometry ionic charge N Ee Z A 4 r 0 4 0 r Madelung constant is used to calculate the effective electrostatic potential energy with basis in a particular crystal structure. The ions are treated as point charges. NOT USED Chemical bonding – ionic bonding NaCl 3D-periodic atom arrangement 1., 2., 3., …n.,… coordination sphere 1) Na+ is surrounded by 6 Cl 2 6 ( Z )( Z ) e 1 E r 4 0 1 + + 2) Na surrounded by 12 next neighbour Na at √2r: E 4 0 3) Na+ surrounded again by 8 ( Z )(Z )e 2 E 4 0 r Cl at √3r: 12 8 6 6 .... 2 3 4 1 E 4 0 12( Z )(Z )e 2 2r 8( Z )( Z )e 2 3r A slowly converging series Madelung constant = NOT USED Chemical bonding – ionic bonding Reduced Madelung constant MmXn N A * Z 2 e 2 Ee 4 0 r N A e 2 mn Z M Z X Ee 2 4 0 r Madelung constants Structure type Rock salt, NaCl CsCl Wurtzite, ZnS Sphalerite, ZnS Fluorite, CaF2 Rutile, TiO2 Maintains charge neutrality mZM = nZX * 1.748 1.763 1.641 1.638 2.520 2.408 Reduced Madelung constants, Structure type Rock salt CsCl Wurtzite Sphalerite Fluorite Rutile M+XM+XM2+X2M2+X2M2+X2M4+X22- 1.748 1.763 1.641 1.638 1.68 1.60 Chemical bonding – ionic bonding NOT USED 2) short range repulsive forces due to overlap of electron clouds Short range repulsive potential energy, Er = B/rn where B and n are constants n is extracted from compressibility measurements NOT USED Chemical bonding – ionic bonding NA * Z 2 e 2 UL Ee Er 4 0 r NAB n r Long range electrostatic forces Born repulsive term Lattice energy at equilibrium separation between ions, r0 N A * e 2 Z 2 UL 2 4 r 0 0 1 1 n Chemical bonding – ionic bonding - example NOT USED Melting point ( Z )( Z )e 2 A Lattice energy is proportional toV r A = Madelung constant [depends on the 3D geometric distribution of anions and cations] r = M-X bond distance Consider KF, KCl, KBr and KI. How do expect Tm to vary? M-X distance depends on size of X anion Lattice energt will reduce from KF to KI (1/r dependency) KF: Tm = 857oC; while for KI Tm = 685oC Chemical bonding – ionic bonding Ionic versus covalent No clear border….. NOT USED Chemical bonding – energies – bonding type Comparison of typical bond energies for different types of bonds NOTE: differences between compounds may be quite significant Type kJ/Mole Species involved Covalent 200-350 Atoms with shared electrons Ionic 250 Ions Metallic 200 Metal atoms Ion-dipole 15 Ions and polar molecules Dipole-dipole 2 Stationary polar molecules Dipole-dipole 0.3 Rotating polar molecules Dispersion 2 All atoms and molecules Hydrogen bond 20 N,O,F in combiantion with H Chemical bonding – binding energies – some comparisons Binding energy kJ/mole C-C 346 Si - Si C-O 358 Si - O 222 452 Consequences: Carbon forms easily C-C chains organic chemistry and chemistry of life! Silicon forms oxides; silicates; the main constituent of the earth crust N N 941 kJ/mol P P 481 kJ/mol N N 163 kJ/mol P P 200 kJ/mol N O 201 kJ/mol P O 335 kJ/mol Concequences: N2 extremely stable (trippel bond; cf. Its MO-scheme) Formation of nitrogen oxides is endothermic Several chemical reactions with nitrogen becomes «unusual» Phosphates (P-O based compounds) are stable No multiple bonds for phosphorus Chemical bonding – stability of binary oxides Enthalpies of formation - oxides CO CO2 N2O NO NO2 SO2 SO3 DHof = -110.5 kJ/mole DHof = -393.5 kJ/mole DHof = 82.1 kJ/mole DHof = 90.3 kJ/mole DHof = 33.2 kJ/mole DHof = -296.8 kJ/mole DHof = -395.7 kJ/mole 78 Chemical bonding – stability of binary oxides Differences in electronegativity gives different reaction pathways NCl3(l) + 3H2O(l) NH3(g) + 3HClO(aq) PCl3(l) + 3H2O(l) H3PO3(aq) + 3HCl(aq) Differences in stability of binary oxides gives different behavior on heating in air/oxygen N2H4(g) + O2(g) N2(g) + 2H2O(g) C2H4(g) + 3O2(g) 2CO2(g) + 2H2O(g) 79 Chemical bonding – reactivity 3.04 3.44 3.16 2.20 NCl3(l) + 3H2O(l) NH3(g) + 3HClO(aq) NCl3 PCl3 PCl3(l) + 3H2O(l) H3PO3(aq) + 3HCl(aq) 2.19 3.44 2.20 3.16 80
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