1/29/2015 Chapter Outline 9.1 9.2 9.3 9.4 9.5 9.6 9.7 Energy as a Reactant or a Product Transferring Heat and Doing Work Enthalpy and Enthalpy Changes Heating Curves and Heat Capacity Heats of Reaction and Calorimetry Hess’s Law and Standard Heats of Reaction Heats of Reaction from Heats of Formation and Bond Energies 9.8 More Applications of Thermochemistry Isolated, Closed and Open Systems open systems can exchange mass and energy closed systems can only exchange energy isolated systems can not exchange mass or energy 1 1/29/2015 Exothermic and Endothermic Processes • Exothermic process: Heat flows out of the system to surroundings (q < 0). • Endothermic process: Heat flows into the system from surroundings (q > 0). Pressure-Volume (P-V) Work E = q + w “internal energy” Heat flow Work (F x d) E > 0 when heat flows in (q > 0) or work is performed on the system (w > 0) E < 0 when heat flows out (q < 0) or work is performed on the surroundings (w < 0) 2 1/29/2015 (a) Intake – air and fuel enters the cylinder (b) Compression – heats up reaction mixture and ignites (q > 0, w > 0, E > 0) (c) Power Stroke (expansion) – combustion products perform work on the surroundings (q < 0, w < 0, E < 0) (d) Exhaust Example of P-V Work, p. 368-369 Work = P x V where V = Vf - Vi and P = F A Remember that energy (in Joules) is the capacity to do work, so P x V has to have the same units as energy. Units of a Joule = Newton x meters = Units of P = kg m2 s2 Newton kgm/s2 kg/s2 = = m m2 m2 Units: P x V = kg/s2 kg m2 x m3 = = Joules m s2 So E = q + w = q - PV There’s a minus sign because when when V > 0, then system does work on the surroundings (w < 0) 3 1/29/2015 Sample Exercise 9.2: Calculating P-V Work A tank of compressed helium is used to inflate 100 balloons for sale at a carnival on a day when the atmospheric pressure is 1.01 atm. If each balloon is inflated with 4.8 L, how much P-V work is done by the compressed helium? Express your answer in Joules. w = -PV P = 1.01 atm Conversion factor: L x atm = 101.325 J V = Vf - Vi = 4.8L – 0 = 4.8L w = - 1.01 atm x 4.8L x 100 balloons x 101.325 J balloon Latm = - 4.9 x 104 J = - 49 kJ Sample Exercise 9.3: Relating E, q, and w The racing cars in the figure are powered by V8 engines in which the motion of each piston in its cylinder displaces a volume of 0.733 L. If combustion of the mixture of gasoline vapor and air in one cylinder releases -1.68 kJ of energy, and if 33% of the energy does P-V work, how much pressure, on average, does the combustion reaction mixture exert on each piston? How much heat flows from the reaction mixture to its surroundings? V = 33% 0.733 L Plan: E -PV P From E = q - PV q 4
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