2. LIMITS AND CONTINUITY 63 sin(x2 + y 2) Example. Find lim . x2 + y 2 (x,y)!(0,0) We use polar coordinates to find the indicated limit, if it exists. Note that (x, y) ! (0, 0) is equivalent to r ! 0. We have sin(x2 + y 2) sin(r2) lim = lim = (by l’Hopitals”s rule) r!0 x2 + y 2 r2 (x,y)!(0,0) 2r cos(r2) lim = lim cos(r2) = cos 0 = 1. r!0 r!0 2r sin(x2 + y 2) Thus lim = 1. x2 + y 2 (x,y)!(0,0) Continuity Definition. Suppose f (x, y) is defined in the interior of a circle centered at (a, b). We say f is continuous at (a, b) if lim (x,y)!(a,b) f (x, y) = f (a, b). If f (x, y) is not continuous at (a, b), then we call (a, b) a discontinuity of f . Definition. (1) An open disk is the interior of a circle, i.e., all points inside but not on the circle.
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