SAT Practice
- when multiplying with the same base,
add the exponents
(2x)y(2x)2y – (2x)y(1) {used distributive property}
= (2x)3y – (2x)y {added the exponents when multiplying}
© Mr. Sims
SAT Practice
List numbers ending in 9 and their factors.
Stop when a set of possible 1st and 3rd
consecutive integers appear as factors:
9
(1 x 9)
19
(1 x 19)
29
(1 x 29)
39
(1 X 39 and 3 x 13}
49
(1 x 49 and 7 x 7}
59
(1 x 59)
69
(1 x 69 and 3 x 23)
79
(1 x 79)
89
(1 x 89)
99
(1 x 99 and 3 x 33 and 9 x 11)
9, 10, and 11 are consecutive integers, where:
- the units (ones) digit of the product of 9 and 11 is 9
- the units (ones) digit of 10 is 0.
© Mr. Sims
SAT Practice
4, 11, 18,…. {common difference of 7}
4th = 18 + 7 = 25
5th = 25 + 7 = 32
6th = 32 + 7 = 39
7th = 39 + 7 = 46
8th = 46 + 7 = 53
9th = 53 + 7 = 60
10th = 60 + 7 = 67
11th = 67 + 7 = 74
12th = 74 + 7 = 81
© Mr. Sims
SAT Practice
(x – 2)2 = 49
(x – 2)(x – 2) = 49 {when squaring a binomial, multiply it by itself}
x2 – 4x + 4 = 49 {used foil method}
-49
-49
x2 – 4x – 45 = 0 {subtracted 49 from each side}
(x – 9)(x + 5) = 0 {factored into two binomials}
x – 9 = 0 or x + 5 = 0 {set each factor equal to 0}
+9
+9
-5
x = 9 or x = -5
-5
{solved each equation for x}
© Mr. Sims
SAT Practice
To find average:
- add the terms together and divide by the number of terms
t+y
= 15
2
{average is 15}
w+x
= 15
2
t + y = 30
{multiplied each side by 2}
w + x = 30
t + y + w + x = 60
{added the two equations together}
t+y+w+x
4
=
60
{divided each side by 4}
4
t+w+x+y
4
= 𝟏𝟓
{reduced}
© Mr. Sims
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