Quiz Review - 8.1 to 8.3
Algebra I 300
Name:
Date:
**When you complete this review, check your answers on my website. Then go back and study
your notes!!!
Type of Problem
Strategy
Determine if the following points are on
Plug in the corresponding values for “x”
the given line
and “y” into the equation. If the resulting
equation is true, then the (x, y) is a point on
1) x – y = 5
(9, 4) (7, 3)
the line.
Put the following equation in “y = “ form.
1) 3x + 4y = 12
Solve for y and graph:
Manipulate the original equation so that
you isolate “y” on one side of the equals
sign.
Step 1: Solve the equation for y.
1) 2x – 3y = 6
Step 2:
Plot “b” (the y – intercept), then
rise
use the slope as
to get the rest of the
run
points.
Step 3:
Calculate the slope of the line containing
the two points below.
1. (-1, 3), (2, 4)
Calculate the slope of the following line
2x – 3y = 6
Horizontal Lines
Vertical Lines
Find the x- and y-intercepts for the
equation 3x – y = 6 and graph
Connect points w/ straight line.

y
rise
change
in
yy
2
1


Slope = run
change
in
xx

x
2
1
Step 1: Solve the equation for y.
Step 2: Make a table of values and
substitute the values in for x to find y. (At
least 3 points)
Step 3: Determine slope by using the
slope formula
y = some number AND slope = 0
x = some number AND slope = undefined
x-intercept: point where the graph
crosses the x-axis. To find the x-intercept,
let y = 0 and solve for x
y-intercept: point where the graph
crosses the y-axis. To find the y-intercept,
let x = 0 and solve for y
Determine the equation of a line with a
slope of -2 and a y-intercept of 7
Use y = mx + b
Plug in the slope for m and the y-int for b
Quiz Review - 8.1 to 8.3
Algebra I 300
Name:
Date:
Determine the equation of a line with a
slope of -3/4 passing through the point (-8,
11)
Use point – slope form y  y1  m( x  x1 )
- Plug in the slope for m, and the given
point for x1, y1.
- Distribute the m.
- Isolate y (put in y = form)
Determine the equation of a line passing
through the points (-3, 5) and (3, 1)
- Find Slope (m) first using slope formula.
- Then use the slope and one of the points
(either point) in point – slope form.
- Continue as above.
Sample Problems
Determine if the following points are on the given line.
1. 5x + 2y = 23
(3, 4) (-3, 19)
2.
(Emerging Level)
3y – 2x = 13
(-2, 3) (-1, 5)
Calculate the slope of the line containing the two points below.
3. (-1, 3), (2, 4)
(Emerging Level)
4. (2, -5) (-3, -10)
Put the following equation in “y = “ form. Then state the slope and the y-intercept. (Proficient Level)
5. 2x – 3y = 6
6. y – 6 = 0
7. 2x + 5y = 10
8. 5x – 3y = -5
Quiz Review - 8.1 to 8.3
Algebra I 300
Name:
Date:
Solve for y and graph:
9.
(Mastery Level)
y
2x – 3y = 6
x
10.
4x = 2y - 8
y
x
Find the x- and y-intercepts for the following equations and graph
11.
4x – 2y = 8
(Mastery Level)
y
x
12.
3x = 6y - 12
y
x
Quiz Review - 8.1 to 8.3
Algebra I 300
Name:
Date:
Directions: Find the equation of a line in slope – intercept form (where possible) with the given
characteristics:
(Emerging Level)
3
13. slope = ; y-intercept = -4.
14. Slope = -1; y-intercept = 8
5
(Proficient Level)
1
15. slope =  ; passing through (-9, 5)
3
16. Slope =
3
; passing through (8, -3)
2
(Mastery Level)
17. Passing through (-4, -3) & (4, -1)
18. Passing through (-2, 2) & (-1, -1)
19. Vertical through the point (2, -6)
20. Horizontal through the point (2, -6)
21. Line with an x – intercept of -4 and a y – intercept of 9.