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UNIT-XIII.ORGANIC COMPOUNDS CONTAINING NITROGEN
SUB TOPIC – I: AMINES INTRODUCTIO
1.
Which of the following statements is wrong?
I) amines possess pyramidal shape
II) Amines act as Bronsted bases
III) 10 amines show metamerism
IV) 20 amines show metamerism
1) I, II and III
2.
3.
4.
2) II, III and IV
3) III only
4) I, II and IV
N, N-dimethyl butanamine-2 contains
1) sixsp3hybridised carbon atoms
2) seven sp3hybridised atoms
3) twosp3hybridised nitrogen atoms
4) 1 and 2 are correct
Primary amino group is absent in
1) p-amino phenol
2) o-amino phenol
3) N-methyl ethanamine
4) phenyl amine
A): n-propyl amine is 10 but isopropyl amine is 20 amine
R): n-propyl amine and isopropyl amine are position isomers
1) A and R are true and R explains A
2) A and R are true but R does not explain A
3) A is true but R is false
5.
6.
N, N-dimethyl butanamine-2 is the functional isomer of
1) N–butanamine–2
2) N-methyl-2-ethyl butanamine-2
3) trimethyl amine
4) triethyl amine
n-butyl amine and isobutyl amine are ---- isomers
1) optical
7.
2) functional
3) chain
4) position
How many isomers with the molecular formula C4H11N.
1) 1
8.
4) A is false and R is true
C3 H 9 N
2) 2
3) 3
4) 4
(b) Secondary amine
(c) Tertiary amine
(d) All of these
Represents
(a) Primary amine
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9.
How many primary amines are possible for the formula C4 H11 N
(a) 5
(b) 6
(c) 3
(d) 4
KEY
1)
4
2) 1
3) 3
4) 4
5) 4
6) 3
7) 4
8) 4
9) 4
SUBTOPIC – II: NITRO BENZENE
1.
⎯→ HydrazoBenzene. Here the reagent is
NitroBenzene ⎯
1) Sn + HCl
2.
In the reaction
1) M
3.
2) Zn + NH4Cl
3) Zn + NaOH
4) LiAlH4
the equivalent weight of Nitrobenzene is
M
2) 2
M
3) 4
M
4) 6
O
||
R − N → O and R-O-N = O are a pair of
1) Chain Isomers
2) Metamers
3) Functional Isomers
4) Epimers
Here the reagent is
4.
1) Zn + NH4Cl
2) Zn + NaOH
3) Sn + HCl
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4) LiAlH4
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NO2
Azobenzene
N
Hydrazobenzene
NH
5.
N
NH
The ratio of the number of moles of Hydrogen atoms required to get 1 mole of azobenzene
and 1 mole of hydrazobenzene
1) 4 : 5
8.
9.
3) 1 : 1
4) 2 : 3
H SO conc.
⎯⎯2⎯ ⎯4⎯ ⎯
⎯→
0C
100
+ HNO3(conc)
the main product of the reaction
6.
7.
2) 5 : 4
1) Aniline
2) O – dinitrobenzene
3) m – dinitrobenzene
4) P – dinitrobenzene
Nitrobenzene is reduced by Zn and alcoholic KOH
1) C6H5NH2
2) C6H5NH-NH C6H5
3) C6H5 - N = N - C6H5
4) C6H5 - NH - CO - C6H5
Nitro benzene on reduction with Zinc and NH4Cl gives
1) Azo benzene
2) Aniline
3) Hydrazo benzene
4) N- Phenyl hydroxyl amine
The structure of the compound formed when Nitrobenzene is reduced by lithium
aluminium hydride (Li AlH4)
NH
NH
1)
NHOH
2)
NH 2
3)
4)
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N=N
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10.
Nitro benzene undergoes reduction with Zn/ alcoholic KOH to from a compound 'A'. The
numbers of sigma and Pi bonds in ‘A’ respectively are
1) 17,6
2) 27,6
3) 27,8
4) 17,8
KEY
1)3
2) 4
3) 3
4) 3
5) 1
6) 3
7) 2
8) 4
9) 4
10) 2
SUBTOPIC – III: ANILINE
1.
can react with a maximum of ........... moles of CH3I
1) 4
2.
2) 3
3) 2
In the nitration of aniline the amino group is protected by conversion into
1) Tribromo derivative 2) Isocyanide
3.
4.
4) 1
3) Diazonium salt
4) Acetyl derivative
The following turns brown on exposure to air and light
1) Nitrobenzene
2) m-dinitrobenzene
3) Aniline
4) Benzene diazonium chloride
In the preparation of N-phenyl benzene sulphonamide from aniline, the reagent used is
1) H2SO4
2) SOCl2
3) C6H5Cl
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4) C6H5SO2Cl
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5.
Which of the following is correct with respect to the order of basic natures of different
amines given below?
6.
(
)
1)
C6H5NH2 > NH3 > CH3NH2 > CH3 2 NH
2)
(CH3 )2 NH>CH3NH2 >C6H5NH2 >NH3
3)
CH3NH2 > CH3 NH > C6H5NH2 > NH3
2
4)
(CH3 )2 NH > CH3NH2 > NH3 > C6H5NH2
(
)
Which of the following methods is used to prepare Aniline on large scale?
Fe H 3O +
⎯→ C H NH + 2H O
A) C6H5NO2 + 6(H) ⎯⎯ ⎯ ⎯ ⎯
6 5 2
2
Sn HCl
B) C6H5NO2 + 6(H) ⎯⎯ ⎯ ⎯→ C6H5NH2 + 2H2O
ZnCl2
⎯⎯ ⎯⎯
→
0C
300
C) C6H5OH2+NH3
C6H5NH2+H2O
D) C6H5Cl + 2NH3
1) A only
7.
C6H5NH2 + NH4Cl
2) B or C
3) C only
4) A or D
Aniline is not the major Product in one of the following reaction. Identify that reaction
1) C6H5-OH + NH3
Zncl
300 c
2
⎯⎯⎯
⎯
→
0
alcoholic KOH
2) C6H5NO2 + Zn Powder
⎯⎯⎯⎯⎯⎯⎯
→
200 0
Cu2O high pressure
⎯⎯⎯⎯⎯⎯⎯⎯
→
3) C6H5Cl+ NH3
Hcl
4) C6H5NO2 + Fe + H2O
⎯⎯⎯
→
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8.
Which of the following is obtained in a Carbyl amine reaction?
1) C6H5NH2
9.
10.
12.
13.
2) C6H5NO2 + Zn/NH4Cl
3) C6H5NO2 + Li Al H4
4) C6H5NO2 + Zn/HCl
Most basic among the following is
2) aniline
3) Nitro benzene
4) N-acetyl aniline
18.
1) It is less basic than ethyl amine
2) it is steam volatile
3) On reaction with Na, it gives H2
4) it is highly soluble in water
On reduction, primary amine is formed by
2) ethyl nitrite
3)azo benzene
4) ethyl carbyl amine
Carbyl amine reaction is answered by
2) nitro methane
3) acetamide
4) trimethyl amine
3) glycine
4) both 2 and 3
Zwitter ion is formed by
2) sulphanilic acid
Benzamide can be converted into aniline by the action of
2) Br2/water
3) Br2/KOH
4) Br2/red P
The process that does not yield an amine is
1) action of ammonia on RX
2) reduction of aldoxime with Na/alcohol
3) acid hydrolysis of alkyl cyanide
4) reduction of amide with LAH
Among different aliphatic amines, correct order of basic strengths in vapour state is
1) 30>20>10
19.
4) p-nitro aniline
In-correct statement about aniline is
1) Br2/CCl4
17.
3) acetanilide
1) Aniline hydro chloride
1) Aniline
16.
2) aniline
Most reactive towards electrophillic substitution is
1) Methanamine
15.
4) C6H5NC
1) C6H5NO2 + Zn/KOH
1) 1-nitro ethane
14.
3) C6H5CN
Which of the following reaction can produce aniline as the main product
1) Benzyl amine
11.
2) COCl2
2) 10 >20>30
3) 20>10>30
4) 30>10>20
Conversion of a primary amide into a primary amine is called
1) Gabriel’s pthalimide reaction
2) Hoffmann bromamide reaction
3) Carbyl amine reaction
4) Hinsberg’s reaction
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20.
21.
Ethanamine can be obtained from methyl iodide by the action of alc.KCN followed by
1) Hydrolysis
2) oxidation
3) Reduction
4) action of NH3/heat
The following amide does not undergo Hoffmann’s degradation
A) Propionamide
B) N-methyl butanamide
C) Butanamide
D) N,N-dimethyl butanamide
1) D only
22.
2) C only
3) C and D
4) B and D
In-correct statement among the following is
I) LiAlH4 can reduce an amide into amine without change in the number of carbon atoms
II) a primary amide can be reduced to a primary amine by Br2/KOH with same number of
Carbon
III) a primary amide can be reduced to a primary amine by LiAlH4 with (n-1) carbon
atoms
IV) Hoffmann’s bromamide reaction is useful to prepare aniline from Benzamide.
1) II only
23.
24.
25.
28.
4) II and III
1) N-methyl ethanamine
2) N, N-dimethyl ethanamine
3) ethanamine
4) trimethyl amine
Most reactive towards electrophillic substitution is
1) Aniline hydro chloride
2) aniline
3) Nitro benzene
4) N-acetyl aniline
On reduction, primary amine is formed by
2) ethyl nitrite
3) azo benzene
4) ethyl carbyl amine
Butanone oxime on reduction with Na/C2H5OH gives
1) 30 amine
27.
3) III and IV
N,N-dimethyl ethanamide on reduction with LiAlH4 gives
1) 1-nitro ethane
26.
2) I only
2) 10 amine
3) 20 amine
4) 10 amide
Which of the following groups will increase basic strength of aniline?
1) -NO2 in ortho or para
2) -CHO in ortho or para
3) -SO3H in ortho or para
4) -OH in ortho or para
Aniline gives meta derivative as major product with
1) CH3COCl/pyridine 2) HNO3+H2SO4
3) Br2/water
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4) CH3Cl/pyridine
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29.
30.
Bromination of aniline in acid medium results ------ as major product
1) 2,4,6-tri bromo aniline
2) 3-bromo aniline
3) 2-bromo aniline
4) 4-bromo aniline
Ethyl amine can be distinguished from Aniline by
1) Tollen’s reagent
31.
2) Schiff’s reagent
3) Azo dye test
4) Carbylamine test
A mixture of three amines A,B and C is treated with Benzene sulphonyl chloride and
filtered.
B is obtained in the filtrate. The mixture containing A and C is treated with KOH so that A
becomes soluble while C does not. Now, A, B and C are
32.
1) aliphatic primary, secondary and tertiary
2) aliphatic secondary, tertiary and primary
3) aliphatic primary, tertiary and secondary
4) aliphatic tertiary, secondary and primary
Which of the following on Hoffmann’s bromamide reaction gives alkanamine?
1) RCH2NH2
33.
34.
2) RCONHR’
3) RCONH2
4) RCOONH4
Dye test is used to distinguish
1) ethanamine and methanamine
2) methanamine and propanamine-1
3) benzenamine and ethanamine
4) urea and acetanilide
Aniline is
1) More basic than ammonia
2) more basic than p-amino phenol
3) More basic than p-nitro aniline
4) as basic as methyl amine
35. Acetanilide on nitration followed by hydrolysis yields --- as main product.
1) 4-nitro aniline
36.
4) 3-nitro aniline
Among the following, strongest base is
1) aniline
37.
2) 2,4,6-trinitro aniline 3) 2-nitro aniline
2) p-nitro aniline
3) m-nitro aniline
4) benzyl amine
The compound which on reaction with aqueous nitrous acid at low temperature produces
in oily nitrosamine is
(a) Methylamine
38.
(b) Ethylamine
(c) Diethylamine
(d) Triethylamine
Acetamide is treated separately with the following reagents. Which one of these would give
methylamine?
(a) PCl5
(b) Sodalime
(c) NaOH+Br2
(d) hot concentrated H2SO4
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39.
Carbylamine test is performed in alcoholic KOH by heating a mixture of
(a) Chloroform and silver powder
(b) Trihalogenated methane and a primaryamine
(c) An alkyl halide and a primart amine.
40.
(d) An alkyl cyanide and a primary amine.
Chlorobenzene can be prepared by reacting aniline with
(a) Hydrochloric acid
(b) Cuprous chloride
(c) Chlorine in the presence of anhydrous aluminium chloride.
(d) Nitrous acid followed by heating with cuprous chloride.
41.
Amongst the following, the most basic compound is
(a) Benzylamine
42.
(b) aniline
(c) Acetanilide
(d) p-nitroaniline
Reaction of RCONH2 with a mixture of Br2 and KOH gives RNH2 as the main product.
The intermediates involved in the reaction are
O
||
(a)
R − C − NHBr
(b) R − NHBr
O
||
R − C− N
(c) R − C ≡ N
43.
(d)
Br
Br
Examine the following two structures for the anilinium ion and chose the correct statement
from the ones gives below.
+ NH3
NH3
(a) II is not acceptable canonical structure because carbonium ions less stable than ammonium
ions
(b) II is not an acceptable canonical structure becasue it is nonaromatic
(c) II is not an acceptable canonical structure because nitrogen has 10 valence electrons
(d) II is an acceptable canonical structure
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44.
Which of the following statement is not correct?
(a) Replacement of halogen by NH2 in alkyl halide is a nucleophilic substitution reaction
(b) Aryl halides show more reactivity as compared to alkyl halides in the replacements of
halogen by NH2 group
(c) During the replacement of halogen by NH2 group, ammonia is taken in large excess so as to
avoid the formation of 20 and 30 amines.
(d) Tertiary alkyl halide generally produces alkene instead of the replacement of halogen by
NH2 group.
45.
Which of the following statements is not correct?
(a) Primary amines show intermolecular hydrogen bonding
(b) Secondary amines shows intermolecular hydrogen bonding.
(c) Tertiary amines show intermolecular hydrogen bonding.
(d) Amines have lower boiling points as compared to those of alcohols and carboxylic acids of
comparable.
46.
Which of the following statements is not correct?
(a) Aliphatic amines are stronger bases than ammonia.
(b) Aromatic amines are stronger bases than ammonia
(c) The alkyl group in alkyl ammonium ion more stabilizes the ion relative to the amine
(d) The aryl group in aryl ammonium ion less stabilizes the ion relative to the amine.
47.
48.
Hinsberg’s reagent is
(a) Phenylisocyanide
(b) Benzenesulphonyl chloride
(c) p-toluenesulphonic acid
(d) O-dichlorobenzene
On warming an aqueous solution of benzenediazonium chloride, the product obtained is
(a) Benzene
49.
(c) Phenol
(d) amide
Which of the following reagents can convert benzenediazonium chloride into benzene?
(a) Water
50.
(b) Aniline
(b) Acid
(c) Hypophosphorous acid (d) HCl
Hofmann’s method to separate amines in a mixture uses the reagent?
(a) Benzenesulphonyl chloride
(b) Diethyl oxalate
(c) Benzeneisocyanide
(d) P-toluenesulphonic acid
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51.
Which of the following compounds will dissolve in an alkali solution after it has undergone
reaction with Hinsberg reagent?
CH3 − N − C6H5
(C 2 H 5 ) 2 NH
(a)
(b)
CH3 NH 2
(d)
(c)
52.
C6 H 5 NHC6 H 5
Activation of benzene ring by-NH2 in aniline can be reduced by treating with
(a) Dilute HCl
53.
|
CH3
Which of
(b) Ethyl alcohol
(c) Acetic acid
(d) Acetyl chloride
the following orders is correct regarding the basic strength of substituted
aniline
(a) P- nitroaniline> P-aminobenzaldehyde> P-bromoaniline
(b) P-nitroaniline<P-bromoaniline< P- aminobenzaldehyde
(c) P- Nitroaniline< P - aminobenzaldehyde< P - bromoaniline
(d) P - Nitroaniline>P - aminobenzaldehyde< P - bromoaniline
54.
Which of the following orders regarding the basic strength
of substituted aniline is
correct?
(a) P-methylaniline> P-chloroaniline> P- aminoacetophenone
(b)P-methylaniline P- aminoacetophenone> P- chloroaniline
(c) P-aminoacetophenone>P-methylaniline> P - chloroaniline
(d) P-aminoacetophenone>P-chloroaniline> P- methylaniline
55.
The number of resonating structures of arylammonium ion is
(a) 2
56.
58.
(c) 4
(d) 5
The number of resonating structures of aniline is
(a) 2
57.
(b) 3
(b) 3
(c) 4
(d) 5
The bromination of aniline produces
(a) 2- bromoaniline
(b) 4-bromoaniline
(c) 2, 4, 6-tribromoaniline
(d) 2, 6-dibromoaniline
A positive carbylamine test is given by
(a) N, N-dimethylaniline
(b) 2, 4-dimethylaniline
(c) N-methyl1-o-methylaniline
(d) P- methylbenzylamine
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59.
60.
Among the following, the strongest base is
(a)
C6 H5 NH 2
(b)
P − NO 2C6 H 4 NH 2
(c)
m − NO 2C6 H 4 NH 2
(d)
C6 H5CH 2 NH 2
Identify the product C in the given reaction.
Na /C H OH
Cu /3000 C
HNO
2 5
2 → B ⎯⎯⎯⎯⎯
CH3 − C ≡ N ⎯⎯⎯⎯⎯⎯
→ A ⎯⎯⎯⎯
→C
61.
(a)
CH 3 − COOH
(b)
CH 3 − CH 2 − NH − OH
(c)
CH3 − CONH 2
(d)
CH 3 − CH = O
What is the product when
C6 H5 − CH 2 − NH 2 reacts with nitrous acid ?
+
⊕
C H − N ≡ N (b) C6 H5 − CH 2 − N ≡ N
(a) 6 5
(c)
62.
C6 H5 − CH 2 − OH
(a)
O
||
O
||
− C− O − C−
(b)
− O − C− R
(c)
(d) -CH = O
C H − N H − CH3
(a) 6 5
(b)
C6 H 5 − N H − C6 H 5
CH3 − CONH 2
(d)
C6 H5 − CH 2 − NH 2
(c)
Strongest base among the following is
NH 2
(a)
65.
−C≡ N
Which of the following having highest value of Kb ?
••
64.
C6 H 5 − NH 2
Which of the following is activating group for nitration reaction ?
O
||
63.
(d)
NH
(b)
(c)
( CH2 )6 N4
(d)
( CH3 )3 N
Identify the product C in the given reaction
Na /C2H5OH
HNO3
Cal/300°C
CH3 − C ≡ N ⎯⎯⎯⎯⎯⎯⎯
→ A ⎯⎯⎯⎯
→ B ⎯⎯⎯⎯⎯⎯
→C
(a) CH3 - COOH
(c) CH3 - CONH2
(b) CH3 - CH2 - NH - OH
(d) CH3 - CH = O
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66.
Column - I
Column - II
→ Azobenzene
(A) Nitrobenzene
(B) Aniline
→ Phenylisocyanide
(Q) NaNO2+ HCl+Cu2Cl2
(C) Aniline
→ Chlorobenzene
(R) CHCl3+KOH
(D) Ethylamine
67.
(P) LiAIH4
→ Ethanol
A
B
C
D
1)
P
Q
R
S
2)
P
R
Q
S
3)
S
R
Q
P
4)
P
R
S
Q
(S) NaNO2+ HCl (aq)
Which amine is heated with chloroform and alcoholic KOH, a bad odour compound is
formed. The compound is
(a) An alcohol
68.
CH 3 NCO
(c)
CH 3 NCS
(d)
CH 3CN
(b) Ethyl nitrite
(c) Ethyl alcohol
(b) Nitroethane
LiAlH 4
(d) Nitroethane
yields a secondary amine
(c) Methyl isocyanide (d) Acetamide
(b) Methane
(c)
CO2 + H 2O
(d) Acetic acid
Acetamide reacts with NaOBr in alkaline medium to form
(a)
73.
CH 3CNO
When methyl cyanide is hydrolysed in presence of alkali, it forms
(a) Acetamide
72.
(b)
Which one of the following on reduction with
(a) Methyl cyanide
71.
(d) An isocyanide
The product of the reaction of the alcoholic silver nitrite with ethyl bromide is
(a) Ethene
70.
(c) A cyanide
The molecular formula of methyl isocyanate is
(a)
69.
(b) An aldehyde
NH 3
(b)
CH 3 NH 2
(c)
CH 3CN
Treatment of ammonia with excess of ethyl chloride will yield
(a) Diethylamine
(b) Methylamine
(c) Tetraethyl ammonium chloride
(d) Ethane
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(d)
CH 3CH 2 NH 2
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74.
75.
76.
The correct order of the increasing basicity of methylamine, ammonia and aniline is
(a) Methylamine < aniline < ammonia
(b) Methylamine < ammonia < aniline
(c) Aniline < methylamine < ammonia
(d) Aniline < ammonia < methylamine
CH3NH2 +CHCl3 + 3 KOH → X + Y + 3 H2O ; compounds X and Y are
(a)
CH 3CN + 3KCl
(b)
CH 3 NC + 3KCl
(c)
CH 3CONH 2 + 3KCl
(d)
CH 3 NC + K 2CO3
In the following series of reactions, (A) is
(a)
77.
CH 3CN
(b)
CH 3 NC
( A) Re
duction ( B ) HNO2 C2 H 5OH
(c)
C2 H 5CN
(d)
CH 3 NO2
Ni / H 2
NaCN
Acetic anhydride
CH 3CH 2Cl ⎯⎯⎯
→( X ) ⎯⎯⎯
→(Y ) ⎯⎯⎯⎯⎯
→( Z )
(Z) in the above reaction sequence is
78.
(a)
CH 3CH 2CH 2 NHCOCH 3
(b)
CH 3CH 2CH 2 NH 2
(c)
CH 3CH 2CH 2CONHCH 3
(d)
CH 3CH 2CH 2CONHCOCH 3
A primary amine is formed from an amide, by the treatment of bromine and alkali. The
primary amine has
79.
(a) 1 carbon atom less than amide
(b) 1 carbon atom more than amide
(c) 1 hydrogen atom less than amide
(d) 1 hydrogen atom more than amide
Acetonitrile on reduction gives
(a) Propanamine
80.
81.
(b) Methanamine
(c) Ethanamine
(d) None of these
An isonitrile on reduction gives
(a) amine
(b) amine
(c) amine
(d) Quaternary ammonium salts
Ethyl chloride on heating with AgCN forms a compound (X). The functional isomer of
(X) is
(a)
82.
C2 H 5 NC
(b)
C2 H 5 NH 2
(c)
C2 H 5CN
(d) None of these
The reduction of which of the following compound would yield secondary amine
(a) Alkyl nitrile
(b) Carbylamine
(c) Primary amine
(d) Secondary nitro compound
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83.
CH 3 NH 2 + CHCl3 + KOH → nitrogen
containing compound + KCl+
H 2O
containing compound is
(a)
CH 3 − C ≡ N
(c)
CH 3
+
N ≡C
(b)
CH 3 − NH − CH 3
(d)
CH 3
+
N ≡C
KEY
1)
3
2) 4
3) 3
4) 4
11) 2
12) 4 13) 1 14) 1
21) 4
5) 4
6) 1
7) 2
8) 4
15) 4 16)3
17) 3
18) 1 19) 2
20) 3
22) 4 23) 2 24) 2
25) 1 26) 2
27) 4
28) 2 29) 2
30) 3
31) 3
32) 3 33) 3 34) 3
35) 1 36) 4
37) 3
38) 3 39) 2
40) 4
41) 1
42) 1 43) 3 44) 2
45) 3 46) 2
47) 2
48) 3 49) 3
50) 2
51) 3
52) 4 53) 3 54) 1
55) 1 56) 4
57) 3
58) 4 59) 4
60) 4
61) 3
62) 2 63) 4 64) 3
65) 4 66) 2
67) 4
68) 1 69) 4
70) 3
71) 4
72) 2 73) 3 74) 4
75) 2 76) 1
77) 1
78) 1 79) 3
80) 2
81) 3
82) 2 83) 4
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9) 4
10) 1
. Nitrogen
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SUBTOPIC – IV: DIAZONIUM SALTS
1.
Benzene diazonium chloride on reaction with KCN in the presence of CuCN yields X. X on
hydrolysis yields Y. Now, Y can also be obtained from
2.
3.
1) Toluene by the action of Cl2/FeCl3
2) Toluene by oxidation by KMnO4
3) Toluene by nitration
4) Toluene by sulphonation
2 SO4
Ar.N 2Cl ⎯dil
⎯. H⎯
⎯→ X + N 2 + HCl where regarding X, correct statement is
1) it is weakly acidic
2) it liberates H2 with Na
3) it is stronger acid than acetic acid
4) 1 and 2
Benzene diazonium salt on reduction with X yields Benzene. X is
1) K2Cr2O7/H+
4.
2) O3
3) H3PO4
4) H3PO2
A):Diazonium ion acts as an electrophile
R): Terminal nitrogen atom in diazo group is positively charged
1) A and R are true and R explains A 2) A and R are true but R does not explain A
3) A is true but R is false
5.
During diazo coupling, the following group is retained
1) N=N
6.
7.
8.
9.
4) A is false but R is true
2) N2Cl
3) NH2
4) NHR’
Which of the following is an example of electrophillic substitution?
1) diazotisation
2) Sandmayer reaction
3) diazo coupling
4) action of KCN on ArN2Cl
Which of the following is the correct order of ease of coupling with C6H5N2Cl?
A) Benzene
B) Nitro benzene
C) Phenol
D) Chloro benzene
1) A > D > B > C
2) C > A > B > D
3) C > A > D > B
4) B > D > A > C
Coupling of phenol with benzene diazonium salt yields
1) o-hydroxy derivative of salt
2) p-hydroxy derivative of salt
3) m-hydroxy derivative of salt
4) a mixture 1, 2 and 3
N, N-dimethyl aniline on coupling with C6H5N2Cl yields
1) 4-(N,N-dimethyl) amino azo benzene
3) 4-(N,N-dimethyl) amino azoxy benzene
2) 4-(N,N-dimethyl) nitroso benzene
4) 4-(N,N-dimethyl) amino hydrazo benzene
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10.
Which of the following reactions is an example of Sandmeyer reaction?
N 2+ HSO 4−
N 2+ HSO 4−
Br
CuBr
Cu powder
HBr
⎯⎯⎯→
⎯⎯⎯⎯⎯
→
(a)
(b)
N 2+ HSO 4−
N 2+ HSO 4−
I
KI
⎯⎯⎯→
(d)
(c)
Which of the following reaction is an example ofGattermann reaction?
N 2+ HSO 4−
N 2+ HSO 4−
Br
⎯⎯⎯⎯⎯
→
(b)
(a)
N 2+ HSO 4−
N 2+ HSO 4−
CN
CuCN
⎯⎯→
(d)
(c)
Benzenediazonium chloride on reaction with phenol in weakly basic medium gives
(a) Diphenyl ether
(b) P- hydroxyazobenzene
(c) Chlorobenzene
(d) Benzene
Which of the following is responsible for the colour of diazocompounds?
(a) Benzene ring
14.
I
KI
⎯⎯⎯→
13.
Br
Cu powder
HBr
CuBr
⎯⎯⎯→
12.
CN
CuCN
⎯⎯→
11.
Br
(b) -N = N-group
(c) -OH group
(d) -NH2 group
Coupling between arenediazoniumcation and amines takes place most rapidly at pH
(a) 10-14
(b) 0-2
(c) 5-7
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(d) 5-8
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N 2+ Cl− + CH3
OCH3 → A
15.
‘A’ is
OCH3
CH3
N
N=N
N
(a)
OCH3
(b)
CH3
N
OH
N
N
(c)
CH3
N
(d)
KEY
1)2
2) 4
3) 4
4) 3
5) 1
11) 2
12) 2 13) 2 14) 3
6) 3
7) 3
8) 2
9) 1
15) 2
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10) 1
OH