Finding the Radius of Convergence Use the ratio test to find the radius of convergence of the power series ∞ � xn . n n=1 Solution As Christine explained in recitation, to find the radius of a series � of convergence � ∞ n+1 � � � cn+1 x �. The value of x cn xn we apply the ratio test to find L = lim �� n→∞ cn xn � n=n0 for which L = 1 is the radius of convergence of the power series. In this case, cn+1 xn+1 cn xn xn+1 /(n + 1) xn /n n . x· n+1 = = Taking the limit of this as n goes to infinity, we get: � � � cn+1 xn+1 � � � L = lim � n→∞ cn xn � � � � n �� � = lim �x · n→∞ n + 1� � � �� � � 1 � � = lim �x · 1 − n→∞ n+1 � L = |x|. When |x| < 1, L < 1 and the ratio test tells us that the series will converge. For |x| > 1, L > 1 and the series diverges. The radius of convergence is 1. ∞ � 1 This gives us an idea of how close the harmonic series is to being n n=1 convergent. 1 MIT OpenCourseWare http://ocw.mit.edu 18.01SC Single Variable Calculus�� Fall 2010 �� For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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