Concept of Equilbrium • Equilibrium is achieved when opposing processes proceed at equal rates. A B In chemical equilibria, forward and reverse reactions occur at equal rates. Forward reaction A! B Rate= Reverse reaction B!A Rate= Equilibrium does not tell you about the rate of the reaction. N2(g) + O2(g) 2NO(g) K ~10-30 Therefore, 2NO(g) N2(g) + O2(g) K ~1030 BUT, NO(g) is stable at room temp. ! What DOES affect equilibrium? 1. concentration 2. volume (if gases are involved) 3. temperature (changes the value of Kc) At equilibrium, •Concentrations of reactants and products do not change over time. Dynamic balance CATALYSTS affect the RATE of a reaction, but not Keq. •Reaching equilibrium may be slow! FA07 CH112 LRSVDS EQUILIBRIUM 1 FA07 CH112 LRSVDS EQUILIBRIUM 2 Catalysts do not effect equilibrium concentrations. A B Calculations of Kc The value of the equilibrium constant Keq is NOT affected by the presence of a catalyst. At temperatures near 800 oC, steam passed over hot coke (a form of carbon obtained from coal), reacts to form CO and H2: C(s) + H2O(g) CO(g) + H2(g) The mixture of gases that results is an important industrial fuel called water gas. When equilibrium is achieved at 800 oC; [H2] = 4.0 x 10"2 M, [CO] = 4.0 x 10"2 M [H2O] = 1.0 x 10"2 M. Calculate Kc at this temperature ! A catalyst lowers ________________________ between the reactants and products. ! Lowering the activation energy increases ____ ______ of a reaction, both forward and backward. ! The catalyst increases the rate at which equilibrium is achieved, but it does not change the _________________ of the equilibrium mixture. FA07 CH112 LRSVDS EQUILIBRIUM 3 a) b) c) d) 0.16 1.6 #10"3 4.0 6.25 FA07 CH112 LRSVDS EQUILIBRIUM 4 Manipulations of Equilibrium Constants Manipulation of Equilibrium Constants: !Keq in the reverse direction is the _______ of the forward reaction Keq. What is the value of the equilibrium constant for the following reaction? N2(g) + O2(g) + Br2(g) 2NOBr(g) Kc =?? Given the following data: 2NO(g) + Br2(g) 2NO(g) 2NOBr(g) N2(g) + O2(g) Kc =2.0 Kc = 2.1. #1030 !Keq of a reaction that has been multiplied by an integer is the original Keq ____________________. !If the net reaction is made up of 2 or more steps, Keq is the ___________ of the individual Keq's FA07 CH112 LRSVDS EQUILIBRIUM 5 FA07 CH112 LRSVDS EQUILIBRIUM 6 Using the Equilibrium Constant Using the Equilibrium Constant 2. Predict direction of a reaction Q $ reaction quotient Information obtained from Kc 1. Which are favored? Reactants or products? For the following reaction Keq is 3.9 ! 10 CaF2(s) The equilibrium constant for the following reaction at 150°C is 8.5#10"3. 11 2IBr(g) Br2(g)+ I2(g) +2 Ca (aq) + 2F (aq) If there are 0.02 moles of I2, 0.05 moles of Br2 and 0.30 moles of IBr then: In the equilibrium reaction mixture: A products dominate B reactants dominate C There is a reasonable mixture of reactants and products D only products exist. E. only reactants exist. FA07 CH112 LRSVDS EQUILIBRIUM a) the system is at equilibrium. b) the system is not at equilibrium and the products will react to produce more IBr(g) in order to get to equilibrium. (The reaction will proceed to the left.) c) the system is not at equilibrium and the reactant (IBr) will react to produce more Br2(g) and I2(g) in order to get to equilibrium. (The reaction will proceed to the right.) d) the system can never get to equilibrium. 7 FA07 CH112 LRSVDS EQUILIBRIUM 8 Using the Equilibrium Constant Le Chatelier’s Principle 3. Obtaining equilibrium concentrations of reactants and products. At 750ºC. Kp = 0.770 for the reaction below. CO2(g) + H2(g) CO(g) + H2O(g) If 0.200 atm of CO2 and H2 are admitted to a rigid container and allowed to reach equilibrium. What is the equilibrium partial pressure of CO? If a system at equilibrium is disturbed by changing: • Concentration of one of the components • Temperature • Pressure the concentrations will shift to counteract the disturbance. Fe3+(aq) + SCN-(aq) yellow colorless heat + CaCO3 (s) [Fe(SCN)]2+(aq) red CaO(s) + CO2(g) heat + Co[H2O]6+2(aq) + 4Cl"(aq) pink CoCl4"2(aq)+ 6H2O(l) blue FA07 CH112 LRSVDS EQUILIBRIUM 9 FA07 CH112 LRSVDS EQUILIBRIUM 10
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