2/22/2016
4Fe + 3O2  2Fe2O3
4Fe + 3O2  2Fe2O3
How many grams of iron are needed to produce 7.70 moles of iron (III) oxide?
If 4.5 moles of oxygen reacts with iron, what mass of iron (III) oxide will be produced?
Mole Ratio
Given
7.70 mol Fe2O3 4 mol Fe
Calculator Answer
860.013
Molar Mass
55.845 g Fe
2 mol Fe2O3 1 mol Fe
= 860. g Fe
2Al+ 3Cu(NO3)2  3Cu + 2Al(NO3)3
What mass of copper is produced if 200.0 g of aluminum reacts?
Given
Molar Mass Mole Ratio
Molar Mass
Calculator Answer
706.537
200.0 g Al 1 mol Al
3 mol Cu 63.546 g Cu
26.982 g Al 2 mol Al 1 mol Cu
= 706.5 g Cu
Given
Mole Ratio
4.5 mol O2 2 mol Fe2O3 159.687 g Fe2O3
3 mol O2
Calculator Answer
479.061
Molar Mass
1 mol Fe2O3
= 480 g Fe2O3
2Al+ 3Cu(NO3)2  3Cu + 2Al(NO3)3
What mass of aluminum nitrate is produced if 100.0 g of aluminum reacts?
Given
Molar Mass Mole Ratio
100.0 g Al 1 mol Al
2 mol Al(NO3)3
26.982 g Al 2 mol Al
Calculator Answer
789.3929286
Molar Mass
212.994 g Al(NO3)3
1 mol Al(NO3)3
= 789.4 g Al(NO3)3
2Al+ 3Cu(NO3)2  3Cu + 2Al(NO3)3
If 30.0 g of aluminum nitrate is produced how many grams of copper (II) nitrate are needed?
Given
Mole Ratio
Molar Mass
30.0g Al(NO3)3 1 mol Al(NO3)3
Molar Mass
3 mol Cu(NO3)2 187.554 g Cu(NO3)2
212.994 g Al(NO3)3 2 mol Al(NO3)3 1 mol Cu(NO3)2
Calculator Answer
39.6252007
= 39.6 g Cu(NO3)2
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