Recap – Last Lecture Predicting Reactions • An acid is a proton donor • A base is a proton acceptor • A reaction between a strong acid and a strong base will go to completion. • A conjugate pair differ by H+ • A strong acid – weak base or weak acid – strong base reaction will go to completion. • Strong A/B is completely dissociated • Weak A/B is in equilibrium eg CH3COOH + OH– → CH3COO– + H2O • For a reaction between a weak acid and a weak base, a comparison of pKa values enables us to determine whether the reaction will occur. • The smaller pKa, the stronger the acid and the weaker its conjugate base. 1 Predicting Reactions 2 Buffer • Example: Will hydrogencarbonate (HCO3–) react with phenol (C6H5OH)? C6H5OH + HCO3– ⇌ C6H5O– + H2CO3 pKa=10.0 pKa=6.35 • A buffer is a solution composed of moderate quantities of both members of a conjugate acid-base pair (e.g. CH3COOH and CH3COO– (Na+)). • It maintains a solution at approximately constant pH even when small quantities of H+ or OH– are added. The answer is ‘no’. The equilibrium lies to the left. • But hydorgencarbonate will react with acetic acid: CH3COOH + HCO3– ⟶ CH3COO– + H2CO3 pKa=4.7 pKa=6.35 Conjugate pair p Ka Optimum pH of buffer CH3COOH / CH3COO- 4.76 H2PO4- / HPO42- 7.20 4.76 7.20 NH4+ / NH3 9.26 9.26 3 Relationship between pKa and pH • The equilibrium between a conjugate acid – base pair is affected by pH. HA ⇌ H+ + A– 4 Example • Which of CH3COOH / CH3COO– will dominate at a physiological pH = 7.4 given CH3COOH pKa = 4.76? • At high [H+], (low pH), the equilibrium is towards the left and visa versa. • Comparison of pH with pKa of the weak acid/base system indicates in which direction the equilibrium lies. • If the pH is on the ‘acid side’ of the pKa, the conjugate acid will predominate. • If the pH is on the ‘base side’ of the pKa, the conjugate base will predominate. 5 CH3COOH(aq) ⇌ CH3COO–(aq) + H+(aq) Answer: pH > pKa ie pH is on the ‘base side’ of the pKa so the conjugate base will dominate: CH3COO– 6 1 Example Amino Acids • A more complicated diagram results for a polyprotic acid, eg H3PO4. • Note pKa1 < pKa2 < pKa3 • • An amino acid contains (at least) two groups that are acid base active – a carboxylic acid and an amine. Each group has a pKa associated with it. e.g. glycine pKa (H3PO4) = 2.2 pKa (H2PO4-) = 7.2 pKa (HPO42-) = 12.3 pK a = 9.60 (of conjugate acid) H H N C H H O OH At physiological pH, this will exist in an ionic form: H H H N C H H O C O 7 Applications – CO2 in blood • H2CO3(aq) ⇌ 8 Applications – O2 in blood Buffers are an important part of living systems. Human blood has a normal pH range of 7.35-7.45. Any deviation from this can disrupt cell membranes, proteins and enzyme activity. The major buffer solution that controls blood pH is CO2(g) + H2O(l) ⇌ pK a = 2.34 C H+(aq) + HCO3–(aq) … (1) • Regulation of pH in the blood relates directly to effectiveness of oxygen transport. The blood transports oxygen using haemoglobin (Hb) which reversibly binds H+ and O2 in a competitive equilibrium: HbH+ + O2 Notes: • Although carbonic acid (H2CO3)is diprotic, only the first ionization is important. • CO2 is a gas which provides the body with a mechanism to adjust the equilibrium. Removal of CO2 by exhalation shifts the equilibrium to the left, consuming H+ ions. • Buffer solution in blood plasma has [HCO3–] ~ 0.024 M and [H2CO3] ~ 0.0012 M (20/1 ratio). As a consequence the buffer solution has a high capacity to neutralize additional acid, but low capacity to neutralize additional base. • Principle organs that regulate blood pH are the lungs and kidneys with input from brain sensors. • When [CO2] rises, equilibrium shifts to the right which increases [H+] which, in turn, triggers receptors that increase breathing rate and elimination of CO2 to restore pH. • Kidneys absorb & release H+ and HCO3–; much excess acid leaves the body in urine (pH 5-7). 9 ⇌ HbO2 + H+ ………(2) Notes: • When the blood reaches the tissue where the [O2] is low, the equilibrium is shifted to the left to release O2. An increase in [H+] and an increase in temperature also shifts the equilibrium to the left (ΔH < 0, exothermic). • During exertion several factors work to ensure delivery O2 to active tissue. • As O2 is consumed the equilibrium 2 shifts to the left. • Exertion raises body temp which also shifts equilibrium 2 to the left. • Increased metabolic production of CO2 shifts equilibrium 1 to the right increasing [H+] which also shifts equilibrium 2 to the left. Other acids such as lactic acid are produced when tissue is starved of O2 which further shifts equilibrium 2 to the left. (This extra production of acids may produce cramps.) • Increased [H+] stimulates increase rate of breathing, which provides more O2 and 10 eliminates CO2. Learning Outcomes: • By the end of this lecture, you should: − predict the outcome of an acid - base reaction. − understand the function and composition of a buffer. − recognise the relationship between pH, pKa and the form of the conjugate pair present. − be able to predict the charge state of an amino acid at a particular pH. − be able to complete the worksheet (if you haven’t already done so…) 11 2
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