8-9 Perfect Squares Factor Perfect Square Trinomials Perfect Square Trinomial a trinomial of the form π2 + 2ab + π 2 or π2 β 2ab + π 2 The patterns shown below can be used to factor perfect square trinomials. Squaring a Binomial Factoring a Perfect Square Trinomial (π + 4)2 = π2 + 2(a)(4) + 42 = π2 + 8a + 16 π2 + 8a + 16 = π2 + 2(a)(4) + 42 = (π + 4)2 (2π₯ β 3)2 = (2π₯)2 β2(2x)(3) + 32 = 4π₯ 2 β 12x + 9 4π₯ 2 β 12x + 9 = (2π₯)2 β 2(2x)(3) + 32 = (2π₯ β 3)2 Example 1: Determine whether 16ππ β 24n + 9 is a Example 2: Factor 16ππ β 32x + 15. perfect square trinomial. If so, factor it. Exercises Determine whether each trinomial is a perfect square trinomial. Write yes or no. If so, factor it. 1. π₯ 2 β 16x + 64 2. π2 + 10m + 25 3. π2 + 8p + 64 Factor each polynomial, if possible. If the polynomial cannot be factored, write prime. 4. 98π₯ 2 β 200y2 5. π₯ 2 + 22x + 121 6. 81 + 18j + j2 7. 25π 2 β 10c β 1 8. 169 β 26r + r2 9. 16π2 β 40ab + 25π 2 10. 16π2 + 48m + 36 13. 36π₯ 2 β 12x + 1 11. 16 β 25π2 12. π 2 β 16b + 256 Solve Equations with Perfect Squares Factoring and the Zero Product Property can be used to solve equations that involve repeated factors. The repeated factor gives just one solution to the equation. You may also be able to use the Square Root Property below to solve certain equations. Square Root Property For any number n > 0, if π₯ 2 = n, then x = ±βπ. Example: Solve each equation. Check your solutions. a. ππ β 6x + 9 = 0 b. (π β π)π = 64 Exercises Solve each equation. Check the solutions. 1. π₯ 2 + 4x + 4 = 0 2. 16π2 + 16n + 4 = 0 3. 25π2 β 10d + 1 = 0 4. π₯ 2 + 10x + 25 = 0 5. 9π₯ 2 β 6x + 1 = 0 6. π₯ 2 + x + 4 = 0 7. 25π 2 + 20k + 4 = 0 8. π2 + 2p + 1 = 49 9. π₯ 2 + 4x + 4 = 64 10. π₯ 2 β 6x + 9 = 25 13. (π₯ + 1)2 = 7 11. (4π₯ + 3)2 = 25 1 12. 16π¦ 2 + 8y + 1 = 0
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