2 = 25 2 = 144 2 = 121 2 = 42 2 = 108 2 = 13 2

Name: __________________________ Algebra 1 Period: _______
Date: _____________
Scaffold Handout : Solving Quadratic Equations using Square roots as Inverse Operations
Directions: You must do at least 9 problems from your proficiency level and 4 from the other 2 levels
LEVEL 1: Developing- I can solve basic one step equations involving square roots as inverse operations
π‘₯π‘₯ 2 = 25
π‘₯π‘₯ 2 = 144
π‘₯π‘₯ 2 = 121
π‘₯π‘₯ 2 = 42
π‘₯π‘₯ 2 = 108
π‘₯π‘₯ 2 = 13
2π‘₯π‘₯ 2 = 36
3π‘₯π‘₯ 2 = 27
4π‘₯π‘₯ 2 = 32
π‘₯π‘₯ 2
=2
9
π‘₯π‘₯ 2
= 18
2
π‘₯π‘₯ 2
= 27
3
LEVEL 2: Proficient- I can solve one and two step equations involving square roots as inverse operations
βˆ’10 + π‘₯π‘₯ 2 = βˆ’6
27 = 14 + π‘₯π‘₯ 2
(3π‘₯π‘₯ βˆ’ 30)2 βˆ’ 9 = 0
(2π‘₯π‘₯ βˆ’ 1)2 + 4 = 9
π‘₯π‘₯ 2
2( ) = 18
8
(π‘₯π‘₯ + 4)2 = 9
βˆ’3 + (3π‘₯π‘₯)2 = 6
(4 βˆ’ π‘₯π‘₯)2 = 5
4π‘₯π‘₯ 2 = (π‘₯π‘₯ βˆ’ 8)2
(π‘₯π‘₯ βˆ’ 110)2 = 144 (6π‘₯π‘₯ + 1)2 βˆ’ 4 = 12
4π‘₯π‘₯ 2
= 27
2
LEVEL 3: Advanced- I can solve multi- step equations involving square roots and squares as inverse
operations
βˆ’5 + (2π‘₯π‘₯)2 = 11
(π‘₯π‘₯ βˆ’ 5)2 = π‘₯π‘₯ 2
(2π‘₯π‘₯ βˆ’ 32)2 βˆ’ 17 = 1 2(π‘₯π‘₯ βˆ’ 3)2 + 1 = 7
√2π‘₯π‘₯ βˆ’ 1 + 4 = 9
4(π‘₯π‘₯ βˆ’ 5)2 + 5 = π‘₯π‘₯ 4
√3π‘₯π‘₯ = π‘₯π‘₯
√2π‘₯π‘₯ βˆ’ 1 + 4 = √π‘₯π‘₯
4π‘₯π‘₯ 4 = (βˆ’5π‘₯π‘₯ + 3)2
√π‘₯π‘₯ βˆ’ 8 = √2π‘₯π‘₯ βˆ’ 32
3(2π‘₯π‘₯ + 1)2 = 12
4π‘₯π‘₯ 4
= 36
2