CHEM 110 (BEAMER) PW33 Last Name Do Date First Name Section M T W R Practice Homework 33 Predicting Products 2 – Decomposition of a Metal Hydrogen Carbonate General Instructions Do Date: W (4/6) Relevant Reading/Materials You will need your Periodic Table, Notes-047A, Notes-047B, and Appendix-08 (Polyatomic Ions) Textbook. Useless here. Instructions For Part “A” of each question, write the name of the product. For Part “B” of each question, write the skeleton equation (the chemical formulas of reactants and products). None of the answers are “NR” in this assignment. Do not balance the equations. Timing: 30 minutes (for now). Timing on a test for the same number of questions: 12 minutes. Remember: In the complete chemical equation: H2O(g) and CO2(g) are written. Remember: In the incomplete chemical equation: H2O(g) + CO2(g) are written as H2CO3(aq). Example Write the (unbalanced) complete chemical equation for the decomposition of chromium(VI) hydrogen carbonate. (You do not have to show this step, you can do it in your head. However, if you need to write it down, do so!) Work from the name. Chromium(VI) hydrogen carbonate means that I will get chromium(VI) hydrogen carbonate. We always get carbon dioxide and water. So… ∆ Cr(HCO3 )6(s) → Cr(CO3 )3(s) + CO2(g) + H2 O(g) Question 1 Write the (unbalanced) complete chemical equation for the decomposition of carbonic acid. See your notes. Page 1 of 2 CHEM 110 (BEAMER) PW33 Question 2 Write the (unbalanced) complete chemical equation for the decomposition of sodium bicarbonate. (Work from the names) Question 3 Write the (unbalanced) incomplete chemical equation for the decomposition of gallium(III) hydrogen carbonate. (Work from the names) Question 4 Write the (unbalanced) incomplete chemical equation for the decomposition of zinc bicarbonate. (Work from the names) Question 5 Write the (unbalanced) complete chemical equation for the decomposition of Ba(HCO3)2(s). (Work from the names) Question 6 Write the (unbalanced) complete chemical equation for the decomposition of Ba(HCO3)2(s). (Work from the names) Page 2 of 2
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