Collisions and Rocket Motion Perfectly Elastic Collisions (no external forces) Initial kinetic energy = Final kinetic energy Example: Baggage Cart m1v1 + m2 v2 = m1v1′ + m2 v2′ Given: A 43 pound baggage cart is moving at 2.3 ft/sec to the right. A 28 pound bag is thrown on the cart with a speed of 4.7 ft/sec to the right. Required: (a) Final velocity of the bag and cart. (b) Energy lost in the process. 1 2 m1v12 + 12 m2 v22 = 12 m1v1′ 2 + 12 m2 v2′ 2 v1 is initial velocity of mass 1; v2 is initial velocity of mass 2 v'1 is final velocity of mass 1; v'2 is final velocity of mass 2 Using algebra, obtain equation for relative velocities v1 − v2 = −(v1′ − v2′ ) In an elastic collision, the relative velocity changes _______, but not __________. EF 151 Fall, 2010 Lecture 3-6 1 Example: Perfectly Elastic Collision 2 Perfectly Elastic Collisions (no external forces) Given: A 14 lb bowling ball is going down the alley at 27 ft/s. It directly strikes a single 3.5 lb pin. Assume the collision to be perfectly elastic. Required: The velocities of the bowling ball and pin after the collision. EF 151 Fall, 2010 Lecture 3-6 EF 151 Fall, 2010 Lecture 3-6 v1 − v2 = −(v1′ − v2′ ) m1v1 + m2 v2 = m1v1′ + m2 v2′ m1 3 v1 m2 v2 Billiard Ball v Billiard Ball 0 Billiard Ball v Bowling Ball 0 Bowling Ball v Billiard Ball 0 EF 151 Fall, 2010 Lecture 3-6 v1’ v2’ A. B. C. D. E. -2v -v 0 v 2v 4 Example: 2D Perfectly Elastic Collision Rocket Motion Given: An air puck with a mass of 0.15 kg and velocity (-1.7î - 2.0ĵ)m/s collides with a second air puck of mass 0.22 kg and a velocity of (3.6î)m/s. Assume the collision to be perfectly elastic. Required: The velocities of the air pucks after the collision in magnitude-angle format. • Mass of rocket __________ as fuel is burned • Rocket characterized by: • _______________ of hot gasses with respect to rocket, uex • __________________ or change of mass of rocket, dm/dt • ________ of rocket, uex(dm/dt) EF 151 Fall, 2010 Lecture 3-6 5 Rocket Motion Rocket speed EF 151 Fall, 2010 Lecture 3-6 6 Example: Space Shuttle Solid Boosters m v = uex ln 0 m Given: The space shuttle burns 49% of its launch weight of 4.5 million pounds in the first 75 seconds. The exhaust velocity of the gasses is 7200 ft/sec. Required: (a) Velocity of shuttle after 75 sec burn (b) Acceleration at lift-off m0 = initial mass m = m0 – (dm/dt)t Rocket speed in the presence of gravity m v = uex ln 0 − gt m Gravity will be assumed to be constant, but it actually decreases with height above the earth’s surface. Thrust = uex EF 151 Fall, 2010 Lecture 3-6 dm dt 7 EF 151 Fall, 2010 Lecture 3-6 8
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