82043_CH10_SA_ANS.qxd:82043_10_SA_ANS.ps 8/30/09 4:15 PM Page 1 CHAPTER S T U DY A I D A N S W E R S 10 THE Rh BLOOD GROUP SYSTEM TONY CASINA AND EVA D. QUINLEY 10-1. AntiD C E 0 c e Wiener Fisher–Race Rosenfield 0 0 R1R1 or R1r DCe/DCe DCe/Ce Rh: 1, 2, 3, 4, 5 0 R2R2 or R2r DcE/DcE or DcE/cE Rh: 1, 2, 3, 4, 5 0 R2R2 or R2r or R2ry DcE/DcE or DCE/cE or DcE/CE Rh: 1, 2, 3, 4, 5 0 0 R0R0 or R0r Dce/Dce or Dce/ce Rh: 1, 2, 3, 4, 5 R1R2 or RzR0 or Rzr or R2r or R1r or R0ry DCe/DcE or DCE/Dce or DCE/ce or DcE/Ce or DCe/cE or Dce/CE Rh: 1, 2, 3, 4, 5 0 0 RzRz or Rzry DCE/DCE or DCE/CE Rh: 1, 2, 3, 4, 5 0 0 0 rr ce/ce Rh: 1, 2, 3, 4, 5 0 0 rr cE/ce Rh: 1, 2, 3, 4, 5 0 0 rr Ce/ce Rh: 1, 2, 3, 4, 5 10-2. Of the genotypes listed in the above table, which one is most common in the Caucasian population? R1r Which one is least common? RzRz 10-3. a, c, d 5 10-4. _____ 2 _____ 1 _____ 4 _____ 3 _____ R1R2 Dc–/Dc– –D–/–D– R1R1 R2R2 10-5. 1) Mother: R1R1 or R1r⬘ Father: RzR0 or R2r or R1R2 or R2r⬘ or R1r⬙ or R0ry 2) Mother: R1R1 Father: R1R2 3) R1 R1 R1 R1R1 R1R1 R2 R1R2 R1R2 50% of offspring would be R1R1 50% of offspring would be R1R2 4) There are three possible explanations. One is nonpaternity. A second explanation is that the Rh type of this offspring may be due to an amorph Rh gene inherited from the mother. The mother’s haplotype may be R1/– – –. In this case, the offspring would type as R2 with a haplotype of R2/– – –. The amorph type of inheritance will continue to be passed to the offspring, resulting in apparent homozygous expression of the Rh genotype. A third possible explanation is that the Rh type of this offspring is due to an Rh “regulator” gene. In this case, the parents would have normal expression of the Rh antigens but be heterozygous for the RHAG gene. If each parent passed the RHAG gene mutation to the offspring, Rh antigen production would be blocked. The offspring would be negative for all Rh antigens (i.e., Rhnull). Because the offspring in question has expressed DcE antigens, the most likely explanation is the “amorph” inheritance. 5) Because positive reactions were noted with all Rh antisera tested, a control was tested to eliminate the possibility of false-positive reactions. Alternatively, the DAT could have been performed. It is best to consult the package insert for the antisera to determine the most appropriate control and when it should be tested. 10-6. • The wrong sample was collected and tested • Technical error (e.g., wrong reagent, improper technique, not following package insert) 1 82043_CH10_SA_ANS.qxd:82043_10_SA_ANS.ps 2 8/30/09 4:15 PM Page 2 UNIT 4 Red Blood Cell Groups and HLA • Reagent anti-D is different than that used previously and results differ (polyclonal vs. monoclonal or different monoclonal reagent with different clones) • Deterioration of reagent anti-D 10-7. The most likely explanation is that the patient has a partial D antigen and has made antibodies against the missing components of the D antigen. The patient is weakly reactive with reagent anti-D, indicating that some D antigen is present but in a smaller quantity than expected. Because the patient has been transfused, it is possible to form antibodies against the missing component of the D antigen. Additional testing with special antisera or testing by nucleic acid analysis would be required to help identify the type of partial D.
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