PracticePacket:OxidationReduction Regents Chemistry: Mrs. Mintz PracticePacket Chapter14:OxidationReduction&Electrochemistry 1 Assigning Oxidation Numbers Objective: How do we assign atoms the correct oxidation number? Chemistry 200 Video Lesson 14.1 Rules for Assigning Oxidation Numbers (states) Oxidation & Reduction (Redox) Oxidation number 1. Free elements are assigned an oxidation state of zero The hydrogen in H2, the sodium in Na, and the sulfur in S8 all have oxidation numbers of zero. 2. The Group 1 metals (Alkali Metals) in compounds always have an oxidation state of +1 • a number assigned to keep track of electron(s) gained or lost in a redox rxns. 3. The Group 2 metals (Alkali Earth Metals) in compounds always have an oxidation state of +2 4. The oxidation state for any simple one-atom ion(monoatomic) is equal to its charge. 7. Oxygen in compounds is assigned an oxidation state of -2. **When combined w/ Fluorine, Oxygen has an oxidation state of +2.** In MgCl2, the Mg2+ ion has an oxidation number of +2. Each of the Cl- ions has an oxidation number of -1. Fe2+ ion has an oxidation number of +2, In FeCl2, the while in FeCl3 the Fe3+ ion has an oxidation number of +3. 5. Fluorine in compounds is always assigned an oxidation state of -1. 8. The sum of the oxidation states of all the atoms in a species must be equal to the net charge on the species. If the species is neutral, the sum of the oxidation states is zero. 6. Hydrogen in compounds is always assigned an oxidation number of +1. (HCl). If combined w/ a metal, Hydrogen has an oxidation # of -1. (LiH) If the species has a charge, the sum is equal to that charge. 2 Determine the oxidation number of sulfur in H2SO4 (+2)+6(-8)=0 +1 +6-2 Determine the oxidation number of nitrogen in NO3-1 +5(-6)= -1 +5-2 -1 H2SO4 NO3 Objective: Redox Reactions How do we identify substances being oxidized or reduced and the oxidizing and reducing agents. How do we use this information to create half reactions ? Chemistry 200 Video Lesson 14.2 Redox Easy way to remember!!! Redox reaction • a chemical rxn where electron(s) are transferred from one atom to another Oxidation • loss of electron(s) by an atom or ion & an increase ) in oxidation # (Ca à Ca+2 + 2e- Chemistry GER!!!!! Yum Yum LEO says GER LEO = Loss of Electrons is Oxidation Reduction • gain of electron(s) by an atom or ion & a decrease in oxidation # ( 5e - + Mn+7 à Mn+2) GER = Gain of Electrons is Reduction **Oxidation & Reduction occur simultaneously, they cannot occur separately** 3 Oxidizing Agent Reducing Agent • the substance that allows another substance to be reduced. They lose electron(s) & therefore are oxidized • the substance that causes the oxidation of other substances. They accept electron(s) easily & therefore are reduced ex: Ca à Ca+2 + 2e- ex1: 5e- + Mn+7 à Mn+2 (gain of electrons, oxidation # reduced) (loss of electrons, oxidation # increases) **The species oxidized, the species reduced, the oxidizing agent or reducing agent must always be a reactant!!** Writing Half Reactions Gains Electrons Loses Electrons Reduced Oxidized Oxidizing Agent Reducing Agent • They show either the oxidation or reduction portion of a redox rxn, including electrons gained or lost Half rxn for oxidation --> electrons are products Half rxn for reduction --> electrons are reactants THERE’S AN EASIER WAY TO REMEMBER!!! **Electronsgoonthesidew/themorepositiveoxid.#** Creating Half Reactions from a Redox Reaction +1+5-6 +1+5-2 1. Assign oxidation numbers to determine the substance oxidized & the substance reduced. +1-1 0 KClO3 --> KCl + O2 2. Write each half reaction, balance by atom, then by electrons. The ONLY exception is a half rxn the contains a diatomic element. Oxid: 2 O-2 à O2+ 4e- (reducing agent) Red: 6e- +Cl+5 à Cl-1 (oxidizing agent) 3. Identify the species oxidized, the species reduced the oxidizing agent & the reducing agent. 4 Objectives • Name the type of reactions involved in electrochemical processes. • Describe how a voltaic cell produces electrical energy. Electrochemical Cells Video Lesson 14.4 Electrochemical Process Voltaic Cells • An electrochemical process is any conversion between chemical and and electrical energy (charged particles). • All electrochemical processes involve redox reactions. • The two half reactions must be physically separated to be used as a source of electrical energy. • To obtain a useful current, we separate the oxidizing and reducing agents so that electron transfer occurs thru an external wire. • What is needed – Spontaneous Reaction o Salt Bridge • connects the 2 containers & provides a passage for ions from one solution to another o Electrodes • one of 2 surfaces that conduct electricity, the site of oxidation & reduction rxns Since Zn is higher on Table J, It will be Oxidized! Anode 5 Cathode Flow of Electrons Voltaic Cell Zn(s) anode - Overall Redox Rxn Reduction occurs at the cathode Oxidation occurs at the anode From Anode to Cathode e- --> Zn(s) + Cu+2(aq) --> Zn+2(aq) + Cu(s) Oxid: Zn(s) --> Zn+2(aq)+ 2e- Red: 2e- + Cu+2(aq) --> Cu(s) Zn Species oxidized_____ Cu+2 Species reduced_____ Zn Anode_______ 6 Cu(s) cathode + Cu Zn Zn+2 Cu+2 Zn Reducing agent______ Cu Oxidizing agent_____ +2 Cu Cathode_______ PracticePacket:Redox Video14.1:OxidationNumbers DeterminetheoxidationnumberofEACHelementineachofthefollowingsubstances: 1. KMnO4 6. PO4-3 7. zincoxide 2. S8 3. Na2Cr2O7 8. water 9. calciumhydride 4. CuCl2 10. 5. H2SO4 carbondioxide Video14.2:RedoxReactions WritingHalfReactions Step1:Balancethehalfreactionbyatomusingcoefficients Step2:Balancethehalfreactionbychargeusingelectrons(e-) Electronsalwaysgoonthesidewiththemorepositiveoxidation# **Halfrxnsarewrittenonaperatombasis.Theonlyexceptionisifthehalfrxncontainsadiatomic element** MgàMg+2 N-3àN2 O2àO-2 S+6àS-2 Cl+5àCl-1 3Cu+1à3Cu Mn+2àMn+5 6H+1à3H2 7 14.1 Oxidation Numbers Name: 1. What is the oxidation state of nitrogen in the compound NH 4 Br? 1) –1 2) +2 3) –3 8. Given the reaction that occurs in an electrochemical cell: 4) +4 Zn(s) + CuSO 4 (aq) ® ZnSO 4 (aq) + Cu(s) During this reaction, the oxidation number of Zn changes from 2. What is the oxidation number of sulfur in Na2S2O3 ? 1) –1 2) +2 3) +6 1) 0 to +2 2) 0 to –2 4) +4 3. Given the balanced equation representing a reaction: 9. In which substance does hydrogen have an oxidation number of zero? 1) LiH 2) H 2 O 2KClO 3 (s) ® 2KCl(s) + 3O 2 (g) The oxidation state of chlorine in this reaction changes from 1) –1 to +1 2) –1 to +5 3) + l to –1 4) +5 to –1 2) +2 3) +3 1) CO 2) CO 2 4) +8 5. What is the oxidation number assigned to manganese in KMnO 4 ? 1) +7 2) +2 3) +3 4) +4 6. What is the oxidation state of nitrogen in NaNO 2 ? 1) +1 2) +2 3) +3 4) +4 7. What is the oxidation number of chromium in K 2 Cr 2 O 7 ? 1) +12 2) +2 3) +3 3) H 2 S 4) H 2 10. In which compound does carbon have an oxidation state of –4? 4. What is the oxidation number of chromium in the chromate ion, CrO 4 2– ? 1) +6 3) +2 to 0 4) –2 to 0 4) +6 8 3) CCl 4 4) CH 4 PracticePacket:Redox CreatingHalfReactionsfromRedoxReactions Step1:Assignoxidationnumberstodeterminethesubstancesthathaveachangeinoxidationnumber Step2:Identifythetwohalfreactions&balanceeachhalfreaction Step3:Labeleachhalfreaction&identifythespeciesoxidized,thespeciesreduced,theoxidizing agent&thereducingagent Note:Thereactionprovidedtoyoumaybebalancedorunbalanced.Rememberthathalfreactionsaremadeonaperatom basis.TheONLYexceptionisahalfreactionthatcontainsadiatomicelement Speciesoxidized______________ Cu+2+MnàMn+4+Cu Speciesreduced______________ Oxidation: Speciesoxidized______________ ReducingAgent______________ Reduction: 3Ag+1+FeàFe+3+3Ag Speciesreduced______________ Oxidation: Speciesoxidized______________ OxidizingAgent______________ ReducingAgent______________ Reduction: Na+Cl2àNaCl Speciesreduced______________ Oxidation: OxidizingAgent______________ OxidizingAgent______________ ReducingAgent______________ Reduction: 2H2+O2à2H2O Speciesoxidized______________ OxidizingAgent______________ Speciesreduced______________ ReducingAgent______________ Oxidation: Reduction: 9 PracticePacket:OxidationReduction Speciesoxidized______________ 2S+3O2à2SO3 Speciesreduced______________ Oxidation: Speciesoxidized______________ ReducingAgent______________ Reduction: 2Fe+6HClà3H2+2FeCl3 Speciesreduced______________ Oxidation: Speciesoxidized______________ OxidizingAgent______________ ReducingAgent______________ Reduction: CH4+2O2àCO2+2H2O Speciesreduced______________ Oxidation: OxidizingAgent______________ OxidizingAgent______________ ReducingAgent______________ Reduction: 2KClO3à2KCl+3O2 Speciesoxidized______________ OxidizingAgent______________ Speciesreduced______________ ReducingAgent______________ Oxidation: Reduction: http://mintzchemistry.weebly.com 10 14.2 Half Reactions Name: 7. Which equation represents an oxidation-reduction reaction? 1. An oxidation-reduction reaction involves the 1) 2) 3) 4) sharing of electrons sharing of protons transfer of electrons transfer of protons 1) 2) 3) 2. During which process does an atom gain one or more electrons? 1) transmutation 2) reduction 4) 8. Which half-reaction shows conservation of charge? 3) oxidation 4) neutralization 1) Cu + e– ® Cu+ 2) Cu2+ + 2e– ® Cu 3. Which half-reaction correctly represents reduction? 1) 2) 3) 4) Mn 4+ Mn 4+ Mn 4+ Mn 4+ 9. Which balanced equation represents an oxidation-reduction reaction? ® Mn3+ + e – ® Mn7+ + 3e– + e – ® Mn3+ + 3e– ® Mn7+ 4. In a redox reaction, the total number of electrons lost is 1) less than the total number of electrons gained 2) greater than the total number of electrons gained 3) equal to the total number of electrons gained 4) equal to the total number of protons gained 2) Mg 2+ 3) Co2+ 4) Ca2+ 6. Given the balanced ionic equation representing a reaction: 2Al(s) + 3Cu 2+(aq) 2Al3+(aq) + 3Cu(s) Which half-reaction represents the reduction that occurs? 1) Al Al 3+ + 3e– 2) Al3+ + 3e– Al 1) 2) 3) 4) Ba(NO3) 2 + Na 2SO4 ®BaSO 4 + 2NaNO 3 H3PO4 + 3KOH ®K3PO4 + 3H2O Fe(s) + S(s) ®FeS(s) NH3(g) + HCl(g) ®NH4Cl(s) 10. Which expression correctly represents a balanced reduction half-reaction? 1) Na+ + e – ® Na 2) Na ® Na+ + e – 5. Which ion is most easily reduced? 1) Zn 2+ 3) Cu+ ® Cu + e – 4) Cu2+ ® Cu + 2e– 3) Cu Cu2+ + 2e– 4) Cu2+ + 2e– Cu 11 3) Cl 2 + 2e– ® Cl – 4) 2 Cl– ® Cl 2 + 2e– PracticePacket:OxidationReduction Lesson14.3:ActivitySeriesandSpontaneity Table J: The table is arranged with the most reactive metals at the top of the tableandtheleastreactivemetalsatthebottomofthetable.Whatthismeansis thatametallistedonthetablewillreactwiththecompoundofametalthatis below it. For example, Zn is above Cu on the table. This means that Zn will replaceCuinacompound.ZnwillbeoxidizedbyacompoundcontainingCu.The Cu+ionwillbereducedbyelementalZn0.MetalshigherontableJaremorelikely tobeoxidized. Thereaction: Zn+Cu(NO3)2àCu+Zn(NO3)2willspontaneouslyoccur. Foreachexamplebelow,ifareactionwilloccurspontaneouslybasedonthe elementpositionsintheActivitySeries,completetheequationandbalance it.Ifthereisnoreaction,writenoreaction. 1. Ag(s)+Cu(NO3)2(aq)à 2. Pb(s)+AuCl(aq)à 3. Au(s)+LiCl(aq)à 4. Mg(s)+Pb(NO3)2(aq)à Determineifaspontaneousreactionwilloccur.Ifonewilloccur,write thebalancedoxidationandreductionhalfreactions. 1. Zn+Pb(NO3)2àPb+Zn(NO3)2 • Isthereactionspontaneous?________________ • Ifyes,writetheoxidation½reaction: • Ifyes,writethereduction½reaction: 2. 3Zn+2Al(NO3)3à2Al+3Zn(NO3)2 • Isthereactionspontaneous?________________ • Ifyes,writetheoxidation½reaction: • Ifyes,writethereduction½reaction: http://mintzchemistry.weebly.com 12 PracticePacket:OxidationReduction Video14.4:ElectrochemicalCells Avoltaiccellisanelectrochemicalcell.(An electrochemicalcellproduceselectriccurrentasaresultofa spontaneousredoxreaction,usedtomakebatteries.They consistoftwohalf-cellsconnectedbyasaltbridgeandtwo electrodesthatconnecttoaloadthatusestheelectricity producedbythecell.)Anexampleanelectrochemicalcellisa battery. OverallRedoxReaction: Oxidation½Reaction: Reduction½Reaction: SpeciesOxidized:_________________ Anode:______________ SpeciesReduced:_________________ Cathode:____________ http://mintzchemistry.weebly.com 13 PracticePacket:OxidationReduction Anoperatingvoltaiccellhaszincandironelectrodes.Thecellandtheunbalancedionicequation representingthereactionthatoccursinthecellareshownbelow. 1. Writethebalancedoxidationhalf-reactionforthiscell. 2. Writethebalancedreductionhalfreactionforthiscell. 3. If6molesofZnreact,howmanymolesofelectronswillbetransferred? 4. Explain,intermsofZnatomsandZnions,whythemassoftheZnelectrodedecreasesasthe celloperates. 5. Identifythesubatomicparticlesthatflowthroughthewireasthecelloperates. http://mintzchemistry.weebly.com 14 PracticePacket:OxidationReduction Astudentconstructsanelectrochemicalcellduringalaboratoryinvestigation.Whentheswitchis closed,electronsflowthroughtheexternalcircuit.Thediagrambelowrepresentsthiscellandthe reactionthatoccurs. 1. State,intermsofenergy,whythiscellisavoltaiccell. ______________________________________________________________________________________________________________ ______________________________________________________________________________________________________________ 2. DeterminethenumberofmolesofAlI(s)neededtocompletelyreactwith9.0molesofNi2+(aq) ions. 3. Writethebalancedhalf-reactionequationfortheoxidationthatoccurswhentheswitchis closed. 4. Statethedirectionofelectronflowthroughthewireandwhentheswitchisclosed. ______________________________________________________________________________________________________________ Lesson14.5:ElectrolyticCells. Electrolyticcellsuseelectricalenergytoforceanonspontaneouschemicalreactiontooccur. Reductionoccursatthecathode.Thecathodeistheelectrodewhereelectronsaresentandisthe negativeelectrode.Oxidationoccursattheanode.Theanodeistheelectrodewhereelectronsare drawnawayfromandisthepositiveelectrode. Electroplating MoltenSalt http://mintzchemistry.weebly.com 15 ElectrolysisofWater PracticePacket:OxidationReduction Electroplating: Completethechart ElectrochemicalCells VoltaicCell Example: RedoxReactions ElectrolyticCell Example:Electroplating 2electrodes Anode= Cathode=ReductionNegative(-) Anode=oxidationNegative(-) Cathode= Electronsflowfromanodetocathode Useelectricalenergyforforceanonspontaneous redoxreactiontooccur(chemical) http://mintzchemistry.weebly.com 16 1 14.5 Electrolytic Cells 3 on a nickel key. As the cell operates, oxidation occurs at the silver electrode and the mass of the silver electrode decreases. 1 cell operates 2 3 4 5 4 5 17 6 8 6 7 8 18 5HGR[5HYLHZ *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJD UHDFWLRQ :KDWLVWKHR[LGDWLRQVWDWHRIQLWURJHQLQWKH FRPSRXQG1+%U" $ ± % & ± ' )H 2$O o$O 2)H 'XULQJWKLVUHDFWLRQWKHR[LGDWLRQQXPEHURI)H FKDQJHVIURP *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJD UHDFWLRQ $ % & ' .&O2 Vo.&OV2 J 7KHR[LGDWLRQVWDWHRIFKORULQHLQWKLVUHDFWLRQ FKDQJHVIURP $ ±WR & OWR± % ±WR ' WR± *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJD UHGR[UHDFWLRQ 'XULQJZKLFKSURFHVVGRHVDQDWRPJDLQRQHRU PRUHHOHFWURQV" $ WUDQVPXWDWLRQ & R[LGDWLRQ $O&Xo$O&X % UHGXFWLRQ ' QHXWUDOL]DWLRQ :KLFKVWDWHPHQWLVWUXHDERXWWKLVUHDFWLRQ" $ % & ' :KLFKKDOIUHDFWLRQFRUUHFWO\UHSUHVHQWV UHGXFWLRQ" $ % & ' 0Q o0Q H ± 0Q o0Q H ± 0Q H ± o0Q 0Q H ± o0Q $ % & ' $ OHVVWKDQWKHWRWDOQXPEHURIHOHFWURQV JDLQHG % JUHDWHUWKDQWKHWRWDOQXPEHURIHOHFWURQV JDLQHG & HTXDOWRWKHWRWDOQXPEHURIHOHFWURQV JDLQHG ' HTXDOWRWKHWRWDOQXPEHURISURWRQVJDLQHG $ $J12DT1D&,DT o$J&,V 1D12DT % +&2 DTo+2 &2 J & 1D2+DT+&ODTo1D&ODT+ 2 ' 0JV+&ODT o0J&O DT+ J GRXEOHUHSODFHPHQWUHDFWLRQV QHXWUDOL]DWLRQUHDFWLRQV ILVVLRQDQGIXVLRQUHDFWLRQV R[LGDWLRQDQGUHGXFWLRQUHDFWLRQV :KLFKHTXDWLRQUHSUHVHQWVDQR[LGDWLRQ UHGXFWLRQUHDFWLRQ" :KLFKKDOIUHDFWLRQHTXDWLRQUHSUHVHQWVWKH UHGXFWLRQRIDQLURQ,,LRQ" )H o)H H ± )H H ± o)H )H H ± o)H )H o)H H ± $Jo$J H ± ) o)±H ± $XH ± o$X )H H ± o)H :KLFKEDODQFHGHTXDWLRQUHSUHVHQWVDUHGR[ UHDFWLRQ" +DOIUHDFWLRQVFDQEHZULWWHQWRUHSUHVHQWDOO $ % & ' (DFK$OORVHVH ±DQGHDFK&X JDLQVH± (DFK$OORVHVH ±DQGHDFK&X JDLQVH± (DFK$OJDLQVH±DQGHDFK&XORVHVH ± (DFK$OJDLQVH±DQGHDFK&XORVHVH ± :KLFKKDOIUHDFWLRQFRUUHFWO\UHSUHVHQWV UHGXFWLRQ" ,QDUHGR[UHDFWLRQWKHWRWDOQXPEHURI HOHFWURQVORVWLV $ % & ' WRDVHOHFWURQVDUHWUDQVIHUUHG WRDVSURWRQVDUHWUDQVIHUUHG WRDVHOHFWURQVDUHWUDQVIHUUHG WRDVSURWRQVDUHWUDQVIHUUHG $ % & ' 19 &+ 2 o&2 +2 +62 &D2+ o&D62 +2 0J&U2%D&O0J& %D&U2 =Q12 1D&2 o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± o&X &XH ± o&X &X o&XH± &X o&XH± $ % & ' HOHFWURO\WLFFHOOVRQO\ YROWDLFFHOOVRQO\ ERWKHOHFWURO\WLFFHOOVDQGYROWDLFFHOOV QHLWKHUHOHFWURO\WLFFHOOVQRUYROWDLFFHOOV *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJWKH UHDFWLRQRFFXUULQJLQDYROWDLFFHOO =QV3E DT =Q DT3EV ,QWKHFRPSOHWHGH[WHUQDOFLUFXLWWKHHOHFWURQV IORZIURP )H&Xo)H &X :KHQWKHLURQDWRPVORVHVL[PROHVRI HOHFWURQVKRZPDQ\PROHVRIHOHFWURQVDUH JDLQHGE\WKHFRSSHULRQV" % PROHV ' PROHV $YROWDLFFHOOVSRQWDQHRXVO\FRQYHUWVFKHPLFDO HQHUJ\WR $ % & ' &XDQRGHWRWKH=QFDWKRGH &XFDWKRGHWRWKH=QDQRGH =QDQRGHWRWKH&XFDWKRGH =QFDWKRGHWRWKH&XDQRGH 5HGXFWLRQRFFXUVDWWKHFDWKRGHLQ *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJD UHDFWLRQ $ PROHV & PROHV 1L H o1L 6QH o6Q =Qo=QH )H o)H H *LYHQWKHEDODQFHGLRQLFHTXDWLRQUHSUHVHQWLQJ WKHUHDFWLRQLQDQRSHUDWLQJYROWDLFFHOO =QV&X DTo=QDT&XV $ EHFDXVHDWRWDORIHOHFWURQVLV WUDQVIHUUHG % EHFDXVHDWRWDORIHOHFWURQVLV WUDQVIHUUHG & EHFDXVHDWRWDORIHOHFWURQVLV WUDQVIHUUHG ' EHFDXVHDWRWDORIHOHFWURQVLV WUDQVIHUUHG $ % & ' HOHFWULFDOHQHUJ\VSRQWDQHRXVO\ HOHFWULFDOHQHUJ\QRQVSRQWDQHRXVO\ QXFOHDUHQHUJ\VSRQWDQHRXVO\ QXFOHDUHQHUJ\QRQVSRQWDQHRXVO\ HOHFWULFDOHQHUJ\ JHRWKHUPDOHQHUJ\ PHFKDQLFDOHQHUJ\ QXFOHDUHQHUJ\ 20 $ % & ' 3EVWR=QV 3EDTWR=QDT =QVWR3EV =QDTWR3E DT :KLFKVWDWHPHQWLVWUXHDERXWR[LGDWLRQDQG UHGXFWLRQLQDQHOHFWURFKHPLFDOFHOO" $ %RWKRFFXUDWWKHDQRGH % %RWKRFFXUDWWKHFDWKRGH & 2[LGDWLRQRFFXUVDWWKHDQRGHDQG UHGXFWLRQRFFXUVDWWKHFDWKRGH ' 2[LGDWLRQRFFXUVDWWKHFDWKRGHDQG UHGXFWLRQRFFXUVDWWKHDQRGH :KLFKVWDWHPHQWGHVFULEHVRQHFKDUDFWHULVWLF RIDQRSHUDWLQJHOHFWURO\WLFFHOO" $ % & ' ,WSURGXFHVHOHFWULFDOHQHUJ\ ,WUHTXLUHVDQH[WHUQDOHQHUJ\VRXUFH ,WXVHVUDGLRDFWLYHQXFOLGHV ,WXQGHUJRHVDVSRQWDQHRXVUHGR[ UHDFWLRQ 7KHGLDJUDPEHORZUHSUHVHQWVDQRSHUDWLQJHOHFWURFKHPLFDOFHOODQGWKHEDODQFHGLRQLF HTXDWLRQIRUWKHUHDFWLRQRFFXUULQJLQWKHFHOO :KLFKVWDWHPHQWLGHQWLILHVWKHSDUWRIWKHFHOOWKDWFRQGXFWVHOHFWURQVDQGGHVFULEHVWKH GLUHFWLRQRIHOHFWURQIORZDVWKHFHOORSHUDWHV" $ % & ' (OHFWURQVIORZWKURXJKWKHVDOWEULGJHIURPWKH1LVWRWKH=QV (OHFWURQVIORZWKURXJKWKHVDOWEULGJHIURPWKH=QVWRWKH1LV (OHFWURQVIORZWKURXJKWKHZLUHIURPWKH1LVWRWKH=QV (OHFWURQVIORZWKURXJKWKHZLUHIURPWKH=QVWRWKH1LV :KLFKVWDWHPHQWGHVFULEHVHOHFWURO\VLV" $ &KHPLFDOHQHUJ\LVXVHGWRSURGXFHDQ HOHFWULFDOFKDQJH % &KHPLFDOHQHUJ\LVXVHGWRSURGXFHD WKHUPDOFKDQJH & (OHFWULFDOHQHUJ\LVXVHGWRSURGXFHD FKHPLFDOFKDQJH ' 7KHUPDOHQHUJ\LVXVHGWRSURGXFHD FKHPLFDOFKDQJH *LYHQWKHEDODQFHGHTXDWLRQUHSUHVHQWLQJD UHDFWLRQRFFXUULQJLQDQHOHFWURO\WLFFHOO 1D&O o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o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
© Copyright 2026 Paperzz