Secondary III 6-2 HW Name: ______________________ DO NOT EDIT--Changes must be made through “File inf Evaluate: Homework and Practice CorrectionKey=NL-A;CA-A Asymptotes of Rational Functions Book 8.2 t0OMJO State the domain using interval notation. For anynotation, x-value excluded from the domain, state State the domain using an inequality, set and interval notation. For any t)JOUT whether the graph has a vertical asymptote or a “hole” at that x-value. Use a graphing calculator t&YUSB excluded tox-value check your answer.from the domain, state whether the graph has a vertical asymptote or a “hole” at that x-value. Use a graphing calculator to check your answer. Sketch the graph of the given rational function. (I 2x 3 x+5 x2 + (x) = __ 2. ƒ 1. ƒ(x) = _ 2 of the numerator is 1 xmore x+1 - 4xthan + 3the degree of the find the graph’s slant asymptote by dividing the nu denominator.) Also state the function’s domain an inequalities, set notation, and interval notation. (I indicates that the function has maximum or minim a graphing calculator to find those values to the n when the range.) Find any holes, asymptotes, and intercepts and state the end determining behavior. 3. f ( x) = 7. x −1 2 x + x−6 x-1 ƒ(x) = _ x+1 Divide the numerator by the denominator to write the function in the form ƒ(x) = quotient + and determine the function’s end behavior. Then, using a graphing calculator to examine the f graph, state the range using an inequality, set notation, and interval notation. 3x + 1 ƒ(x) = _ x made - 2 through “File info” O NOT EDIT--Changes must be 4. 3. x ƒ(x) = __ (x - 2)(x + 3) Sketch the graph of the given rational function. Also state the function’s domain and range rrectionKey=NL-A;CA-A using interval notation. Find any x and y intercepts, state the end behavior, and behavior around the asymptotes. 8. f (x) = x +1 (x − 1)2 (x + 2) Sketch the graph of the given rational function. (If the degree of the numerator is 1 more than the degree of the denominator, find the graph’s slant asymptote by dividing the numerator by the denominator.) Also state the function’s domain and range using Domain: inequalities, set notation, and interval notation. (If your sketch 8. Range: indicates that the function has maximum or minimum values, use X–intercept: a graphing calculator to find those values to the nearest hundredth when determining the range.) Y–intercept: hton Mifflin Harcourt Publishing Company 7. x-1 )=_ ƒ(xVAsymptote: x+1 x 2 - 5x + 6 _ ( ) 5. ƒ x = Hole: x-1 increasing: decreasing: EndBehavior: y 4 x-1 ƒ(x) = __ (x - 2)(x + 3) 2 x -4 -2 6. 4x - 1 ƒ(x) = _ 2 x +x-2 AsymptotesBehavior: 0 2 -2 2 9. (x + 1)(x - 1) ƒ(x) = __ x+2 y x Name: ______________________ -6 -4 - 2 0 2 Secondary III 6-2 HW 9. f (x) = x 2 + 2x − 3 x2 + x − 2 -2 -4 x-1 y 8. ƒ(x) = __ 4 (x - 2)(x + 3) Domain: 2 Range: X–intercept: -4 -2 0 -2 Y–intercept: VAsymptote: -4 Hole: increasing: decreasing: EndBehavior: AsymptotesBehavior: DO NOT EDIT--Changes must be made through “File info” CorrectionKey=NL-A;CA-A © Houghton Mifflin Harcourt Publishing Company Module 8 Domain: Range: X–intercept: Y–intercept: VAsymptote: Hole: Increasing: Decreasing: EndBehavior: -8 x 2 4 © Houghton Mifflin Harcourt Publishing Company -3x(x - 2) __ (x + 1)(x - 1) 10. ƒ(x) =9. ƒ(x) = __ (x - 2)(x + x2+ ) 2 -6 y -6 -6 -4 -4 -2 -2 y 0 x 0 -2 2 -2 -4 -4 Lesson 2 456 -6 -6 -8 AsymptotesBehavior: -3x(x - 2) 10. ƒ(x) = __ y x 2 x -x+ 6 ⎩ ⎭ ⎫ ⎧ B. The function’s domain is ⎨xǀx⎧≠ -2 and x ≠ -3⎬. ⎫ A. The function’s domain⎩ is ⎨xǀx ≠ -2 and x ≠ ⎭ 3⎬. Secondary III 6-2 HW Name: ______________________ ⎩ ⎭ ⎫ ⎧ C. The function’s range is ⎨yǀy ≠⎧ 0⎬. ⎫ ⎩ ⎭ xǀx ≠ -2 and x ≠ -3 B. Thex 2function’s domain is ⎨ ⎬. −1 f ( x) = ⎩ ⎭ ⎫ ⎧ +2 11. D. The xfunction’s < y ⎫< +∞⎬. range is ⎨yǀ-∞ ⎧ ⎩is ⎨yǀy ≠ 0⎬. ⎭ C. The function’s range x 2 -3x ( ) y __ ( ) 10. ƒ x = ⎩ ⎭ E. The has vertical asymptotes at x = -2 and x = 3. x (x function’s - 2)(x + 2graph ) Domain: 0 ⎫ -6 -4 -2 ⎧ 2 yǀ-∞ < y < +∞ . D. The function’s range is ⎨ ⎬ F. The function’s graph has a vertical asymptote at x = -3 and a “hole” at x = 2. -2 Range: ⎩ ⎭ © Houghton Harcourt Publishing Company © Houghton Mifflin Harcourt PublishingMifflin Company © Houghton Mifflin Harcourt Publishing Company X–intercept: G. graph hashas a horizontal asymptote ataty x== 0. -2 and-x4 = 3. E. The Thefunction’s function’s graph vertical asymptotes Y–intercept: H. hashas a horizontal 1. -3 and-a6 “hole” at x = 2. VAsymptote: F. The Thefunction’s function’sgraph graph a verticalasymptote asymptoteataty = x= Hole: G. The function’s graph has a horizontal asymptote at y = 0. increasing: H.O.T. Focus on Higher Order Thinking decreasing: x+a H. The function’s graph hasvalue(s) a horizontal asymptote 1. (x) = _________ 18. Draw Conclusions For what of a does the graphatofy ƒ= EndBehavior: AsymptotesBehavior: x 2 + 4x + 3 have a “hole”? Explain. Then, for each value of a, state the domain and the range of ƒ(x) using notation. H.O.T. Focusinterval on Higher Order Thinking x+a x + 4x + 3 18. Draw Conclusions For what value(s) of a does the graph of ƒ(x) = _________ 2 have a “hole”? Explain. Then, for each value of a, state the domain and the range of ƒ(x) using interval notation. Module 8 Lesson 2 457 4x - 1 19. Critique Reasoning A student claims that the functions ƒ(x) = ______ and 4x + 2 4x + 2 ______ g(x) = 2 have different domains but identical ranges. Which part of the 2 4x - 1 student’s claim is correct, and which is false? Explain. 4x - 1 19. Critique Reasoning A student claims that the functions ƒ(x) = ______ and 4x + 2 4x + 2 ______ g(x) = 2 have different domains but identical ranges. Which part of the 2 4x - 1 student’s claim is correct, and which is false? Explain. Module 8 461 Lesson 2 Secondary III 6-2 HW Name: ______________________ Selected Answers: 1. VA: x = −1 3. X–intercept:(1,0) ⎛ 1⎞ Y–intercept: ⎜ 0, ⎟ ⎝ 6⎠ VAsymptote: x = −3, x = 2 HAsymptote: y = 0 EndBehavior: lim f (x) = 0 , lim f (x) = 0 AsymptotesBehavior: lim− f (x) = −∞ , lim+ f (x) = ∞ , lim− f (x) = −∞ , lim+ f (x) = ∞ x→−∞ x→∞ x→−3 x→−3 x→2 10. Domain: (−∞,−2) U (−2,∞) Range: (−∞,−3) U (−3,∞) X–intercept:(0,0) Y–intercept:(0,0) VAsymptote: x = −2 HAsymptote: y = −3 Hole: ⎜ 2,− ⎟ 2⎠ ⎝ increasing: ∅ decreasing: (−∞,−2) U (−2,∞) EndBehavior: lim f (x) = −3 , lim f (x) = −3 AsymptotesBehavior: lim− f (x) = −∞ , lim+ f (x) = ∞ ⎛ 3⎞ x→−∞ x→∞ x→−2 x→−2 x→2
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