POLYNOMIAL’S CLASS IX Questions From CBSE Examination Papers 1. 2. If a polynomial f (x) is divided by x – a, then remainder is : 3. (b) f (a) (c) f (–a) (d) f (a) – f(0) (b) 3 (c) –2 x3 One of the factors of ( (d) 1 (c) x – 1 (b) –10 (d) x + 4 (c) –3 (d) 17 One of the factors of ( x – 1) – – 1) is : (a) x2 – 1 (b) x + 1 (c) x – 1 (d) x + 4 6. b)3 8. The factors of (2 a – + (b – is : (a) (2 a – b)(b – 2c)(c – a) (b) 3(2a – b)(b – 2c)(c – a) ( c) 6(2a – b)(b – 2c)(c – a) (d) 2a × b × 2 c Which of the following is a binomial in y ? 1 + 2 (a) y2 + 2 (b) y + y 17. www.avte.in 18. (c) x x + x+ 1 (d) x3 + 2x a2 + b2 + c2 – ab – bc – ca equals : (c) ( a – b + c)2 (b) 31 (c) 21 (d) (d) 22 z1/3 If + + = 0, then which one of the following expressions is correct ? 19. www.avte.in 20. (c) x + y + z = 3xyz ( x + 2) is a factor of 2x3 + 5x2 – x – k. The value of k is : (a) 6 (b) –24 (c) –6 15 6 (b) 17 6 If x51 + 51 is divided by (x + 1), the remainder is : (a) 0 (b) 1 (c) 49 (d) 50 2 is a polynomial of degree : (c) 1 6 www.avte.in (d) 13 6 (b) 0 (c) 1 (d) 1 2 Which of the following is a polynomial in one variable ? (a) 3 – x2 + x (d) 24 What is the remainder when x3 – 2x2 + x + 1 is divided by (x – 1)? (a) 0 (b) –1 (c) 1 (d) 2 2 x x 2+ + x2 , then p(–1) is : If p ( x) = 2 3 (a) 21. (b) (a – b – c)2 1 [( a - b)2 + (b - c) 2 + (c - a)2 ] 2 (a) 2 (d) x3 + y3 + z3 = 3xyz 12. (b) x3 + x2 + x (b) –2x3 + x2 – x – 19 (b) x + y + z = 3x1/3y1/3z1/3 11. (a) x3 + 1 (c) 4 x3 + 13x – 25 If P(x) = 7 – 3x + 2x2, then value of P(–2) is : 1 (d) y y + Which of the following is a trinomial in x ? (a) ( a + b + c)2 (a) x3 + y3 + z3 = 0 10. y+ 2y (c) + 8(c – a) (b) x3 + x2 + x + 4 y1/3 3x+ 1 16. (a) 4 x3 – 13x + 6 x1/3 (d) The remainder when x2 + 2 x + 1 is divided by (x + 1) is : (a) 4 (b) 0 (c) 1 (d) –2 3 In which of the following ( x + 2) is a factor ? (a) 12 9. 2c)3 Which of the following is a polynomial inx ? 1 (a) x + (b) x2 + x x 15. (x2 5. Zero of the polynomialp(x) where p(x) = ax, a ≠ 0 is : 1 (a) 1 (b) a (c) 0 (d) a (c) x ++ 2 x2 1 – 1) – (x – 1) is : The coeffcient of x2 in (2 – 3x2)(x2 – 5) is : (a) –17 7. 14. The coefficient of x in the product of (x – 1)(1 – 2x) is : (a) x + 1 (b) x2 – 1 4. www.avte.in (a) f (0) (a) –3 13. (b) 3x+ 4 1 (d) x + x The value of p for which x + p is a factor of x2 + px + 3 – p is : (c) x3 + y3 + 7 22. (a) 1 23. (b) –1 (c) 3 (d) –3 The degree of the polynomial p(x) = 3 is : (a) 3 (b) 1 (c) 0 (d) 2 Follow us Maths4All AVTEOfficial 24. If x y + = - 1,( x, y ≠0), the value of x3 – y3 is : y x (a) 1 25. 26. 27. (b) –1 32. 29. 30. (b) 5 (c) –8 (d) 8 One of the factors of (16 y2 – 1) + (1 – 4y)2 is : (a) (4 + y) (b) (4 – y) (c) (4 y + 1) (d) 8 y If x2 + kx + 6 = (x + 2)(x + 3) for all x, the value of k is : (a) 1 (b) –1 (c) 5 (d) 3 Zero of the zero polynomial is : (a) 0 (b) 1 (c) any real number (d) not defned If ( x – 1) is a factor of p(x) = x2 + x + k, then value of k is : (b) 2 (c) –2 (d) 1 Evaluate using suitable identity (999) 3. x2 – x – 4. www.avte.in Factorise : 3 33. Using factor theorem, show that ( x + 1) is a factor of x19 + 1. 35. 36. 37. 38. 39. Check whether the polynomial p(s)=3s3+s2 -20s +12 is a multiple of 3 s – 2. 49. Factorise : 125 x3 + 27y3. 50. Find the value of x3 + y3 – 12xy + 64 when x + y = –4. 51. If x = 2y + 6, then fnd the value of x3 – 8y3 – 36xy – 216. 52. Factorise : 27( x + y)3 – 8(x – y)3. 53. Factorise : ( x – 2y)3 + (2y – 3z)3 + (3z – x)3. 54. If 2 a =3+2b , prove that 8a3 –8 b3 – 36ab = 27 55. If a – b = 7, a2 + b2 = 85, fnd a3 – b3. 56. The polynomials kx3 + 3x2 – 8 and 3x3 – 5x + k are divided by x + 2. If the remainder in each case is the same, fnd the value of k. 57. Find the values of a and b so that the polynomial x3 + 10x2 + ax + b has (x – 1) and (x + 2) as factors. 58. Factorise : 8 x3 + y3 + 27z3 – 18xyz. 59. If a2 + b2 + c2 = 90 and a + b + c = 20, then fnd the value of ab + bc + ca. www.avte.in 32. 34. 48. The coeffcient of x2 in (3x2 – 5)(4 + 4x2) is : (a) 3 31. If – 1 is a zero of the polynomial p(x) = ax3 - x2+ x+4 , find the : value of a (d) 0 (1 + 3 x)3 is an example of : (a) monomial (b) binomial (c) trinomial (d) none of these Degree of zero polynomial is : (a) 0 (b) 1 (c) any natural number (d) not defned (a) 12 28. (c) 1/2 47. Without actually calculating the cubes, fnd the value of 303 + 203 – 503. Evaluae (104) Find the 3 60. 61. Factorise : 64 a3 – 27b3 – 144a2b + 108ab2. 62. Simplify : ( a + b + c ) 2 +( + (a + b – c)2. using suitable identity. value of the polynomial 17 when z = 3. p( z ) = 3z 2 - 4 z + Check whether the polynomial t + 1 is a factor of 4t3 + 4t2 – t – 1. x 1 Factorise : x2 + - . 4 8 www.avte.in 1 9 1 Factorise : 27p3 - p2 + p. 216 2 4 -1 If x= is a zero of the polynomial p(x) = 27x3 3 – ax2 – x + 3, then fnd the value of a. 63. 64. a – b + c )2 Factorise : 4( x2 + 1)2 + 13(x2 + 1) – 12. 2 1 + 2 - 2x - . Factorise : x2 + 2 x x 65. Determine whether (3 x – 2) is a factor of 3x3 + x2 – 20x + 12 ? 66. Factorise:(2 x – y – z)3 + (2y – z – x)3 + (2z – x – y)3. 67. If a + b = 11, a2 + b2 = 61, fnd a3 + b3. 40. If 2 x + 3y = 8 and xy = 4, then fnd the value of 4x2 + 9y2. 68. 30 and a + a2 + b2 + c2 = b+ c= 10, then fnd the value of ab + bc + ca. 41. Check whether the polynomial 3 x – 1 is a factor of 9x3 – 3x2 + 3x – 1. Using factor theorem, show that (2 x + 1) is a factor of 2x3 + 3x2 – 11x – 6. 69. Using suitable identity evaluate : (42)3 - (18)3 - (24)3 . 70. Find the values of p and q, if the polynomial x4 +px 3 + 2x2 – 3x + q is divisible by the polynomial x2 – 1. 71. Simplify ( x + y + z)2 – (x + y – z)2. 72. Factorise 9x2 + y2 + z2 – 6xy + 2yz – 6zx. Hence fnd its value if x = 1, y = 2 and z = –1. 42. 43. Check whether (x +1) isa factor of x3+ x+ x2 +1 44. Find the value of a if (x – 1) is a factor of 2 x2 + ax + 2. 45. Factorise : 7 2x2 - 10 x - 4 2 . 46. If a + b + c = 7 and ab + bc + ca = 20, fnd the value of a2 + b2 + c2. Follow us Maths4All AVTEOfficial 73. Find the value of a3 + b3 + 6ab – 8 when a + b =2 74. If x + y + z = 9, then fnd the value of (3 – x)3 + (3 – y)3 + (3 – z )3 – 3(3 – x)(3 – y)(3 – z). 75. 1 x3 + y3 + z3 - 3 xy = (x+ y+ z) 2 [( x - y)2 + ( y - z) 2 + ( z - x)2 ]. 95. Verify : If x – 3 is a factor of x2 – kx + 12, then fnd the value of k. Also, fnd the other factor for this value of k. 96. 2 2 3 (b2 - c2 ) 3 + (c2 - a2 )3 Simplify : (a - b ) + . (a - b)3 + (b - c) 3 + (c - a)3 76. Find the value of x3 + y3 + 9xy – 27, if x + y =3 97. Prove that : 2 x3 + 2y3 + 2z3 – 6xyz = (x + y + z) 77. If a + b + c = 6, then find the value of (2 – a)3 + (2 – b)3 + (2 – c)3 – 3(2 – a)(2 – b)(2 – c). 78. 79. 80. 81. www.avte.in Factorise : 2 x3 – x2 – 13x – 6. 83. Factorise : a3(b – c)3 + b3(c – a)3 + c3(a – b)3. 84. If p = 4 – q, prove that p3 + q3 + 12pq = 64. 85. Find the value of k so that 2x – 1 be a factor of 8x4 + 4x3 – 16x2 + 10x + k. 86. x4 Using factor theorem show that x2 + 5x + 6 is factor of x4 + 5x3 + 9x2 + 15x + 18. 99. Prove that (x + y+ z) × [( x- y)2 + ( y - z) 2 ] = 2( x3 + y3 + z3 - 3xyz) 100. The polynomials p(x) = ax3 + 4x2 + 3x – 4 and q(x) = x3 – 4x + a leave the same remainder when divided by x – 3. Find the remainder when p(x) is divided by (x – 2). 101. If both ( x + 2) and (2x + 1) are factors of ax2+ 2 x + b, prove that a – b = 0. 102. Simplify by factorisation method : 6 - 2 2x - x2 . 2 - x2 Show that ( x – 1) is a factor of P(x) = 3x3 – x2 – 3x + 1 and hence factorise P(x). 103. ax + 8 x3 104. The polynomials x3 + 2x2 – 5ax – 8 and x3 + ax2 – 12x – 6 when divided by (x – 2) and (x – 3) leave remaindens p and q respectively. If q – p = 10 find the value of a . x2 105. Prove that ( x + y )3 –( x – y )3 –6 y(x2 – y2) = 8y3. 106. Find the value of ( x – a)3 + (x – b)3 + (x – c)3 – 3(x – a)(x – b)(x – c), if a + b + c = 3x. Simplify by factorisation method : 87. If the polynomial P(x) = –2 +3 – is divided by (x – 2), it leaves a remainder 10. Find the value of a 88. Simplify : ( a + b + c)2 – ( a – b – c)2. 107. 89. Factorise ( x – 3y)3 + (3y – 7z)3 + (7z – x)3. 108. 90. Factorise : 2 2a3 + 8b3 - 27c3 + 18 2abc. 91. Factorise : x6 – y6. 92. Find the value of a if (x + a) is a factor of x4 – a2x2 + 3x – a. 93. Factorise by splitting the middle term : 9(x – 94. 2y)2 – 4(x – 2y) – 13. 9 - 2 3x - x2 3 - x2 If p(x) = x3 – ax2 + bx + 3 leaves a remainder –19 when divided by (x + 2) and a remainder 17 when divided by (x – 2), prove that a + b = 6. 109. The volume of a cube is given by the polynomial p(x) = x3 –6 x2 + 12x – 8. Find the possible expressions for the sides of the cube. Verify the truth of your answer when the length of cube is 3 cm. 110. Using factor theorem, factorise the polynomial : x4 + 3x3 + 2x2 – 3x – 3. 111. Factorise a7 + ab6. 112. Using factor theorem, factorise the polynomial. www.avte.in Find the remainder obtained on dividing 1 2x4 - 3x3 - 5x2 + x+ 1 by x- . Follow us 2 98. What are the possible expressions for the dimensions of the cuboids whose volume is given below ? Volume = 12 ky2 + 8ky – 20k. 2 2(7)3 + 2(9)3 + 2(13)3 – 6(7) (9) (13). If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c. 1 1 3 . If x + = 7, then find the value of x + x x3 1 1 3 If x - = 3, then fnd the value of x - 3 . x x 3 2 If ax + bx + x – 6 has (x + 2) as a factor and leaves a remainder 4 when divided by x – 2, fnd the values of a and b. 82. 2 [( x – y) + (y – z) + (z – x) ]. Hence evaluate x4 + 2x3 – 7 x2 – 8x + 12. Maths4All AVTEOfficial 4 3 2 113. Without actual division, show that the polynomial 2x4 – 5x3 + 2x2 – x + 2 is exactly divisible by x2 – 3x + 2. 125. Without actual division, prove that 2 x – 8x. + 3x + 12x – 9 is exactly divisible by x2 – 4x + 3. 114. If x and y be two positive real numbers such that 8x3 + 27y3 = 730 and 2x2y +3 xy2 = 15, then evaluate 2x + 3y. 126. If f(x) = x4 – 2x3 + 3x2 – ax + b is divided by (x – 1) and (x + 1), it leaves the remainders 5 and 19 respectively. Find a and b. 115. Factorise : ( x2 – 2x)2 – 2(x2 – 2x) – 3. 127. If x2 – 3x + 2 is a factor of x4 – ax2 + b then fnd a and b. 128. Without actual division show that x4 + 2x3 – 2x2 + 2x – 3 is exactly divisible by x2 + 2x – 3. 129. 1 27a2 9a Factorise : 27a3 + + + . 3 4 b 16b2 64b 116. 1 = 51, fnd If x2 + x2 1 1 x(i) (ii) x3 - 3 . x x www.avte.in 117. Find the values of m and n so that the polynomial f(x) = x3 – 6x2 + mx – n is exactly divisible by (x – 1) as well as (x – 2). 118. Factorise : x8 – y8. 119. x4 2x3 Without actual division prove that + – + 2x – 3 is exactly divisible by x2 + 2x – 3. 130. Find the values of a and b so that (x + 1) and (x – 2) are factors of (x3 + ax2 + 2x + b). 131. Wi t h o u t a c t u a l d i v i s i o n , p r o v e t h a t (2x4 - 6x3 + 3x2 + 3x - 2) is exactly divisible by 2x2 ( x2 - 3 x + 2). 120. Factorise : a12x4 – a4x12. 132. Simplify : (5 a + 3b)3 – (5a – 3b)3. 121. Without actual division, prove that the polynomial 2x4 – 5x3 + 2x2 – x + 2 is exactly divisible by x2 – 3x + 2. 133. Find the value of a if (x – a) is a factor of x5 – a2x3 + 2 x + a + 3, hence factorisex2 – 2 ax – 3. 122. Factorise : ( x2 – 3x)2 – 8(x2 – 3x) – 20. 134. The polynomial ax3 + 3x2 – 3 and 2x3 – 5x + a when divided by x – 4 leave the same remainder in each case. Find the value of a. 135. Factorise : 3 u3 – 4u2 – 12u + 16. 1 1 . If x + = 5 , then evaluate x6 + x x6 Multiply 9 x2 + 25y2 + 15xy + 12x – 20y + 16 by 3x – 5y – 4 using suitable identity. 123. 124. The polynomial p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by (x + 1), leaves the remainder 19. Find the value of a. Also, fnd the remainder, when p(x) is divided by x + 2. Find the values of a and b so that (x + 1) and (x – 1) are factors of x4 + ax3 – 3x2 + 2x + b. Follow us Maths4All www.avte.in 136. 137. AVTEOfficial
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