自然科學與教育 2015,第一期第二卷,63-64 Natural Science and Education 2015,1(2),63-64 A Generalized Basis Representation Theorem Kuo-Jye Chen Department of Mathematics, National Changhua University of Education [email protected] We present a generalized basis representation theorem. Key words: basis representation Classiciation :Mathematics In this note, we will present a generalized basis representation theorem (Theorem 1 below). The proof uses Andrews’ s idea [1] and the following simple lemmas. Lemma 1. Let a0 , a1 , a2 , … be a sequence of positive integers. Then (1 a0 )(1 a1 )(1 a2 ) (1 an ) 1 a0 (1 a0 )a1 (1 a0 )(1 a1 )a2 (1 a0 )(1 a1 )(1 a2 ) (1 an1 )an . Lemma 2. Let a0 , a1 , a2 , … be a sequence of positive integers. Then, for any integer n 0, n 1 a0 1 a1 1 a2 1 a j 1 . These two lemmas can be readily proved by induction. Our main theorem is Theorem 1. (Generalized Basis Representation Theorem) Let a0 , a1 , a2 , … be a sequence of positive integers. Let B j be defined by B0 1 and B j = 1 a0 1 a1 1 a2 1 a j 1 for j 1. Then every integer n 0 can be uniquely expressed in the form Where d j n d0 B0 d1B1 d2 B2 , is an integer satisfying 0 d j a j . Proof. Let R n denote the number of representations of a nonnegative integer n in the form (1). Note that R 0 1 . Let n 1 and assume that n d0 B0 d1B1 d2 B2 0 d j a j is a representation for n . If d0 0, then n 1 d0 1 B0 d1B1 d2 B2 . 0 d j a j , d0 1 is a representation for n 1. If d0 0, then there exists a positive integer m such that n dm Bm dm 1Bm1 dm 2 Bm 2 . 0 d j a j , m 1, dm 1 It follows from Lemma 1 that n 1 Bm 1 d m 1 Bm d m 1Bm1 a0 B0 a1 B1 a2 B2 am1Bm1 d m 1 Bm d m1Bm1 , which is a representation for n 1. (1) A Generalized Basis Representation Theorem Thus we have shown that R n R n 1 . n 1 64 2 Note that (2) holds even if n has no representation. It follows from (2) and Lemma 2 that 1 R Bn R n R n 1 R 0 1. Therefore R n 1, n 0 which completes the proof of the theorem.□ Specializations. Two well-known basis representation theorems follow as special cases. Corollary 1. Let k be a positive integer 2 . Then every integer n 0 can be uniquely written as n d0 d1k d2 k 2 d3k 3 , where d j is an integer satisfying 0 d j k 1. Proof. In Theorem 1, put a j k 1 , for all j 0. □ Corollary 2. Every integer n 0 can be uniquely written as n d01! d1 2! d2 3! d3 4! , where d j is an integer satisfying 0 d j j 1. Proof. In Theorem 1, put a j j 1 , for all j 0. □ References 1.Andrews, George E., On radix representation and the Euclidean algorithm, Amer. Math. Monthly 76 (1969), pages 66-68.
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