Advanced Algebra and Trigonometry Summer Packet

Directions: Simplify.
1. (6 + 5i) + (−3+ 2i)
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3. (1+ 8i)(6 + 2i)
5.
3+i
5 − 2i
2. (−3+ 4i) − (4 − 5i)
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6.
−3 + i
4 − 3i
Directions: Determine whether each function has a maximum or minimum. Then find
the value of the maximum or minimum, €
and state the domain and range of the function.
7.
8.
Directions: Solve each equation.
9. x 2 − x − 20 = 0
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4. (−3+ 3i)(−2 + 2i)
11. x 2 + 2x −1 = 0
Directions: Simplify each expression.
13.
6
x12 y15
25r 5t 4 u2
15.
10. x 2 − 3x + 5 = 0
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12. x 2 +11x + 24 = 0
14.
3
8a9b7
16.
5
32x11y 20z 5
18.
4
81x 8 y14
1
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17.
x2
x
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1
4
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19.
7
8
x15 y 23
20.
6
49
7
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€ State whether the system is consistent and
Directions: Solve each system of equations.
independent, consistent and dependent, or inconsistent.
3x + y = 4
2x − y = 2
21.
22.
x − y = 12
−4 x + 2y = −4
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2x + 4 y − z = −1
23. 2x − 3y + 2z = 6
−x − 5y + z = −2
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€ If the system has no solution, state no
Directions: Solve each system of inequalities.
solution.
y ≥ x +5
y+x <3
25.
26.
y ≤ 2x + 2
y > −2x − 4
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27.
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−3x + 9y − 3z = −12
24. −3x + y − z = −1
2x − 6y + 2z = 9
4 x − 3y < 7
2y − x < −6
3y ≤ 2x − 8
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28.
2
y ≥ x −1
3
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Directions: Answer the following word problems.
29. CARS The current value V and the original v of a car are related by the function
V = v(1− r)n , where r is the rate of depreciation per year and n is the number of
years. If the original value of a car is $10,000, what would be the current value of the
car after 30 months at an annual depreciation rate of 10%?
30. JOBS Destiny mows lawns for $8 per lawn and weeds gardens for $10 per garden. If
she had 8 jobs and made $72, how many of the jobs were mowing? How many were
weeding?
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Directions: Factor the following completely.
31. 2a 2 + 2a − 84
32. x 2 − 5x −14
33. 2x 2 − 50
34. 3x 2 −15x − 42
35. x 3 − x 2 − 6x
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Directions: Evaluate the following logarithmic and exponential expressions.
36. log5x = log(2x + 9)
37. log(10 − 4 x) = log(10 − 3x)
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38. −10 + log 3 (n + 3) = −10
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2
40. ln(n +12) = ln(−9n − 2)
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39. log− m + 2 = 4