IB Math 11 Test: Ch. 3, 4, 5 – Exponents & Logs 1. The following diagram shows the graph of NAME:________________________ y y = 3–x + 2. The curve passes through the points (0, a) and (1, b). (a) Find the value of (i) (0, a) O (ii) (1, b) a; x b. Diagram not to scale (b) Write down the equation of the asymptote to this curve. (Total 8 marks) 2. Solve log 2 x + log 2 ( x − 2) = 3 , for x > 2. (Total 7 marks) 3. Let f ( x) = log 3 (a) x = log 3 16 − log 3 4 , for x > 0. 2 Show that f ( x) = log 3 2 x . (2) (b) Find the value of f(0.5) and of f(4.5). (3) The function f can also be written in the form f(x) = (c) ln ax . ln b (i) Write down the value of a and of b. (ii) Hence on graph paper, sketch the graph of f, for –5 ≤ x ≤ 5, –5 ≤ y ≤ 5 y 4 2 x −4 −2 2 4 −2 −4 (iii) Write down the equation of the asymptote. (6) (d) Write down the value of f–1(0). (1) The point A lies on the graph of f. At A, x = 4.5. (e) On your diagram, sketch the graph of f–1, noting clearly the image of point A. (4) (Total 16 marks) 4. (a)Find log 2 32 . (1) (b) 32 x Given that log 2 y can be written as px + qy, find the value of p and of q. 8 (4) (Total 5 marks) 5. Find the exact solution of the equation 92x = 27(1–x). (Total 6 marks) 6. Given that log5 x = y, express each of the following in terms of y. (a) log 5 x 2 (b) 1 log 5 x (c) log 25 x (Total 6 marks) 7. A machine was purchased for $10000. Its value V after t years is given by V =100000e−0.3t. The machine must be replaced at the end of the year in which its value drops below $1500. Determine in how many years the machine will need to be replaced. (Total 6 marks) 1. (a)(i) y = 3–0 + 2 y=1+2 a=3 (ii) (M1) (A1) (A1) (C3) y = 3–1 + 2 (M1) 1 +2 3 1 b=2 3 y= (b) (A1) (A1) (C3) y=2 (A2) (C2) Note: Award (A1) for y = any constant. [8] 2. recognizing log a + log b = log ab (seen anywhere) e.g. log2(x(x – 2)), x2 – 2x (A1) recognizing loga b = x ⇔ ax = b (seen anywhere) e.g. 23 = 8 (A1) correct simplification e.g. x(x – 2) = 23, x2 – 2x – 8 A1 evidence of correct approach to solve e.g. factorizing, quadratic formula (M1) correct working e.g. (x – 4)(x + 2), A1 2 ± 36 2 x=4 A2 N3 [7] 3. (a) combining 2 terms (A1) e.g. log3 8x – log3 4, log3 1 x + log3 4 2 expression which clearly leads to answer given e.g. log 3 8x 4x , log 3 3 2 f(x) = log3 2x (b) A1 attempt to substitute either value into f AG N0 2 (M1) e.g. log3 1, log3 9 (c) f(0.5) = 0, f(4.5) = 2 A1A1 (i) A1A1 a = 2, b = 3 N3 3 N1N1 (ii) A1A1A1 Note: Award A1 for sketch approximately through (0.5 ± 0.1, 0 ± 0.1) A1 for approximately correct shape, A1 for sketch asymptotic to the y-axis. (iii) x = 0 (must be an equation) A1 N3 N1 [6 (d) (e) f–1(0) = 0.5 A1 N1 1 A1A1A1A1 Note: Award A1 for sketch approximately through (0 ± 0.1, 0.5 ± 0.1), A1 for approximately correct shape of the graph reflected over y = x, A1 for sketch asymptotic to x-axis, A1 for point (2 ± 0.1, 4.5 ± 0.1) clearly marked and on curve. N4 4 [16 4. (a) 5 A1 N1 (b) METHOD 1 32 x log 2 y 8 = log 2 32 x − log 2 8 y (A1) = x log2 32 – y log2 8 (A1) log2 8 = 3 (A1) p = 5, q = –3 (accept 5x – 3y) A1 N3 METHOD 2 32 x 8y = (2 5 ) x (2 3 ) y (A1) = 25x (A1) 23y = 25x–3y (A1) log2 (25x–3y) = 5x – 3y p = 5, q = –3 (accept 5x – 3y) A1 N3 [5] 5. METHOD 1 9 = 32 , 27 = 33 (A1)(A1) expressing as a power of 3, (32 )2 x = (33 )1− x (M1) 34 x = 33−3 x (A1) 4 x = 3 − 3x (A1) 7x = 3 ⇒x= 3 7 (A1) (C6) METHOD 2 2 x log 9 = (1 − x ) log 27 2x log 27 = = 1 − x log 9 (M1)(A1)(A1) 3 2 (A1) (A1) 4 x = 3 − 3x 7x = 3 ⇒x= 3 7 (A1) (C6) Notes: Candidates may use a graphical method. Award (M1)(A1)(A1) for a sketch, (A1) for showing the point of intersection, (A1) for 0.4285…., and (A1) for 3 . 7 [6] 6. (a) log5 x2 = 2 log5 x = 2y (b) (M1) (A1) (C2) log5 1 = –log5 x (M1) x = –y (c) (A1) (C2) log 5 x log 5 25 1 = y 2 log25 x = (M1) (A1) (C2) [6] 7. 10 000e− 0.3t = 1500 For taking logarithms − 0.3t ln e = ln 0.15 t= (A1) (M1) (A1) ln 0.15 − 0.3 (A1) = 6.32 (A1) 7 (years) (A1) (C6) Note: Candidates may use a graphical method. Award (A1) for setting up the correct equation, (M1)(A1) for a sketch, (A1) for showing the point of intersection, (A1) for 6.32, and (A1) for 7. [6]
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