Mm? 4U1 Double An2le Identities 1 Use a Double Angle identity to rewrite each expression. . a) cos(2(2x)) b) sin(3x) c) tan(6x) d) sin(!xJ e) f) tan(— 7x) cosxJ 2. Express as a single Sine or Cosine function. a) 2sin(3x)cos(3x) cos2J d) _ sin2J — 2cos2J — _ 1 h) 1 2sin2 — and A is in the interval evaluate the following: a) sin(2A) andA is in the interval (ir-?J evaluate the following: a) sin(2A) 4. If sinA = 5. If sinA = 3 6. If cos A = 7. If tan A = 8. If tan A 1 2s2J e) (2x)— 4 2 g) 8sin 3. If cos A = c) !sinJcos(J b) 6sinxcosx = , , 2 b) cos(2A) and A is in the interval O, find the value of sin(4A). L 2) and A is in the interval -2,rJ evaluate the following: a) csc(2A) --- b) cos(2A) and A is in b) sec(2A) the interval O, find the value of tan(2A). i\ 2) , 2 and A is in the interval ( 2,r__J find the value of tan(4A). , 9. Find the exact value of each by using a Double Angle Identity. a) sin.J b) cos.J c) tan(22.5 ) d) cosJ e) sin_ !J Answers: 2 (2x) (any of the three variations) b) 2sinxJcosxJ c) 2 tan(3x) #1 a) cos 2 (2x)— sj 2 2 1—tan (3x) (7 —2tanL—x d) 2s-_xJcos_xJ e) cos 2 -xJ sin 2 -.xJ (or any of the three variations) f) — 2 #2 a) s(6x) b) 3s(2x) c) s(x) d) cos(3x) e) cosJ #3 a) #6a) #9 a) — .: 25 b) 25 — 4ñi I-J+i 2 #4 a) -- 25 b) b) 25 #7 —— 17 L/—i - 2 c) - 1+ 169 b) cos(7x) g) #5 — 169 4 #8 — 3 d) iJ•+i 2 e) I/—i - 2 81 24 — 7 — 4cos(4x) h) sin(x) 7 ‘I’ 4)— 7 tfl r it’ ‘4 ‘Is’ 0 ;c !f ) IL,) F ‘q% :1, - r’ - :‘ ,3 )C - ?‘ -‘- _i___ —( ,3 V ,, 1 ‘I I, - - - ) -- - — “% ‘4) ?c - .,( % -‘ -- %%1’ -, ,4 4Is - -p- : -: - ;_ ‘ - : --- .-‘ ‘ —. I%__ e’M - 7 11 —— P -_-i’ ? -,‘r -‘p ?. ‘I — - —— - - %2 —— —— — — — _j — — —- N I %fr i!v’ I r IlL I ,0 ‘p ‘p ‘3 F, p 1 i? , ‘3 %J ‘S ‘I C-’ ÷ _D1 H 4 3 p /‘ ,? 141 ‘C ‘—9 I a,i , ‘ ‘I’ 7 ii 1 (, \; . I rs L I, ‘ ‘e— -C -% 1 ,, z ) , I I ‘1 If ‘4 11 e ‘1 cfr4 I’ (% •v, a t %% ‘:131 r f%%\ , 1__ ‘I £ LJ 1 ‘%__‘‘ Mrz %% %_‘ :r9 2 ji oJL %3 0 J)%D ‘, II ,, ?t ! 9 1 ‘1 r%’ ‘3 ) ?‘ — “I oJ , +1 QJ 1 VI) tø tl ) r ‘1 ‘$1 G £ •r’ 0% _ I ‘p t4i 1’ ± L’ ç4jf% 43 ‘4 i ‘C (%sj I, I’ c) 4: (4 ‘4) ‘4) V I’ IL 4: ‘ 0 (p “4 IL (S j 4 (%4t I. flç4 I 1eoc 4 r 1 4 mb4r 7.’ r L jN1 ‘4 d ‘ •F ’ 41 L I ,Jc%1 C’ I 4 _ rH if’ c\’J I T (4 •1 ri 1(i%b Hri .A1v, j I r II N ii v’ ¶3 ‘3 £ 1.1 >- ‘I ‘3 I ia 1+ 9) I :ih Jjr - I cA ‘I ,94 11 a vs - H )• 3_ ,., I 0 p 1 _1 I -13 ii 43 11 , r : .1’ 4 1 I” fr Ca 0 q’J ‘3 I i 4 Sej c it4c d %% I L- ii ti .
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