Acids, Bases, and Salts Review for Sections 4.1 – 4.9 1. Consider the following: I II III H2CO3 + F- HCO3- + HF HCO3- + HC2O4- H2CO3 + C2O42HCO3- + H2C6H6O7- H2CO3 + HC6H5O72- The HCO3- is a base in A. B. C. D. 2. The volume of 0.200 M Sr(OH)2 needed to neutralize 50.0 mL of 0.200 M HI is A. B. C. D. 3. 0.050 1.30 12.70 13.70 The volume of 0.450 M HCl needed to neutralize 40.0 mL of 0.450 M Sr(OH)2 is A. B. C. D. 5. 10.0 mL 25.0 mL 50.0 mL 100.0 mL The pOH of 0.050 M HCl is A. B. C. D. 4. I only I and II only II and III only I, II, and III 18.0 mL 20.0 mL 40.0 mL 80.0 mL Consider the following I H3PO4 II H2PO4- III HPO42- IV PO43- Which of the following solutions will have the largest [H30+]? A. B. C. D. 6. Which of the following solutions will have the largest [H3O+]? A. B. C. D. 7. I and II only II and III only I, II, and III only II, III, and IV only 1.0 M HNO2 1.0 M HBO3 1.0 M H2C2O4 1.0 M HCOOH Consider the following: H2O + 57 kJ H3O+ + OH- When the temperature of the system is increased, the equilibrium shifts A. B. C. D. left and the Kw increases left and the Kw decreases right and the Kw increases right and the Kw decreases _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts 8. A 1.0 M solution of sodium dihydrogen phosphate is A. B. C. D. 9. A Bronsted-Lowry base is defined as a chemical species that A. B. C. D. 10. accepts protons neutralizes acids donated electrons produces hydroxides ions in solution Which of the following solutions will have the greatest electrical conductivity? A. B. C. D. 11. acidic and the pH < 7.00 acidic and the pH > 7.00 basic and the pH < 7.00 basic and the pH > 7.00 1.0 M HCN 1.0 M H2SO4 1.0 M H3PO4 1.0 M CH3COOH Consider the following equilibrium: HC6H5O72- + HIO3 H2C6H5O7- + IO3The order of Bronsted-Lowry acids and bases is A. B. C. D. 12. acid, base, acid, base acid, base, base, acid base, acid, acid, base base, acid, base acid Consider the following: H2O(l) H+ + OHWhen a small amount of 1.0 M KOH is added to the above system, the equilibrium A. B. C. D. 13. Which of the following has the highest pH? A. B. C. D. 14. shifts left and [H+] decreases shifts left and [H+] increases shifts right and [H+] decreases shifts right and [H+] increases 1.0 M NaIO3 1.0 M Na2CO3 1.0 M Na3PO4 1.0 M Na2SO4 In a 100.0 mL sample of 0.0800 M NaOH the [H3O+] is A. B. C. D. 1.25 1.25 8.00 8.00 x x x x 10-13 M 10-12 M 10-3 M 10-2 M _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts 15. Consider the following: I ammonium nitrate II calcium nitrate III iron III nitrate When dissolved in water, which of these salts would form a neutral solution? A. B. C. D. 16. II only III only I and III only I, II, and III Consider the following: SO42- + HNO2 HSO4- + NO2Equilibrium would favour the A. B. C. D. 17. The net ionic equation for the hydrolysis of Na2CO3 is A. B. C. D. 18. the products since HSO4- is a weaker acid than HNO2 the reactants since HSO4- is a weaker acid than HNO2 the products since HSO4- is a stronger acid than HNO2 the reactants since HSO4- is a stronger acid than HNO2 H2 O H2 O H2 O H2O + + + + Na+ NaOH + H+ 2Na+ Na2O + 2H+ CO32- H2CO3 + O2CO32- HCO3- + OH- Consider the following equilibrium: 2H2O(l) H3O+ + OHA few drops of 1.0 M HCl are added to the above system. When equilibrium is re-established, the A. B. C. D. 19. A basic solution A. B. C. D. 20. tastes sour feels slippery does not conduct electricity reacts with metals to release oxygen gas The balanced formula equation for the neutralization of H2SO4 by KOH is A. B. C. D. 21. [H3O+] has increased and the [OH-] has decreased [H3O+] has increased and the [OH-] has increased [H3O+] has decreased and the [OH-] has increased [H3O+] has decreased and the [OH-] has decreased H2SO4 H2SO4 H2SO4 H2SO4 + + + + KOH → KSO4 + H2O KOH → K2SO4 + H2O 2KOH → K2SO4 + H2O 2KOH → K2SO4 + 2H2O An Arrhenius base is defined as a substance which A. B. C. D. donates protons donates electrons produces H+ in solution produces OH- in solution _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts 22. Consider the following equilibrium: HS- + H3PO4 H2S + H2PO4The order of Bronsted-Lowry acids and bases is A. B. C. D. 23. The equation representing the reaction of ethanoic acid with water is A. B. C. D. 24. acid, base, acid, base. acid, base, base, acid base, acid, acid, base base, acid, base, acid CH3COO- + H2O CH3COOH + OHCH3COO- + H2O CH3COO2- + H3O+ CH3COOH + H2O CH3COO- + H3O+ CH3COOH + H2O CH3COOH2+ + OH- Consider the following equilibrium: 2H2O + 57kJ H3O+ + OHWhen the temperature is decreased, the water A. B. C. D. 25. The conjugate acid of C6H50- is A. B. C. D. 26. 1.0 M HCl 1.0 M HNO2 1.0 M H3BO3 1.0 M HCOOH A solution of 1.0 M HF has A. B. C. D. 28. C6H4OC6H5OH C6H4O2C6H5OH+ Which of the following solutions will have the greatest electrical conductivity? A. B. C. D. 27. stays neutral and the [H3O+] increases stays neutral and the [H3O+] decreases becomes basic and [H3O+] decreases becomes acidic and [H3O+] increases a lower pH than a solution of 1.0 M HCl a higher pOH than a solution of 1.0 M HCl a higher [OH-] than a solution of 1.0 M HCl a higher [H3O+] than a solution of 1.0 M HCl Which of the following is the weakest acid A. B. C. D. HIO3 HCN HNO3 C6H5COOH _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts 29. Considering the following data Ka = 5.0 x 10-5 Ka = 8.0 x 10-8 Ka = 6.0 x 10-10 H3AsO4 H2AsO4HAsO42- The Kb value for H2AsO4- is A. B. C. D. 30. 10-10 M 10-5 M 10-1 M 104 M x x x x basic because Ka < Kb basic because Ka > Kb acidic because Ka < Kb acidic because Ka > Kb HSO4- + H2O SO42HSO4- + H2O H2SO4 KHSO4 + H2O K+ + KHSO4 + H2O K+ + + H3O+ + OHSO42- + H3O+ H2SO4 + OH- The [OH-] in an aqueous solution always equals A. B. C. D. 35. 1.7 6.0 6.3 1.7 The net ionic equation for the predominant hydrolysis reaction of KHSO4 is A. B. C. D. 34. 10-20 M 10-9 M 10-7 M 10-6 M x x x x An aqueous solution of NH4CN is A. B. C. D. 33. 3.5 2.9 1.0 3.5 In a solution with a pOH of 4.22, the [OH-] is A. B. C. D. 32. 10-10 10-8 10-7 10-5 x x x x In a solution at 25oC, the [H3O+] is 3.5 x 10-6 M. The [OH-] is A. B. C. D. 31. 2.0 8.0 1.2 1.7 Kw x [H3O+] Kw - [H3O+] Kw/[H3O+] [H3O+]/Kw The [H3O+] in a solution with pOH of 0.253 is A. B. C. D. 5.58 1.79 5.58 5.97 x x x x 10-15 M 10-14 M 10-1 M 10-1 M _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts 36. 37. The equilibrium expression for the hydrolysis reaction of 1.0 M K2HPO4 is A. [H2PO42-][OH-] [HPO4-] C. [K+] [KHPO4-] [K2HPO4] D. [H3PO4][OH-] [H2PO4-] [K+]2 [HPO42-] [K2HPO4] The solution with the highest pH is A. B. C. D. 38. B. 1.0 M NaCl 1.0 M NaCN 1.0 M NaIO3 1.0 M Na2SO4 The pH of 100.0 mL of 0.0050 M NaOH is A. B. C. D. 2.30 3.30 10.70 11.70 Written Response Practice 1. a) Write the net ionic equation for the reaction between NaHSO3 and NaHC2O4. HSO3- + HC2O4- H2SO3 + C2O42- b) Explain why the reactants are favoured in the above reaction. H2SO3 is a stronger acid than HC2O4- 2. What is the [H3O+] in a solution formed by adding 60.0 mL of water to 40.0 mL of 0.400 M KOH? KOH 40 100 → x 0.400 M [H+][OH-] = 1.0 x 10-14 K+ + 0.160 M OH0.160 M [H+] = 6.3 x 10-14 M 3. Calculate the pH of the solution formed by mixing 20.0 mL of 0.500 M HCl with 30.0 mL of 0.300 M NaOH. HCl + NaOH → NaCl + H2O 0.200 L x 0.500 mole = 0.01000 mole HCl 0.300 L x 0.300 mole = 0.00900 mole NaOH L L Total new volume = 20.0 mL + 30.0 mL = 50.0 mL = 0.0500 L [H+] = 0.0010 moles = 0.020 M 0.0500 L _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts pH = 1.70 4. a) Write the balanced equation representing the reaction of HF with H2O. HF + H2O H3O+ + F- b) Identify the Bronsted-Lowry bases in the above equation. H2O 5. and F- Consider the following data: Barbituric acid Sodium propanoate Propanoic acid Ka = 9.8 x 10-5 Kb = 7.5 x 10-10 Ka = ? HC4H3N2O3 NaC3H5O2 HC3H5O2 Which is the stronger acid, propanoic acid or babituric acid? Explain using calculations. Ka (HC4H3N2O3) = Kw Kb(C3H5O2-) = 1.0 x 10-14 7.5 x 10-10 = 1.3 x 10-5 Barbituric acid is a stronger acid because it has a larger Ka. 6. a) b) Write equations showing the amphiprotic nature of water as it reacts with HCO3-. HCO3- + H2O H3O+ + CO32- HCO3- + H2O H2CO3 + OH- Calculate the Kb for HCO3-. Kb (HCO3-) = Kw Ka(H2CO3) = 1.0 x 10-14 4.3 x 10-7 = 2.3 x 10-8 _____________________________________________________________________________________________ Chemistry 12 Acids, Bases, and Salts
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