Name____________________________________________________Date_____________________Period___________
IP/Homework (DUE 1/19 (B) & 1/20(A)): Pythagorean Theorem
1. If c represents the length of the hypotenuse of a right triangle and a and b represent the lengths of the legs, solve
for the length of the missing side in each case. Express your answers in simplest radical form and then as a decimal
to the nearest hundredth.
a. a = 6 and b = 4
b. a = 9 and c = 18
c. a = 5 and b = 4√2
2. Find the length of each missing side.
Express your answers in simplest radical form and as a decimal rounded to the nearest hundredth.
a.
b.
c.
5
5√3
q
3. Find the values of x and y. Leave answer in simplest radical form if necessary.
x
y
7
4. A baseball diamond has the shape of a square measuring 90 feet on each side. Approximate, to the nearest
hundredth of a foot, the distance from home plate to second base. Hint: Label the picture below.
5. For each of the following, tell whether the sets of numbers represent a Pythagorean Triple. Explain.
a. 5, 3.2, 4.1
b. 8, 17, 15
c. 3, 4, 6
6. Is Pythagorean Theorem applicable to all triangles? Why or why not?
7. How do you know which side of a right triangle is the hypotenuse?
8. At GainSaver.com, a refurbished Apple Macbook is being sold for $206.10. The screen for is listed as 13.3 inches,
which represents the diagonal distance across the screen. If the screen measures 8.9 inches in height, what is the
width to the nearest hundredth of an inch?
9. Which of the following sets of numbers represents sides that would form a right triangle? (circle one)
A
B
5, 3.2, 4.1
C
3.6, 6, 4.8
D
4.5, 8, 6.7
8.5, 5.2, 10
10. Ms. Sampson and Ms. Pfister are located at point A and Ms. Hooker is located at point B.
b. If Ms. Sampson travels by boat directly across the pond, how far does she travel to get to Ms. Hooker?
c. If Ms. Pfister walks around the pond by going south and then east, how far does she walk to get to Ms.
Hooker?
d. How much shorter was Ms. Sampson’s trip?
11. Simplify the following:
a. 2√6 • 3
b. √6 • √2
c. √6 + 3√5