Lesson 7.2.notebook 7. Trigonometric Integrals October 09, 2013 Example 1: Page 471 We do not have our u and du part to integrate. u=cos(x) du=sin(x)dx THUS In this section we use trigonometric identities to integrate certain combinations of trigonometric functions. u=sin(x) du=cos(x)dx We start with powers of sine and cosine. (even exponents with odd du Mar 15:27 PM Mar 210:15 AM Example 2: Find ∫ sin5x cos2x dx. In general we try to write an integrand involving powers of sine and cosine in a form where we have only one sine factor (and the remainder of the expressions in terms cosine) Solution: We could convert cos2x to 1 – sin2x, but we would be left with an expression in terms of sin x with no extra cos x factor. Instead, we separate a single sine factor and rewrite the remaining sin4x factor in terms of cos x: or only one cosine factor (and the remainder of the expression in terms of sine. Mar 210:32 AM Example 3: Evaluate Solution: If we write sin2x = 1 – cos2x, the integral is no simpler to evaluate. Using the halfangle formula for sin2x, however, we have sin5 x cos2x = (sin2x)2 cos2x sin x = (1 – cos2x)2 cos2x sin x Mar 15:27 PM Trigonometric Integrals To summarize, we list guidelines to follow when evaluating integrals of the form ∫ sinmx cosnx dx, where m ≥ 0 and n ≥ 0 are integers. Property Mar 15:27 PM Mar 15:27 PM 1 Lesson 7.2.notebook October 09, 2013 Evaluate ∫ tan6x sec4x dx. Solution: If we separate one sec2x factor, we can express the remaining sec2x factor in terms of tangent using the identity sec2x = 1 + tan2x. Trigonometric Integrals For other cases, the guidelines are not as clearcut. We may need to use identities, integration by parts, and occasionally a little ingenuity. We will sometimes need to be able to integrate tan x by using the formula given below: We will also need the indefinite integral of secant: Mar 15:27 PM Mar 15:27 PM Find ∫ tan3x dx. Solution: Here only tan x occurs, so we use tan2x = sec2x – 1 to rewrite a tan2x factor in terms of sec 2x: ∫ tan3x dx = ∫ tan x tan2x dx = ∫ tan x (sec2x – 1) dx = ∫ tan x sec2x dx – tan x dx u du Mar 15:27 PM Mar 15:27 PM Example: Evaluate ∫ sin 4x cos 5x dx. Solution: Pink Sheet Property Homework Lesson 7.2 Page 476 (127odd) Due on Friday (2,4,20,29,38) Mar 15:27 PM Mar 211:26 AM 2
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