Master’s Degree and Internship Program
of the African Business Education Initiative for Youth (ABE Initiative)
(3rd Batch)
Examination for Mathematics (45 min.)
Note:
1. Rules of Examination
Do not leave the room without proctor’s permission.
Do not take this question booklet out of the room.
No calculators are allowed.
Show all your work in blank spaces and write your answers in the
space provided.
2. Instruction for the Question booklet
Do not open this question booklet until instructed.
Do not remove the staples from this booklet.
After being instructed, write your registration number and name in
the space provided below.
If your question booklet is missing any pages, raise your hand.
This question booklet consists of 2 parts (Part1 and Part 2). You are
requested to answer all the questions.
Registration No.
Name
(Type A)
Part 1
Write down your answer for each question.
(1) Calculate 4 − {1 − (2 − 6) − 7}.
Answer:
(2) Calculate
×
−
÷ −
6
.
Answer:
(3) Calculate 4
×
÷2
.
Answer:
2 =8
(4) Solve 2x − 8 = 1 + 5x for x.
Answer:
x = −3
(5) Solve x + y − 24 = 0 and −2x − 6y + 4 = 0 for x and y.
Answer:
x = 35, y = −11
Answer:
x = −15, 3
(6) Solve 45 − x + 5x = 17x for x.
(7) Suppose that the average of the five values, {−1, 2, 1 − 2x, x, 5}, is equal
to x. Find the value of x.
Answer:
x=
Part 2
Write down your answer for each question.
(8) Find the region of x satisfying
≤ 1.
Answer:
(9) Solve 10
−1 ≤ x ≤ 3
= 1.
Answer:
x = 0,2
(10) Find the region of x satisfying log (2x − 1) < 0.
Answer:
< 𝑥< 1
(11) Find the positive value of n satisfying
2
= 63
Answer:
n=6
(12) Find the first-derivative of y = x [ln(x) − 1]. Note that ln (x) is the log of x
with the base of the exponential, e, which is approximately equal to 2.718.
Answer:
y = ln (x)
(13) Find the definite integral:
√𝑥 dx
Answer:
(14) Let A =
x−1
1
1 − 2x
. Suppose the determinant of A is zero, so that A
2
is not invertible. Solve for x
Answer:
x=
(15) Assume that 0 < 𝜃 < 𝜋. Solve the following equation for θ.
1
= 2√3tanθ − 2
(cosθ)
Answer:
θ = π/3
(16) There are 5 boys and 6 girls in the math class. Find the number of ways the
instructor can select a team of 3 students from the class. The team consists
of 1 boy and 2 girls.
Answer: C × C = ×
×
×
= 75
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