Answers to first review packet.

Module 6 Review Part 1 KEY
Perform the requested transformations. Make sure to label A' and B’.
1. Reflect over the x-axis
2. Rotate 180° counter-clockwise
around the point (0 , 0).
3. Reflect over the line 𝑦 = π‘₯.
Part III: Short Answer
4. (π‘₯ + 1 , 𝑦 βˆ’ 4)
5. What is the name of the shape on the left?
octagon
6. How many diagonals are there on the shape to the left?
20
7. Draw all the lines of symmetry on the shape.
8.
How many lines of symmetry are there on the shape to the left?
16
9. List all of the degrees of rotational symmetry for the shape above.
45°, 90°, 135°, 180°, 225°, 270°, 315°, 360°
10. What are the angles of rotation for a 20-gon? How many lines of symmetry (lines of reflection)
will it have?
18°, 36°, 54°, …, 360°
20 lines of symmetry
11. What are the angles of rotation for a 15-gon? How many line of symmetry (lines of reflection)
will it have?
24°, 48°, 72°, …, 360°
15 lines of symmetry
12. How many sides does a regular polygon have that has an angle of rotation equal to 18°? Explain.
20 sides
20 lines of symmetry
Using the information given determine the most specific classification of the quadrilateral.
(parallelogram, rectangle, rhombus, square)
13. Has 180° rotational symmetry.
Parallelogram
14. Has 90° rotational symmetry.
Square
15. Has two lines of symmetry that are diagonals.
not diagonals.
Rhombus
16. Has two lines of symmetry that are
17. Has congruent diagonals.
Rectangle
18. Has diagonals that bisect each other.
Parallelogram
19. Has diagonals that are perpendicular.
Rhombus
20. Has congruent angles.
Rectangle
Rectangle
Use the coordinate grid to find the length of each side of the triangles provided.
21.
22.
23. Graph a line perpendicular
to the given line.
24. Graph a line perpendicular
to the given line.
25. Graph a line perpendicular
to the given line.
Equation for given line:
𝟏
π’š= 𝒙+𝟏
πŸ‘
Equation for new line:
π’š = βˆ’πŸ‘π’™ + 𝒃
Equation for given line:
π’š = βˆ’πŸ’π’™ βˆ’ 𝟏
Equation for new line:
𝟏
π’š = 𝒙+𝒃
πŸ’
Equation for given line:
π’š = πŸπ’™ βˆ’ 𝟐
Equation for new line:
𝟏
π’š=βˆ’ 𝒙+𝒃
𝟐