Helsinki University of Technology Institute of Mathematics Research Reports Teknillisen korkeakoulun matematiikan laitoksen tutkimusraporttisarja Espoo 2003 A464 SAMPLING AT EQUIANGULAR GRIDS ON THE 2-SPHERE AND ESTIMATES FOR SOBOLEV SPACE INTERPOLATION Ville Turunen AB TEKNILLINEN KORKEAKOULU TEKNISKA HÖGSKOLAN HELSINKI UNIVERSITY OF TECHNOLOGY TECHNISCHE UNIVERSITÄT HELSINKI UNIVERSITE DE TECHNOLOGIE D’HELSINKI Helsinki University of Technology Institute of Mathematics Research Reports Teknillisen korkeakoulun matematiikan laitoksen tutkimusraporttisarja Espoo 2003 A464 SAMPLING AT EQUIANGULAR GRIDS ON THE 2-SPHERE AND ESTIMATES FOR SOBOLEV SPACE INTERPOLATION Ville Turunen Helsinki University of Technology Department of Engineering Physics and Mathematics Institute of Mathematics Ville Turunen: Sampling at equiangular grids on the 2-sphere and estimates for Sobolev space interpolation; Helsinki University of Technology Institute of Mathematics Research Reports A464 (2003). Abstract: We sample functions at 4n2 equiangularly spaced points on the unit sphere S2 of the 3-dimensional Euclidean space, and study the corresponding interpolation projections Qn : C(S2 ) → C(S2 ) in the scale of L2 -type Sobolev spaces H s (S2 ). The main result is that if −1 < s < t and t > 7/2 then kf − Qn f kH s (S2 ) ≤ cs,t,ε ns−t n4+ε kf kH t (S2 ) , where cs,t,ε < ∞ is a constant depending on s, t and ε > 0. Hence this result is useful only when t > s + 4. We also compare our methods to the well-known interpolation on the circle S1 . AMS subject classifications: 65T40, 33C55, 46E35, 42C10, 65T50. Keywords: spherical harmonics, sampling, equiangular grid, interpolation, Sobolev space estimates. [email protected] ISBN 951-22-6828-0 ISSN 0784-3143 Helsinki University of Technology Department of Engineering Physics and Mathematics Institute of Mathematics P.O. Box 1100, 02015 HUT, Finland email:[email protected] http://www.math.hut.fi/ 1 Introduction Let S2 be the unit sphere of the Euclidean space R3 . In this paper, we are concerned with approximation in the L2 -type Sobolev spaces H s (S2 ). A most natural set of sampling points on the sphere consists of the intersections of the equiangularly spaced longitudes and latitudes, and we shall restrict to this case. We study approximation in Sobolev spaces on the sphere S 2 with comparison to the very basic case of interpolation on the circle S 1 . For S1 , the old results are optimal and easy to obtain. However, non-commutative harmonic analysis poses hard problems, and for S2 , our results are quite likely far from optimal, and yet require some work. Our interest in this subject came originally from a need to solve integral and pseudodifferential equations by efficient algorithms. For example, a Dirichlet boundary value problem of a linear elliptic partial differential equation in a domain diffeomorphic to the unit disk of the plane R 2 leads to a pseudodifferential equation on the unit circle S1 ⊂ R2 . To solve such an equation numerically, one may use equispaced sampling points on S 1 , and compute with the now-classical FFT, the Fast Fourier Transform (see [8]). Within last few years, the progress in Fast Fourier type algorithms on the sphere S2 (see [1], [2], [3]) has made it feasible to tackle applications, ranging from tomography to meteorology. E.g. boundary value problems in domains diffeomorphic to the unit ball of R3 can be considered ([6], [7]). The structure of the paper is as follows: The second section reviews the well-known analysis on the circle. The third section is the core, dealing with the case of the sphere. The fourth section demonstrates the sins committed in estimates, applying the techniques of the sphere case to the circle. 3 2 Approximation on S1 To get some perspective to numerical harmonic analysis on the sphere S 2 , let us review some elementary facts from numerical Fourier analysis on the unit circle S1 ⊂ R2 . We identify S1 naturally with the 1-dimensional torus T = R/Z (the space of real numbers modulo integers): if x ∈ [0, 1[ then x + Z ∈ T can be identified with (cos(2πx), sin(2πx)). Of course, we may identify T also with the interval [0, 1[, via (x + Z 7→ x) : T → [0, 1[. The Fourier transform fb : Z → C of a measurable function f : S1 → C is defined by Z fb(ξ) = 1 f (x) e−i2πx·ξ dξ. 0 The L2 -type Sobolev space of order s ∈ R on S1 , denoted by H s (S1 ), is the completion of C ∞ (S1 ) with respect to the norm ! à ¯2 1/2 ¯ X ¯ ¯ , hξi2s ¯fb(ξ)¯ f 7→ kf kH s (S1 ) := ξ∈Z where hξi := max{1, |ξ|}; the inner product is of course X hξi2s fb(ξ) gb(ξ). (f, g) 7→ hf, giH s (S1 ) = ξ∈Z For n ∈ N, let us define the orthogonal projection Pn : H s (S1 ) → H s (S1 ) by n X Pn f := fb(ξ) eξ , ξ=−n+1 where eξ (x) = ei2πx·ξ . If s ≤ t then it is easy to show that kf − Pn f kH s (S1 ) ≤ ns−t kf kH t (S1 ) . In practice, however, we are able to sample the values of a function f only at finitely many points of S1 , and so we cannot even calculate Pn f ; hence let us define the interpolation projection Qn : C(S1 ) → C(S1 ) by µ ¶ µ ¶ j j Qn = Pn Qn , (Qn f ) =f , (0 ≤ j < 2n); 2n 2n recall that we can identify S1 with [0, 1[. This indeed determines Qn : if 1/2 < t and f ∈ H t (S1 ) then n X X eξ fb(ξ + 2nη), Qn f = η∈Z ξ=−n+1 and if moreover 0 ≤ s ≤ t then kf − Qn f kH s (S1 ) ≤ Ct ns−t kf kH t (S1 ) , where Ct < ∞ depends only on t, and lim Ct = ∞; this result is optimal 1 t→ 2 + d (for a proof, see e.g. the lecture notes [8]). The Fourier coefficients Q n f can be computed efficiently by FFT, in time O(n log n). 4 3 Approximation on S2 For the unit sphere S2 = {x = (x1 , x2 , x3 ) ∈ R3 : kxkR3 = (x21 + x22 + x23 )1/2 = 1} we use the spherical coordinates x = x(θ, φ), where x1 = cos(φ) sin(θ), x2 = sin(φ) sin(θ), x3 = cos(θ), 0 ≤ θ ≤ π, 0 ≤ φ < 2π. The inner product for L2 (S2 ) is Z 2π Z π f (x) g(x) sin(θ) dθ dφ. (f, g) 7→ hf, giL2 (S2 ) := 0 0 Applying the Gramm–Schmidt process to the sequence (z 7→ z l )∞ l=0 we ob2 tain the Legendre polynomials Pl forming an orthogonal basis for L ([−1, 1]): µ ¶l d 1 0 Pl (z) = Pl (z) := l (z 2 − 1)l . 2 l! dz For l ∈ N and m ∈ {0, . . . , l}, the associated Legendre function P lm is defined by µ ¶m d m 2 m/2 Pl0 (z), Pl (z) := (1 − z ) dz and furthermore Pl−m (z) := (−1)m (l − m)! m P (z). (l + m)! l Then an orthonormal basis for L2 (S2 ) consists of the spherical harmonic functions Ylm ∈ C ∞ (S2 ) (l ∈ N, |m| ≤ l), s (2l + 1)(l − m)! m Ylm (x(θ, φ)) = (−1)m Pl (cos(θ)) eimφ . 4π(l + m)! For l ∈ N and m ∈ Z, |m| ≤ l, the Fourier coefficient fb(l, m) of a function f ∈ C ∞ (S2 ) is Z 2π Z π m b f (l, m) := hf, Yl iL2 (S2 ) = f (x) Ylm (x) sin(θ) dθ dφ. 0 0 The Fourier inverse transform is now f= ∞ X l X l=0 m=−l fb(l, m) Ylm . It is often convenient to define fb(l, m) := 0 whenever l < 0 or |m| > l. The spherical harmonic Fourier series can be obtained also from the Fourier series on groups SO(3) or U(2); this process is canonical, owing to the representation theory of the groups. 5 The Laplace operator ∆ on S2 is the angular part of the Laplace operator ∂x21 + ∂x22 + ∂x23 on R3 : 1 ∂ ∆f = sin(θ) ∂θ µ ∂ f sin(θ) ∂θ ¶ + ∂2 1 f. sin2 (θ) ∂φ2 Also ∆ can be obtained using the representation theory of the symmetry group of S2 . Notice that Ylm is an eigenfunction of the Laplacian, such that ∆Ylm = −l(l + 1) Ylm . Let the test function space D(S2 ) be C ∞ (S2 ) endowed with the standard Fréchet space structure. The Sobolev space H s (S2 ) is the completion of the test function space in the norm kf kH s (S2 ) := à ∞ X l ¯ ¯2 X ¯b ¯ ¯f (l, m)¯ hli2s l=0 m=−l !1/2 , where hli = max{1, l}. The inner product for H s (S2 ) is obvious. Let us define the orthogonal projection PN : H s (S2 ) → H s (S2 ) by Pn f := l n−1 X X l=0 m=−l fb(l, m) Ylm . Lemma 1. If s ≤ t then kf − Pn f kH s (S2 ) ≤ ns−t kf kH t (S2 ) . Proof. This is a matter of a simple calculation: kf − Pn f kH s (S2 ) = s≤t ≤ à ∞ X l=n ns−t ≤ ns−t = s−t n l2(s−t) l2t à à l X m=−l ∞ X l=n ∞ X l2t l X m=−l hli2t l=0 kf kH t (S2 ) |fb(l, m)|2 |fb(l, m)|2 l X m=−l !1/2 !1/2 |fb(l, m)|2 !1/2 2 Now we are facing the difficulty that a function f can be sampled only at finitely many points. As in the case of numerical Fourier analysis on the torus, we need interpolation projections Qn , and study their approximation properties in the scale of Sobolev spaces. Moreover, it would be important 6 to have some efficient computation method for the approximated Fourier d coefficients Q n f (l, m). Actually, there is an FFT-type algorithm for computing the Fourier coefn−1 X l X ficients of a function f = fb(l, m) Ylm , where n ∈ N. Notice that here l=0 m=−l f has at most N := n2 non-zero Fourier coefficients; a straightforward calculation for all these coefficients would cost O(N 2 ) operations, but with the FFT-type approach only O(N (log N )2 ) operations and memory is needed. The inverse Fourier transform has similar properties. The key to an FFTtype algorithm on S2 is that Ylm (x) = clm Plm (cos(θ)) eimφ , where the classical FFT on S1 can be applied to the exponential factor, and that there is a recurrence formula m m (l − m + 1) Pl+1 (z) − (2l + 1) z Plm (z) + (l + m) Pl−1 (z) = 0 allowing one to construct a “Fast Legendre Transform”. It can be said that all this is possible due to the rich symmetries, and there has been research on FFT-type algorithms on many compact groups [4]. Let b ∈ N and n = 2b . The sampling points on S2 for degree n are (n) (n) (n) xjk = x(θj , φk ), (n) θj := π j , 2n (n) φk := 2π k , 2n (n) where 0 ≤ j, k < 2n. Notice that x0k ∈ S2 is the north pole for every k, and furthermore we will have sampling weight equal to 0 at the north pole; yet for convenience we may think of 4n2 points, which of course holds asymptotically as n → ∞. Proposition 1 collects some results from [1]: Proposition 1. Let l0 ∈ N and m0 ∈ Z, |m0 | ≤ l0 . If f = l n−1 X X l=0 m=−l then fb(l0 , m0 ) = fb(l, m) Ylm 2n−1 2n−1 ³ ´ 1 X X ³ (n) ´ m0 ³ (n) ´ (n) f x Y sin θ x × j jk l0 jk 4n2 j=0 k=0 × n−1 ³ ´ 4X 1 (n) sin (2l + 1)θj . π l=0 2l + 1 Notice that here we used (less than) 4n2 sampled values of f to compute n2 Fourier coefficients fb(l, m). The sampling measure implicit here is 2n−1 2n−1 n−1 ³ ´ 4 X ³ ´ 1 1 X X (n) (n) δx(n) sin θj sin (2l + 1)θj µn := 2 . 4n j=0 k=0 jk π l=0 2l + 1 7 Let us define Qn : C(S2 ) → C(S2 ) by Qn f := Pn (f µn ). Trivially Pn Qn = Qn . By Proposition 1, we have Qn Pn = Pn . Hence Q2n = Qn (Pn Qn ) = (Qn Pn )Qn = Pn Qn = Qn , i.e. Qn is a projection. We want to estimate kf − Qn f kH s (S2 ) . First, let us present some auxiliary results. Lemma 2. µ cn (l, m) = ( 1, 0, when l = 0 = m, when 0 < l < 2n or m 6∈ 2nZ. Here 2nZ = {2nk : k ∈ Z}. Moreover, |c µn (l, m)| ≤ C hli1/2 , where C < 2.043 is a constant. Proof. The equations for the Fourier coefficients were proven in [1]. Let us then establish the estimate. Let ( 1, 0 < θ < π, sgn(θ) = −1, −π < θ < 0. Notice that in the L2 ([−π, π])-sense, ∞ 4X 1 sgn(θ) = sin((2l + 1)θ). π l=0 2l + 1 Due to the Gibbs phenomenon, the partial sums of this Fourier series do not converge in L∞ , but yet we may say that ¯ ¯ n ¯ ¯4 X 1 ¯ ¯ sin((2l + 1)θ) ¯<c ¯ ¯ ¯π 2l + 1 l=0 for every n ∈ N, where c < 1.179 is a constant. Thereby = = ≤ ≤ = |c µ (l , m )| ¯Zn 0 0 ¯ ¯ ¯ ¯ Y m0 dµn ¯ ¯ ¯ 2 l0 ¯ ¯ S 2n−1 2n−1 n−1 ¯ 1 X X ´ 4X ´ ³ ³ ´¯ ³ 1 ¯ (n) (n) (n) ¯ Yl0m0 xjk sin θj sin (2l + 1)θj ¯ ¯ 2 ¯ ¯ 4n π l=0 2l + 1 j=0 k=0 ¯ m ¯ c sup sup ¯Yl0 0 (x(θ, φ))¯ 0≤θ≤π 0≤φ<2π p ° ° c 2l0 + 1 °Yl0m0 °L2 (S2 ) p c 2l0 + 1. In the last inequality we used Lemma 8 from [5]. Hence the desired estimate is obtained 2 For a function or a distribution g on S2 , denote glm := gb(l, m) Ylm . 8 Lemma 3. Let f ∈ D(S2 ) and g ∈ D 0 (S2 ). Then f g ∈ D 0 (S2 ) satisfies fcg(l, m) = ∞ X l2 =0 l2 +l X X m1 m2 f\ l1 gl2 (l, m). m1 ,m2 : |mj |≤lj m1 +m2 =m l1 =|l2 −l| Proof. There is a product formula Yl1m1 Yl2m2 = lX 1 +l2 clm1 l12mL2 YLm1 +m2 , L=|l1 −l2 | where l1 l2 L cm = 1 m2 s (2l1 + 1)(2l2 + 1) l1 ,l2 ,L l1 ,l2 ,L C0,0,0 Cm1 ,m2 ,m1 +m2 , 4π(2L + 1) l1 l2 L l1 ,l2 ,l3 =0 being a Wigner symbol, see [9]. We use the convention cm Cm 1 m2 1 ,m2 ,m3 whenever L < |l1 − l2 | or L > l1 + l2 or |m1 + m2 | > L. Thus so that m1 m2 l1 l2 l b f\ b(l2 , m2 ), l1 gl2 (l, m) = δm,m1 +m2 cm1 m2 f (l1 , m1 ) g fcg(l, m) = = l1 l2 ∞ ∞ X X X X m1 m2 f\ l1 gl2 (l, m) l1 =0 m1 =−l1 l2 =0 m2 =−l2 l1 ∞ X ∞ X X l2 X m1 m2 l1 l2 l δm,m1 +m2 cm f\ l1 gl2 (l, m) 1 m2 l1 =0 l2 =0 m1 =−l1 m2 =−l2 = = ∞ X l2 +l X X l2 =0 l1 =|l2 −l| m1 ,m2 : |mj |≤lj m1 +m2 =m ∞ X l2 +l X X l2 =0 l1 =|l2 −l| l1 l2 l cm fb(l1 , m1 ) gb(l2 , m2 ) 1 m2 m1 m2 f\ l1 gl2 (l, m) m1 ,m2 : |mj |≤lj m1 +m2 =m 2 Lemma 4. Let f be a function, and let µn be the sampling measure presented above. Then ¯ ¯ ¯ ¯ ¯ ¯ \ ¯ m1 m2 −r r r+1/2 ¯ b ≤ C hli hl i hl i f (l , m ) f µ (l, m) ¯ 1 1 ¯. ¯ l1 nl2 ¯ r 1 2 for every r > 1, where Cr is a constant depending on r, lim Cr = ∞. r→1+ 9 2 Proof. The last claim follows simply because µm nl2 ≡ 0 when m2 6∈ 2nZ. Notice that H r (S2 ) ⊂ C(S2 ) if and only if r > dim(S2 )/2 = 1. For functions g, h : S2 → C let us denote Mg h := gh. When r > 1, H r (S2 ) is a Banach algebra when equipped with the norm g 7→ sup h∈H r (S2 ): khkH r (S2 )≤1 kghkH r (S2 ) = kMg kL(H r (S2 )) . This Banach algebra norm is equivalent to the Sobolev norm: kgkH r (S2 ) ≤ kMg kL(H r (S2 )) ≤ cr kgkH r (S2 ) . Here cr is a constant, and lim cr = ∞. Thereby we get r→1+ ¯ ¯2 ¯ \ ¯ m1 m2 1 m2 m 2 µnl2 )l kH r (S2 ) f µ (l, m) ¯ l1 nl2 ¯ = hli−2r k(flm 1 1 m2 2 ≤ hli−2r kflm µnl2 kH r (S2 ) 1 2 2 = hli−2r kMflm1 µm nl2 kH r (S2 ) 1 2 2 ≤ hli−2r kMflm1 k2L(H r (S2 )) kµm nl2 kH r (S2 ) 1 ≤ c2r hli −2r = c2r hli−2r 2 2 1 2 kflm kH r (S2 ) kµm nl2 kH r (S2 ) 1 ¯ ¯2 ¯ 2r 2r ¯ b µn (l2 , m2 )|2 . hl1 i hl2 i ¯f (l1 , m1 )¯ |c By Lemma 2 above, |c µn (l2 , m2 )|2 ≤ C 2 hl2 i, and this concludes the proof 2 Theorem 1. If −1 < s < t and t > 7/2 then kf − Qn f kH s (S2 ) ≤ cs,t,ε ns−t n4+ε kf kH t (S2 ) . Here cs,t,ε < ∞ is a constant depending only on s, t and ε > 0. Proof. First, H k+1+ε (S2 ) ⊂ C k (S2 ) ⊂ H k (S2 ) for every k ∈ N and ε > 0, and furthermore H k+1 (S2 ) 6⊂ C k (S2 ). Therefore we assume that f ∈ H t (S2 ) for some t > 1. Trivially kf − Qn f kH s (S2 ) = k(f − Pn f ) + (Pn f − Qn f )kH s (S2 ) ≤ kf − Pn f kH s (S2 ) + kPn f − Qn f kH s (S2 ) . Lemma 1 gave the optimal estimate for kf − Pn f kH s (S2 ) , and the difficulties come when dealing with kPn f − Qn f kH s (S2 ) . Now Qn f = Pn (f µn ) l n−1 X X fd µn (l, m) Ylm . = l=0 m=−l 10 When 0 ≤ l < n, we have fd µn (l, m) = fb(l, m) + l2 +l X ∞ X l2 =2n l1 =l2 −l X m1 m2 f\ l1 µnl2 (l, m) m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m by Lemmata 2 and 3. Thereby (Qn − Pn )f ∞ l n−1 X X X m Yl = l=0 m=−l l2 +l X l2 =2n l1 =l2 −l X m1 m2 f\ l1 µnl2 (l, m). m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m We have k(Pn − Qn )f k2H s (S2 ) ¯ ¯ ¯ ¯ ∞ l2 +l n−1 l X X X ¯¯ X 2s = hli ¯ ¯ l=0 m=−l ¯l2 =2n l1 =l2 −l ¯ ¯ m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m ∞ l2 +l l X X X 2s hli ≤ l=0 m=−l l2 =2n l1 =l2 −l n−1 X X X ¯2 ¯ ¯ ¯ ¯ ¯ m1 m2 \ fl1 µnl2 (l, m)¯ ¯ ¯ ¯ ¯ m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m 2 ¯ ¯ ¯ \ ¯ 1 m2 µnl2 (l, m)¯ , ¯flm 1 and by Lemma 4 we get k(Pn − Qn )f k2H s (S2 ) ≤ Cr2 n−1 l X X hli2s−2r l=0 ∞ l2 +l X X l2 =2n l1 =l2 −l m=−l X hl1 ir hl2 ir+1/2 m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m 11 2 ¯ ¯ ¯b ¯ ¯f (l1 , m1 )¯ . The Hölder inequality gives us the next estimate: k(Pn − Qn )f k2H s (S2 ) Cr2 ≤ n−1 X hli l X 2s−2r m=−l l=0 l2 +l ∞ X X l2 =2n l1 =l2 −l X hl1 i2r−2t m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m l2 +l ∞ X X × l2 =2n l1 =l2 −l X m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m 2r+1 hl2 i × ¯2 ¯ ¯ ¯ m1 m2 hl1 i2t ¯f\ l1 µnl2 (l, m)¯ for some t large enough. Moreover, ∞ X l2 +l X X m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m l2 =2n l1 =l2 −l ≤ ∞ X l22r+1 l2 =2n ≤ ∞ X l2 +l X (1 + 2 min{l1 , l2 /(2n)}) l12r−2t l1 =l2 −l l22r+1 (1 + l2 /n) k:=l2 −n ≤ ≤ ≤ ∞ X (2l + 1) (2l + 1) (2l + 1) l2 +l X l12r−2t l1 =l2 −l l2 =2n ≤ hl1 i2r−2t hl2 i2r+1 l22r+1 (1 + l2 /n) (l2 − n)2r−2t l2 =2n ∞ X (k + n)2r+1 (2 + k/n) k 2r−2t k=n ∞ X 22r+1 k 2r+1 (2 + k/n) k 2r−2t k=n 4r−2t+2 ct,r hli n , where ct,r depends on t and r. In the previous calculation, we had to demand that 4r − 2t + 2 < −1, i.e. t > 2r + 3/2. Since r > 1, we must have t > 7/2. 12 With this knowledge, we get k(Pn − Qn )f k2H s (S2 ) ≤ Cr2 ct,r n4r−2t+2 ∞ l2 +l X X l2 =2n l1 =l2 −l Cr2 ct,r n m=−l X m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m 4r−2t+2 n−1 X hli 2s−2r+1 m=−l ≤ Cr2 X m1 ,m2 : m2 ∈2nZ |mj |≤lj m1 +m2 =m ct,r n 4r−2t+2 hli 2s−2r+1 l1 X m1 =−l1 ≤ 9 Cr2 ct,r n 4r−2t+2 ∞ X ¯2 ¯ ¯ ¯b f (l , m ) ¯ 1 1 ¯ n−1 X hli 2s−2r+3 l=0 ≤ 9 Cr2 ct,r n4r−2t+2 hl1 i2t n−1 X X l2 :max{2n,l1 −l}≤l2 ≤l1 +l hl1 i2t (2l + 1) × l1 =n+1 l=0 × (2l + 1) ∞ X l1 =n+1 ¯ ¯2 ¯b ¯ ¯f (l1 , m1 )¯ n−1 X ¯ ¯2 ¯b ¯ ¯f (l1 , m1 )¯ hl1 i2t l=0 l X l X hli2s−2r+1 l=0 = n−1 X ∞ X hl1 i 2t l1 =n+1 hli2s−2r+3 kf k2H t (S2 ) . l1 X m1 =−l1 ¯2 ¯ ¯ ¯b ¯f (l1 , m1 )¯ l=0 We may consider r > 1 to depend t. We must suppose that 2s−2r+3 > P on 2s−2r+3 −1, i.e. s > r − 2 > −1. Then n−1 hli ≤ c0s−r n2s−2r+4 , so that l=0 2 n2s−2t n2r+6 kf k2H t (S2 ) . k(Pn − Qn )f k2H s (S2 ) ≤ Cs,t,r Here 2r + 6 = 2(r + 3) > 2 · 4. This yields 0 k(Pn − Qn )f kH s (S2 ) ≤ Cs,t,ε ns−t n4+ε kf kH t (S2 ) , where Ctε is a constant depending on t and ε > 0. Consequently, an estimate for kf − Qn f kH s (S2 ) is established 2 13 4 Insufficiency of methods It is also important to notice that the results in numerical Fourier analysis on S2 above are quite robust; more delicate treatises will be needed. To demonstrate this, let us apply our technique on S2 to get estimates for interpolation projections on S1 . The notation in this section is parallel to the S2 -case. We identify S1 with [0, 1[⊂ R. Recall that here n X Pn f = ξ=−n+1 fb(ξ) eξ . Lemma 1’. If s ≤ t then kf − Pn f kH s (S1 ) ≤ ns−t kf kH t (S1 ) . This result is optimal, but we will present non-optimal results, yet in analogy to the interpolation on the sphere S2 — we must remember that the main point of this section is to demonstrate how insufficient our methods for S2 may be. The sampling points are {j/(2n) : 0 ≤ j < 2n}, and each point carries the equal weight 1/(2n). The corresponding sampling measure is 2n−1 1 X δj/(2n) . µn = 2n j=0 Let Qn f := Pn (f µn ). Now we can calculate all the Fourier coefficients of µn : µ cn (ξ) = ( 1, when ξ ∈ 2nZ, 0, when ξ 6∈ 2nZ. But we want to demonstrate what could possibly cause bad estimates for S 2 in the previous section. Hence let us modestly state the following: Lemma 2’. Moreover, µ cn (ξ) = ( 1, 0, when ξ = 0, when ξ ∈ 6 2nZ, |c µn (ξ)| ≤ 1. For a distribution g ∈ D 0 (S1 ), let gξ = gb(ξ) eξ . We write the well-known formula fcg(ξ) = (fb ∗ gb)(ξ) in the following form: 14 Lemma 3’. Let f ∈ D(S1 ) and g ∈ D 0 (S1 ). Then f g ∈ D 0 (S1 ) satisfies fcg(ξ) = X X f\ ξ1 gξ2 (ξ). ξ2 ∈Z ξ1 =ξ−ξ2 The Fourier coefficients of Qn f can be written down precisely, but we settle for a weaker result: Lemma 4’. Let f be a function, and let µn be the sampling measure presented above. Then where r > 1/2. ¯ ¯ ¯b ¯ f (ξ ) ¯ 1 ¯, ¯ ¯ ¯d ¯ f µ (ξ) ¯ n ¯ ≤ Cr hξi−r hξ1 ir hξ2 ir Proof. The operator norm endows H r (S1 ) with a Banach algebra structure if and only if r > dim(S1 )/2 = 1/2. Now the estimation process goes as in the proof of Lemma 4, and we notice that |c µn (ξ2 )| ≤ 1 here 2 Theorem 1’. If −1/2 < s < t and t > 3/2 then kf − Qn f kH s (S1 ) ≤ cs,t,ε ns−t n kf kH t (S1 ) . Here ct,s,ε < ∞ is a constant depending only on s, t and ε > 0. Proof. First, kf − Qn f kH s (S1 ) ≤ kf − Pn f kH s (S1 ) + kPn f − Qn f kH s (S1 ) . Lemma 1’ gave the optimal estimate for kf − Pn f kH s (S1 ) . We must estimate kPn f − Qn f kH s (S1 ) , but not too well: we follow the path taken in the proof of Theorem 1. If −n < ξ ≤ n then Lemma 2’ yields fd µn (ξ) = fb(ξ) + X X f\ ξ1 µnξ2 (ξ). ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 Hence (Qn − Pn )f = n X ξ=−n+1 eξ X X ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 15 f\ ξ1 µnξ2 (ξ), so that Lemma 4 gives k(Pn − Qn )f k2H s (S1 ) ¯ ¯ X n X ¯ 2s ¯ hξi ¯ = ¯ξ2 : |ξ2 |≥2n ξ=−n+1 n X X hξi2s ≤ 2 ¯ X ¯¯ ¯ ¯f\ ξ1 µnξ2 (ξ)¯ ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 ξ=−n+1 ≤ Cr2 ¯2 ¯ X ¯ ¯ f\ ξ1 µnξ2 (ξ)¯ ¯ ξ1 =ξ−ξ2 n X ξ=−n+1 hξi2s−2r X X ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 The Hölder inequality yields k(Pn − Qn )f k2H s (S1 ) n X X hξi2s ≤ ξ=−n+1 Here × X X 2 ¯ ¯ ¯ ¯ hξ1 ir hξ2 ir ¯f\ . ξ1 µnξ2 (ξ)¯ ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 X X hξ1 i2t ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 X hξ1 i2r−2t hξ2 i2r × ¯2 ¯ ¯b ¯ ¯f (ξ1 )¯ . hξ1 i2r−2t hξ2 i2r ≤ Ct,r n4r−2t+1 ; ξ2 : |ξ2 |≥2n ξ1 =ξ−ξ2 here 4r − 2t < −1, i.e. t > 2r + 1/2 > 3/2. Consequently, k(Pn − Qn )f k2H s (S1 ) n X 4r−2t+1 ≤ ct,r n hξi2s−2r ξ=−n+1 X ξ2 : |ξ2 |≥2n ≤ c0t,r n2(s−t) n2(r+1) kf k2H t (S1 ) , hξ1 i 2t ¯ ¯ ¯ b ¯2 ¯f (ξ1 )¯ where 2s − 2r > −1, i.e. s > r − 1 > −1/2. Since r > 1/2, we have r + 1 > 3/2. Thus we eventually get kf − Qn f kH s (S1 ) ≤ ct,s,ε ns−t n3/2+ε kf kH t (S1 ) , where −1/2 ≤ s < t, t > 3/2 and ε > 0. 16 2 5 Conclusion Theorem 1’ shows that our method does not give the optimal result even in the extremely simple case of the circle S1 : We lost 3/2 + ε Sobolev space degrees, and we had to suppose that f ∈ H t (S1 ) with t > 3/2, even though actually t > 1/2 can be assumed. This may suggest that our results for the 2-sphere S2 are not the best possible. Acknowledgements. The work was funded by the Academy of Finland. References [1] J. Driscoll, D. Healy: Computing Fourier transforms and convolutions on the 2-sphere. Adv. Appl. Math. 15 (1994), 202–250. [2] D. M. Healy, D. N. Rockmore, P. J. Kostelec, S. Moore: FFTs for the 2sphere — improvements and variations. J. Fourier Anal. Appl. 9 (2003), 341–385. [3] S. Kunis, D. Potts: Fast spherical Fourier algorithms. J. Comp. Appl. Math. 161 (2003), 75–98. [4] D. K. Maslen: Efficient computation of Fourier transforms on compact groups. J. Fourier Anal. Appl. 4 (1998), 19–52. [5] C. Müller: Spherical Harmonics. Lecture Notes in Mathematics 17. Springer-Verlag, Berlin - New York, 1966. [6] V. Turunen: Pseudodifferential calculus on compact Lie groups and homogeneous spaces. Ph.D. Thesis, Helsinki Univ. Techn., 2001. http://lib.hut.fi/Diss/2001/isbn9512256940/ [7] V. Turunen: Pseudodifferential calculus on the 2-sphere. Helsinki University of Technology, Research Report A462, 2003. To appear in Proceedings of the Estonian Academy of Sciences. Physics. Mathematics. http://www.math.hut.fi/reports/a462 [8] G. Vainikko: Periodic integral and pseudodifferential equations. Helsinki University of Technology, Research Report C13, 1996. [9] N. J. Vilenkin: Special Functions and the Theory of Group Representations. Amer. Math. Soc., Providence, Rhode Island, 1968. 17 (continued from the back cover) A458 Tuomas Hytönen Translation-invariant Operators on Spaces of Vector-valued Functions April 2003 A457 Timo Salin On a Refined Asymptotic Analysis for the Quenching Problem March 2003 A456 Ville Havu , Harri Hakula , Tomi Tuominen A benchmark study of elliptic and hyperbolic shells of revolution January 2003 A455 Yaroslav V. Kurylev , Matti Lassas , Erkki Somersalo Maxwell’s Equations with Scalar Impedance: Direct and Inverse Problems January 2003 A454 Timo Eirola , Marko Huhtanen , Jan von Pfaler Solution methods for R-linear problems in C n October 2002 A453 Marko Huhtanen Aspects of nonnormality for iterative methods September 2002 A452 Kalle Mikkola Infinite-Dimensional Linear Systems, Optimal Control and Algebraic Riccati Equations October 2002 A451 Marko Huhtanen Combining normality with the FFT techniques September 2002 A450 Nikolai Yu. Bakaev Resolvent estimates of elliptic differential and finite element operators in pairs of function spaces August 2002 HELSINKI UNIVERSITY OF TECHNOLOGY INSTITUTE OF MATHEMATICS RESEARCH REPORTS The list of reports is continued inside. Electronical versions of the reports are available at http://www.math.hut.fi/reports/ . A463 Marko Huhtanen , Jan von Pfaler The real linear eigenvalue problem in setcn November 2003 A462 Ville Turunen Pseudodifferential calculus on the 2-sphere October 2003 A461 Tuomas Hytönen Vector-valued wavelets and the Hardy space H 1 (Rn ; X) April 2003 A460 Timo Eirola , Jan von Pfaler Numerical Taylor expansions for invariant manifolds April 2003 A459 Timo Salin The quenching problem for the N-dimensional ball April 2003 ISBN 951-22-6828-0 ISSN 0784-3143
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