PRACTICE ..... Taking it to the next level of greatness.
1.
Name:
kÿL,,
Period:
Learning Level:
Going to the next level. TÿSis time you will be looking at the force applied to the charge in between two other charges.
Negative and Positive values show level attraction or repulsion only.
Use the picture below to determine the net force on a -2 pC (X) charge that is placed between a - 6pC which is 0.2 m
from the center charge (X) and - 3 pC which is 0.10 m from the center charge.
Q1 = - 6pC
Q2 = -2 pC
(qÿ% !
qÿq,
Gÿ..,,< k: i <F
F1 + F2 = Fnet
d= 0.2m
9X 109X6X 10-6X2Xl,0-6
9 X 109 X 2 X 10-6 X 3 XIO-6
Q1 = -2 pC
(0.2)2
(o.lo)2
Q2 = - 3 pC
d= O,10m
F2 = ?
F1 = 2.7 N
F2 = 5.4 N
FI=?
2.7+5.4=8.1N
(pushed) Left
Why?
F2 is stronger than F1.
The net force on the
center charge is greater
from the F2 direction,
hence "pushing it"
toward the left.
Use the picture below to determine the net force on a -9 pC (X) charge that is placed between a - 5pC which is 0.15 m
from the center charge (X) and - 8 F-tC which is 0.10 m from the center charge.
/
Q1 .... °ÿjÿ, ÿ12
I' qÿqÿ!
Q2 .... <ÿt{ C,
F1 + F2 = Fnet
d= ,# i ÿ )ÿ,ÿ;,¢ -
FI=?
'?ÿ/ÿ'ÿ, ¢x/ÿ'%, Ix/,J°
Q1 =....ÿ?
"
!>i-
Q2
F2 = ?
ÿ/. C
........... <:/:i5; ........................................
(; i )ÿ
,j" "4,.t
Direction ? (ÿLeÿ' or Right)
Use the picture below to determine the net force on an 8 pC (X) charge that is placed between a -2 pC which is 0,10 m
from the center charge (X) and - 8 pC which is 0,10 m from the center charge,
© ./,- S ,,,-©_
Q1-_
' qjq:, 'ÿ
" qÿq.! '!
d = d;'ÿ t ÿÿ
FI:?
L,I>'ÿ:
(,i )"x-
d = %t ÿ4.
F2: ?
., .: f,
Use the picture below to determine the net force on a -6 pC (X) charge that is placed between a - :[pC which is 0,25 m
from the center charge (X) and 8 pC which is 0.20 m from the center charge.
Q:[ ...... /,,:ÿ ÿL
<
E.,ÿ<....,,< , k< qÿq''-
d' i
FI=?
F1 + F2 = Fnet
qÿq:
:7:'I°
, . "/ J
' D
<ÿ;<.d:.
8 " x ÿ, ÿ:u,
ÿ ,-Z.
O<
7:5q
s' ,ÿ #.ÿ'i ÿ,s
ql. = ,-ÿ7,,,.:
Q2 =
d=
:;'
(, ÿ< .;,ÿ z
Direction. (Left or ÿgl'iÿJ
O< g u"
F2= ?
/:,ÿ<,:: :s :<c:_: M...<I%.). .ÿ