Practice Problem Ch. 15 – this is #15.14 in the book. There is some evidence that drinking moderate amounts of wine helps prevent heart attacks (this helps you with your direction). The table gives data on yearly wine consumption (liters of alcohol from drinking wine, per person) and yearly deaths from heart disease (deaths per 100,000 people) in a dozen developed nations. Alcohol from wine 3.9 2.4 2.9 9.1 0.7 7.9 Country Austria Canada Denmark France Ireland Italy Heart disease deaths 167 191 220 71 300 107 Country Spain Sweden Switzerland United Kingdom United States West Germany Alcohol from wine 6.5 1.6 5.8 1.3 1.2 2.7 Heart disease deaths 86 207 115 285 199 172 1. Make a scatterplot that shows how wine consumption affects heart disease. increments of 25. Heart Disease Vs. Alcohol Consumption Heart Disease deaths 350 300 250 200 150 100 50 0 0 2 4 6 8 10 Alcohol 2. Use your calculator to obtain the LSRL equation and correlation. Heart disease deaths = 266-23.4(Alcohol); r=.9032; strong, negative, linear correlation. 3. Formulate null and alternative hypotheses about the slope of the true regression line. H a : 0 (There is no linear association between a country’s annual per person wine consumption and yearly deaths from heart disease) H a : 0 (There is a negative linear association between a country’s annual per person wine consumption and yearly deaths from heart disease) 4. Report the sum of the 12 residuals and the sum of the squares of the residuals. What is the value of s (the standard error about the line)? L3: L2-Y1(L1) to get residuals; then do 1 var stats on L3 to get the following: Sum of 12 residuals = x 1e 11 0 ; Sum of squares of the residuals: x 2 10,803.3597 Chapter 15 S (approximates ) = (residuals) n2 2 10803.3597 32.868 10 5. The model for regression inference has 3 parameters: , , and . Estimate these parameters from the data. approximates a approximates a b approximates b = -23.3567 s approximates s = 32.868 6. Computer output reports that the standard error of the slope is SEb = 3.511. Use this to construct a 95% confidence interval for the slope of the true regression line. Degrees of freedom = 12-2 = 10 b t *SEb = -23.3567 (2.228)(3.511) = (-31.18, -15.53) With 95% confidence, we estimate that the number of deaths from heart disease (per 100,000 people) decreased on average between 15.46 and 30.47 for each additional liter of wine consumed per person.
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