REVISION: FUNCTIONS 10 JUNE 2013 Lesson Description In this lesson we revise: the effects of a, p and q on the graphs of the form: 2 y = a(x + p) + q y = a.b (x + p) +q how to find the equation of various functions from a given graph how to find the average gradient between two points on a graph Key Concepts The effect of changing p and q If q > 0 the graph moves vertically up by 'q' units If q < 0 the graph moves vertically down by 'q' units If p > 0 then the graph shifts horizontally to the left If p < 0 then the graph shifts horizontally to the right The effect of changing a Multiplying 'x' by 'a' will stretch or compress the graph vertically by the factor 'a' o Example (0 < a < 1 compresses the graph) o Example (a < 0 reflects and stretches the graph) Graphs of the form: y = a(x + p)2 + q If a > 0 then we have a minimum turning point (smile) If a < 0 then we have a maximum turning point (frown) If q > 0 then the t.p is above the x axis If q < 0 then the t.p is below the x axis p affects the horizontal shift of the graph and the axis of symmetry: If p > 0 then the t.p is on the left of the y axis If p < 0 then the t.p is on the right of the y axis The axis of symmetry is x = -p Graphs of the form: Recall: An increasing function-as the x values increase, the y values increase. A decreasing function-as the x values increase, the y values decrease. If a > 0 then the hyperbola is a decreasing function If a < 0 then the hyperbola is an increasing function The value of q determines the vertical shift of the graph and also gives the horizontal asymptote (y = q) p affects the horizontal shift of the graph and gives the position of the vertical asymptote (x = -p) The axes of symmetry are y = x + p + q and y = -(x + p) + q Graphs of the form: y = a.b(x+p) + q There is a horizontal asymptote at y = q If a > 0 the graph will be decreasing for 0 < b < 1 and for b > 1 the graph is increasing If a < 0 and 0 < b < 1, the standard graph is reflected about the x axis and is now an increasing function If a < 0 and b > 1, the standard graph is reflected about the x axis and is now a decreasing function. Finding the Equation For a Parabola Case 1: Turning point and another point given 2 Step 1 Use y = a(x + p) + q and substitute the coordinates of the turning point. Step 2: Find the value of a by substituting the coordinates of another point on the graph into the equation. Case 2: The x intercepts and another point given Step 1: Use y = a(x - x1)(x - x2) where x1 and x2 are the x intercepts Step 2: Find the value of a by substituting the coordinates of another point on the graph into the equation. For a Hyperbola Step 1: The position of the asymptotes gives us p and q in Step 2: To find the value of a, substitute any point on the graph into the equation. Questions Question 1 (Adapted from Clever Keeping Maths Simple Grade 11 Learner's Book. Page 175, Ex5.21 no. 3) The equations of the graphs shown in the sketch are and a.) b.) c.) d.) Give the coordinates of D, the y-intercept of both graphs. Calculate the coordinates of A and B, the x-intercepts of g. Determine the coordinates of C, the turning point of g. Calculate the coordinates of E, one of the points of intersection of f and g. Question 2 (Clever Keeping Maths Simple, Macmillan, Grade 11 Learner's Book. Page 165, Ex 5.19 no 6) Find the equation of the following graph: y=b x+p +q Question 3 (Clever Keeping Maths Simple, Macmillan, Grade 11 Learner's Book. Page 177, Ex. 5.21 no. 6) 2 The diagram represents the graphs of y = f(x) = -(x – 2) + 4 and y = g(x) = 2 x+1 – 4. Calculate the following: a.) b.) c.) d.) e.) OE OD OC BC FG Question 4 (Adapted from Clever Keeping Maths Simple, Macmillan, Grade 11, Example 1, Page 167) 2 a.) Calculate the average gradient of the graph y = x - 4 between x=1 and x=3 b.) For which values of x is the graph i. increasing ii. decreasing
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