Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
Aim:
SWBAT calculate and estimate the volume
of pyramids.
Do Now: At the top of Page 15
Homework:
Page 18 in the Unit 5C Packet
** Unit 5C Test is Friday, May 20th **
May 11, 2016
Day 05 ­ Volume of Pyramids.notebook
l
May 11, 2016
h
h
w
V = lwh
V = ( 1 bh)h
V = (27)(19)(18)
2
V = ( 1 14 6.8) 10
2
V = 9234 m3
V = 476 km3
h
l
w
h
V = lwh
V = (15)(27)(12)
V = ( 1 bh)h
2
V = ( 1 29 12.2) 28
2
V = 4860 in3
V = 4953.2 ft3
h
V = 1 (b1 + b2)h h
2
V = 1 (8 + 18)9.8 22
2
V = 2802.8 cm3
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
The base of a pyramid is a polygon and the sides are triangles which meet at the top point (called an apex).
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
it is a square pyramid
1
V = lwh
3
V = 1 lwh
3
1
V = (16)(16)(15)
3
V = 1280 in3
it is a rectangular pyramid
1
V = lwh
3
V = 1 lwh
3
1
V = (16)(6)(14)
3
V = 448 ft3
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
it is a triangular pyramid
V = 1 ( 1 bh)h
3 2
V = 1 ( 1 bh)h
3 2
V = 1 ( 1 6 8) 9
3 2
V = 72 cm3
it is a rectangular pyramid
1
V = lwh
3
V = 1 lwh
3
1
V = (10)(8)(6)
3
V = 160 in3
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
V = 38.4 cm3
V = 1445 in3
V = 168 cm3
V = 6250 mm3
V = 630 cm3
Day 05 ­ Volume of Pyramids.notebook
May 11, 2016
Day 05 ­ Volume of Pyramids.notebook
V = 1 lwh
3
1
V = (16)(8)(22)
3
V ≈ 938.7 mi3
V = 1 ( 1 bh)h
3 2
V = 1 ( 1 15 20) 15
3 2
V = 750 yd3
May 11, 2016
V = 1 lwh
3
1
V = (6)(6)(11)
3
V = 132 cm3
V = 1 lwh
3
1
3
V = (24)(8)(10)
V = 640 in3