xiv ______________________________________________________________________________ Physics 1020 Plotting and Interpreting Graphs Plotting and Interpreting Graphs Introduction In many labs you will be plotting data in order to obtain the value of a physical quantity. It is imperative to get a good understanding of this technique in order to obtain the best results in the lab. Plotting your results To plot data points we use a software package called βGraphical Analysisβ. Letβs start by plotting some data, consisting of a set of points (x, y). The important thing here is to notice that if you plot a graph of π¦ vs. π₯ then your quantity π₯ is called an independent variable and is represented on the horizontal axis. The quantity π¦ is called a dependent variable and is plotted on the vertical axis. Consider the following data points of x and y. x 1 2 3 4 5 Plotting π¦ vs. π₯ produces the graph below. y 4.25 5.48 6.74 7.89 9.10 xv ______________________________________________________________________________ Physics 1020 Plotting and Interpreting Graphs Interpreting Graphs In physics your dependent and independent variables have a physical meaning i.e. they are physical quantities like mass (π), volume (π), position (π₯) or time (π‘) to name a few. These quantities are related to each other via physical laws generally expressed as equations. When interpreting your graph you have to know that equation. Here is an example. Consider the definition of density. It is the mass per unit volume and is expressed by the following equation: π π You can find the density of any material by taking a piece of it and measuring its mass and volume. However, a more precise method of doing it involves making the same measurements but for a set of a few objects, made out of the same material, each of different mass and volume. Rearranging the above equation gives: π= π = ππ This shows that the mass of an object is linearly dependent on its volume or in other words if the volume doubles so does the mass. That in turn means that the relation between π and π can be described by an equation of a straight line i.e. π¦ = ππ₯ + π, and a plot of M (on π¦-axis) versus V (on π₯-axis) should be a straight line. Our task is to find the best line going through our data points. We do that by performing a straight line fit (or linear regression). The results of that analysis will result in numerical values of the parameters π and π. They will also have a physical meaning, which you can obtain by comparing the fit equation with the physics equation, which relates the two variables in question (in this case π and π) Letβs look at an example. Consider the following measurements. Volume (m3) 0.250 0.350 0.440 0.490 0.600 Mass (kg) 0.191 0.268 0.341 0.375 0.449 Plot of that data together with the fit parameters obtained by the softwareβs fitting routine are shown below. Comparing: π = ππ with π¦ = ππ₯ + π xvi ______________________________________________________________________________ Physics 1020 Plotting and Interpreting Graphs tells us that if we choose π as the π¦ variable and π as the π₯ variable then the slope of our straight line π will be equal to density π, and we would expect the intercept π to be equal zero. Therefore in this example π = (0.74 ± 0.02)ππ/π3, where we take the standard deviation of the slope as its absolute uncertainty. IMPORTANT: Whenever you are asked to find the physical meaning of the slope of your graph you will have to write the physics equation and the fit equation side by side and identify which physics variables correspond to which symbols in the fit equation. Summary For plotting and interpreting graphs follow the steps below and refer to the above example as needed: 1. Identify which physical variable is the x (x-axis) and which is the y (y-axis). [e.g. V, M] 2. Identify a physics equation that relates the variables. [e.g. M=ο²V] 3. Note the relationship of your data i.e. linear, quadratic etc. [e.g. linear] 4. Write down the general form of the equation i.e. y=mx+b, y=ax2+bx+c, etc. [e.g. y=mx+b] 5. Compare with physical equation to the equation of the fit. [e.g. Comparing M=ο²V to y=mx+b gives m=ο², b=0]
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