Graphing ( a YD In +1

Graphing tutorial
In this tutorial
will
we
,
cover
:
drawing slope intercept graphs
writing slope intercept graphs
-
-
How to
draw
slope
inarapt
graphs
Slope intercept graph equation
-
y
:
(
o
,
.
by
/
•
(
T"
mntb
=
~
8
"
Nea
?
slope
.
Xz
Yz )
,
•
slope
rise
run
•
(
a
YD
,
a
slope
=m
Y2 Y
-
rise
=
=
run
Ex
.
Draw
the graph
D Identify
of y=3z
the slope
and
This
and
When
and
looks like
touch the
ye
+1
-
n
,
1
y intercept
math
-
m
so
=
22
fslopej
( y intercept)
b= 2
drawing
the
In
y=
xz
set
,
-
-
graph
our
y
-
axis
,
on
at /
graph should be
as
steep
.
Graph
as
Is
units
2) Plot at least
from
you found
Y
6
5
e.
•
4
••
We
•
2
1
2
9
8
7
56
4
3
10
,
( 0,1 )
because
3
(o
Know
D is
2 points
the equation
a
they
is
Use the
equation
generate
another
point
From y Int
find Y when
Drama
These 2
the grapw
Notice
*
to the
is
line
-
points
the slope !
.
6
5
4
(m/s )
3
:
1
2
-
of the graph
5
.
let's
1
a
-2
.
:
6
1
another
(
point
2,4 )
intercept graph
below
iz
34
.
3+1=4
which
points ,
slope
a
Velocity
y
this
Y=¥#+
is
Determine the equation
Velocity
2
2
runs
so
How to write The equation of
Ex
solving
intercept
.
by 3 and
rises
between the
right
that passes
.
to help you
.
3)
point
Find the
.
units
of the
slope
overtime
78
9
10
timers )
11
13141516
ttlglg
K
.
Find they intercept
1)
-
Velocity
(m/s )
iz
at
the graph
intercepts the graph
go
4
overtime
Velocity
y
;
.
y
:
1
23
1
-
intercept
4 in
y=MNtb
=
°
:
80
y=mn+4
9
8
67
5
4
orb
,
y=4m/s
10
1
1
K
15/6
ttlglg
1314
timers )
2)
Find
2
points
:
(m/s )
the graph
p
:
1
1
far
as
-
as
possible from
40
§
Velocity
y
Velocity
on
Ist
another
one
.
overtime
point
( 0,47
2
34
5
9
78
6
10
11
(
yard
12,0 )
point
K
1516
ttlglg
1314
timers )
* The points that
dond_ have to be the y intercept and
you choose
In fact There
The a- intercept I chose them for simplicity
may
-
,
.
.
be
Our
1st
point
graphs
has coordinates
calculate slope and
( 12,0)
that
(0/4)
as
don't
have
which
.
th
,
yd
we
.
either of these intercepts
will
rse
as
our
(
n
,
.
,y )
,
to
3) Find the slope
We have
.
:
@
)=(
,Y
0,41
,
Recall
=m=njfnt=yz±
slope
x<
.
x
( Nz
YD
,
.
( 12,0)
Slopes
Substituting these values gives
"
.
be
can
O
y intercepts
-
y
:
m=tIs÷=9KE4Yy=tT¥
too !
-
:
(
You may noice that the units of our slope represents acceleration MAD
This is not a coincidence since we were dividing our velocity ( values)
by time (
The slope
which yields acceleration
,
with
how
how velocity changes with time
and
n
y changes
values)
n
.
y
of
graph represents
a
÷mk
4)
Let's
acceleration
slopes
take
a
on
the units in
m=m¥=
last step
our
's
Msx
=
TIT
the same
dividing a number Amt
Dimensional analysis practice !
Velocity overtime
y
:
4
(nys )
3
iz
5) Equations
For
:
1
2
34
5
6
78
9
.
My
.
.
as
multiplying
y=
-
tzx
r=
10
timers )
its
inverse
11
1314
-
.
+4
meaningful variables ,
and
...
n=t
more
y=r
say
units
:
is
Velocity
'
closer look at determining the
Let's focus
*
IS
we
Et+4
1516117
Ig
Ig
K
can
!