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Date:
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Sex-Linked Inheritance Problems
1. Hemophilia, or bleeder’s disease, is inherited as a recessive
X-linked trait.
If we represent the genotype of a hemophilic woman as Xh Xh
then how
do we represent the following genotypes:
A. normal, non-hemophilic, homozygous woman:
11 j
B. normal man:
1
D. hemophilic man:
X
A
/H ‘I
C. a normal heterozygous woman (carrier>:
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A
A
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xY
2. A normal man marries a normal woman and her father
wasah
Hemophilia will likely occur in
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and
c
..
ohilic
) L’
% of their male children
&
% of their female children
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3. A man with hemophilia has a daughter of normal phenotype.
She marries
a man who is a hemoPhilic.,y i
k
Ily
A. What is the percentage that a daughter of these two will
be a Hemophilic?
B. What is the percentage out of 2 sons that they will be
a Hemophilic?
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y
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x
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4. In Drosophila (fruit flies), the gene that controls eye color is on the X
chromosomeS Red eyes are dominant and white eyes are recessive. If a
heterozygous red eyed female mated with a white eyed male, what would
be the percent of having a white eyed fly?
\f
5)9 w4i4
;
rry
(Xb) is caused by a recessive X-linked trait. If
5. Red-green color blindness
a color-blinded man married a woman with normal vision and NO color
blindness in her family.
a. What is the percentage that they will have a color-blind son?
b. What is the percentage that they will have a carrier daughter?
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h
jOTh/D
6. The mugwump, a type of tree-dwelling mammal, has a reversed sex
romosome condition. The male is an X)( and the female is XY. Even
the sex-chromosomes are switched when comparing to humans,
they still inherit traits the same way.
For example, a recessive X-Iinked trait produces red-green colorblindness
mu wurnp mates with a hetej yous mate
(g). So if a
a. What is the percentage that a son from the mating will be
Vr
colorblind?
b. What is the percentage that a daughter from the mating will be
colorblind?
De7
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Name:
Date:
—
Pedigree Practice
Directions: Using the following Autosomai
recessive pedigree, determine the
of the following numbered individuals.
genotypes
—
r:
—
-
Widow’s Peak
No Widow’s Peak
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2.HV
3.
6.
7.
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Pedigree Practice
given be/ow, create a proper pedigree
ation
inform
the
Using
T&rections:
names of each person.
showing the symbo/s, genotypes, and
becember day. Stan has AB blood
bebbie and Stan were married one
3 daughters. Erin is type A blood,
and bebbie has 0 blood. They have
is
type A blood. Erin married Ken, who
Kristen is type B blood and Julie is
Bill, who is type 0 blood. Kristen
type B blood and they have a son named
They had a daughter named Luna.
married Justin, who is type AB blood.
be?
• What could Luna’s blood type
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JA
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X ñ
A
C
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r ;;
0
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For the pedigree below the trait represented is colorblindness. This is a
recessive trait; normal vision (R) is dominant over colorblindness (r). If a circle or square
is filled in, then the individual is colorblind.
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Fill in the genotypes of all the individuals in the following pedigree:
•
Lf&
X’
II
: r tL
L V—41
Construct a Punnett square for the cross between individuals C and D from the pedigree in item 9.
‘1’
LI)
1’-
xY
Rr
xl
What a,r the possible phenotypes of the children in the above cross?
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7. Usi4 the pediVe* fro
jaber the two rL-ixt
for that.
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Give the gnucyve for all petna ha’ri
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lincs below cch pto’s vtboL
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S. Predict the cypat for aU ec81
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