2, c = 5 x=(-(-2)±√(〖(-2)〗^2-4(3

x–y=3
x2 + y2 = 29
(x + 2)(x – 4) = 0
x(x – 4) +2(x – 4) = 0
x2 – 4x + 2x – 8 = 0
x2 – 2x – 8 = 0
You are working backwards
here. Instead of finding the
value of x, you are given x and
have to form the equation.
Step 1: Create a table to work out the y value for all x values from -3 to 2
x
x2 – x - 2
F(x) / y
-3
(-3)2 – (-3) - 2
10
-2
(-2)2 – (-2) – 2
4
-1
(-1)2 – (-1) – 2
0
0
(0)2 – (0) – 2
-2
1
(1)2 – (1) – 2
-2
2
(2)2 – (2) - 2
0
First Point (x, y) is (-3, 10)
Everywhere you
have x, substitute in
the value in the
previous column
Work out the answer
with your calculator,
and enter it into the
last column
Points from table:
(-3, 10)
(-2, 4)
(-1, 0)
(0, -2)
(1, -2)
(2, 0)