Phase rule • • • Sunday, September 13, 2009 Gibbs Phase Rule Goldschmidt mineralogical phase rule implications for chemographic analysis basis of phase rule • minerals (phases) are reaction products! therefore, they record the reactions that occurred, as well as conditions • why is phase rule useful? • • • Sunday, September 13, 2009 helps to characterize state of the system predict equilibrium relations of phases helps to construct phase diagrams F=C-P+2 • • • • Sunday, September 13, 2009 F = degrees of freedom (variance) C = minimum # components in system P = # phases integers related to # intensive variables (scale independent; e.g., P, T, density, Xmineral) F=C-P+2 • what does Gibbs say? • variance of the system is the minimum # of intensive variables needed to define the state of the system at equilibrium • for each C we add, must specify 1 more variable (more stuff) • for each P we add, 1 less variable need be specified (fewer boxes to put it in) Sunday, September 13, 2009 F=C-P+2 • or, if you change 1 variable, how many other things must you change to maintain the system? • if F = 2, can change either P or T independently • if F = 1, if change one thing, must change the other (or, if know one, you know the other) • if F = 0, cannot change anything and still keep system the same Sunday, September 13, 2009 degrees of freedom • • • Sunday, September 13, 2009 F = 0 invariant (no change in system) F = 1 univariant (equilibrium line) F = 2 divariant (stable phase region) F=2 F=1 F=0 Sunday, September 13, 2009 selecting components CaMg(CO3)2 + 2 SiO2 = CaMgSi2O6 + 2 CO2 dolomite + 2 quartz = diopside + 2 carbon dioxide possible components CaO, MgO, SiO2, CO2 or CaMgO2, SiO2, CO2 which is best? how do we choose? Sunday, September 13, 2009 selecting components suppose we have a pelitic rock containing 5 phases typical of lower amphibolite facies: St + Grt + Bt + Ms + Qtz how many components? Sunday, September 13, 2009 selecting components or suppose we have a mafic rock containing 5 phases typical of greenschist metavolcanics: Act + Chl + Ep + Ab + Qtz how many components? Sunday, September 13, 2009 “degenerate” systems if you can reduce the # components to a limited subset of the whole system that still explains the observed mineral assemblage, this is simpler A e.g., use B-C, rather than A-B-C A33B33C33 B100C0 B Sunday, September 13, 2009 B0C100 B50C50 C selecting components so for our greenschist: Act + Chl + Ep + Ab + Qtz how can we reduce the ACNFMS components? • assume free substitution of Fe & Mg • assume plagioclase is pure Ab (and no Na in others) • assume system is Si-H2O saturated end up with 3 components (ACF); phase rule says F = 3 - 3 + 2 = 2 (not counting Ab & Qtz) so the system is divariant, and might even have more freedom (will come back to this) Sunday, September 13, 2009 intensive variables • need to know how many intensive (massindependent) variables govern the system • • if T & P are variables, F = C - P + 2 Sunday, September 13, 2009 if either one is fixed (constant), the “modified” phase rule becomes F = C - P + 1 “modified” phase rule for a T-X diagram, P = const. A so, only 1 intensive variable B Sunday, September 13, 2009 assumptions • assumptions when applying Gibbs phase rule: • • EQUILIBRIUM!!! sufficient time & energy • no kinetic effects Sunday, September 13, 2009 minerals have uniform, simple structural states (but allows for zoning, disorder, etc.) Goldschmidt’s mineralogical phase rule • • consider F = C - P + 2 normally: • • Sunday, September 13, 2009 as C increases, F increases as P increases, F decreases ... • as C increases, F increases • as P increases, F decreases C=2 P=1 P=2 Sunday, September 13, 2009 C=1 Goldschmidt’s mineralogical phase rule • • consider F = C - P + 2; normally: • • as C increases, F increases as P increases, F decreases GMPR says that for a given rock in equilibrium at a fixed P & T, generally: # phases ≤ # components (P ≤ C) Sunday, September 13, 2009 Goldschmidt’s mineralogical phase rule • Goldschmidt observed that “common” mineral assemblages occur over wide areas in rocks of varying composition • he reasoned, then, that this simpler assemblage (low #P) is a consequence of variable (P, T, X) and hence high #C • it follows, then, that the common situation is to have C > P, and more F Sunday, September 13, 2009 Goldschmidt’s mineralogical phase rule • hence, GMPR rule says that for a rock in equilibrium at fixed P & T, # phases ≤ # components • in general, rock systems are divariant for P & T (i.e., F = 2), so P = C • but because of natural variation in T-P-Xminerals, it is also common that F ≥ 2 • if F ≥ 2 and F = C - P + 2, then P ≤ C! let’s see how this works... Sunday, September 13, 2009 if P = C • this is the standard divariant condition, where F=2 • • you are probably within a mineral zone Sunday, September 13, 2009 all is good if P ≤ C • • • how do we get higher F? • either higher C or variable P-T if we simplify to easy-tounderstand 3-component projection, then we can still maximize C by allowing for solid solution so, consider the system xyz... Sunday, September 13, 2009 3-component projections P, T = const. Sunday, September 13, 2009 what do we know? 3-component projections P, T = const. the independent variable is composition (not P or T) what does the phase rule say? for rock (B) for rock (f) compositionally degenerate Sunday, September 13, 2009 for rock (xyz) 3-component compatibility diagrams P, T = limited C=3 P=1 phases: • pure • 2C ss • 3C ss P=2 P=3 Sunday, September 13, 2009 3-component compatibility diagrams P, T = limited C=3 P=3 for (D), F=3-3+2= 2, but because solid solution allows for small system variation in X, variance F corresponds to P&T there is no compositional freedom in phases!! Sunday, September 13, 2009 3-component compatibility diagrams for (f): F=3-2+2= 3 P, T = limited C=3 P=2 (f) Sunday, September 13, 2009 variance is in P, T and phase compositions (ss) phase compositions determined by system composition recap 3-component compatibility diagrams P, T = limited C=3 F= F= F= Sunday, September 13, 2009 more phases than components? A if C = 3, P = 4? ??? B Sunday, September 13, 2009 C NO! if P > C • F < 2 (you are either on a univariant curve or at an invariant point) • • • as Winter points out, this has lower probability so more common to be divariant disequilibrium? (check phases and textures) • • • Sunday, September 13, 2009 are your minerals in 1 “system”? are some minerals retrograde? is there evidence of incomplete reaction? did not choose components carefully!
© Copyright 2025 Paperzz