Experiment 12 – Calorimetry 02/14/2007 Experiment 12 Calorimetry WS 2006/2007 Authors: Lorenz Germann, Lukas Bischoff Team members: Lorenz Germann, Lukas Bischoff, Adrian Jenni, Dimitri Kokkinis Date: 29.11.2006 Assistant: Ashley Harvey E-mail: [email protected] [email protected] 1/1 Experiment 12 – Calorimetry 02/14/2007 1. Abstract Different calorimetrical measurements were executed. First the solution enthalpy of potassium nitrate was determined. The calculated value (12.854 kJ*mol-1) was three times too small in comparison to the standard value (32.014 kJ*mol-1). Most likely the KNO3 did not dissolve completely or the experiment was stopped too early. Like this only the solution enthalpy for a part of the reaction was calculated. In a second experiment the specific heat capacity (cp) of raw and cooked potatoes were determined. For the raw potatoes the results correspond well with the theory. The results for the cooked potatoes were quite surprising. More experiments should be executed. Lastly an unknown metal should have been identified by calculating its atomic mass out of its cp. This result wasn’t quite clear. The only reasonable possibility was aluminium. The metal’s density was calculated to be sure. It was aluminium indeed. 2/2 Experiment 12 – Calorimetry 02/14/2007 2. Introduction 2.1. Goal The aim of the experiment was to determine the heat of solution of potassium nitrate, the atomic weight of an unknown metal through its heat capacity, and the difference in heat capacity between cooked and raw potatoes as the structure of their starch molecules was changed. 2.2. Theory [1] 2.2.1. Thermodynamics First rule: Energy doesn’t get lost: U = Q+W (1) The internal energy of an insulated system is constant. It is the sum of the work W and the heat energy Q. It is measured in Joule [J]. Second rule: Heat capacity C= dQ/dT (2) The internal energy of a system increases by heating. The temperature difference dT is proportional to the added heat energy Q. Third rule: Enthalpy H = U + pV (3) Enthalpy H is the sum of the internal energy with the multiplication of pressure and volume. The enthalpy designates a quantity of energy, which a thermodynamic system possesses and which can transfer between it and its environment. When the pressure of a system is constant, the enthalpy can be written as H = Q The enthalpy H is lower than 0 for endothermic reactions (heat is put in the substance) and higher than 0 for exothermic reactions (substance transfers heat to environment). Its unit is the Joule. 2.2.2. Calorimeter A calorimeter is a container, thermally insulated from the environment using a material such as styrofoam. In its cover there is a small hole for a Thermometer thermometer. The thermometer is the only measuring instrument needed for this experiment. Cover Styrofoam The insulation is to prevent the calorimeter from losing thermal Insulation Styrofoam energy through the walls. This way the calorimeter can be described as 250ml beaker an independent, insulated container that is usable for thermodynamic 1000ml beaker experiments. Inside the calorimeter, 3/31. Structure of calorimeter Fig. Experiment 12 – Calorimetry 02/14/2007 heat energy can be exchanged between materials, but there ideally is no loss of energy. 2.2.3. Correction factor Before getting started with the experiment there must be found a correction factor that compares the calculated result with the measurement. This correction factor is determined by melting a piece of ice in a predefined mass of water in the calorimeter and the first rule of thermodynamics: H(ice) m(Eis) m + c p (Water) (t'e t A ) = mwater c p (water) (t'e t a ) 1 18g mol (4) tA = 0°C (Temperature of the ice) t’e = calculated final temperature ta = Start temperature water te = final temperature water J cp (water) = 4.1868 g°C J m H(ice) = 6010 mol Correciton factor f: f = Ttheoretical t'e t a = Tmeasured te ta (5) 2.2.4. The rule of Dulong-Petit The specific heat of a metal depends on its atomic weight. The rule of Dulong-Petit says that increasing the temperature of the molar mass of many metals 1°C needs 24J of energy. 24J /°C mol = C p(metal ) M metal (6) 2.2.5. Consistence of potatoes The heat capacity of potatoes cannot specifically be identified because of the vast amount of various sorts. An average potato consists of 77% water, 15% starch, 2% protein, 1,5% organic acids, 1% minerals and 2.5% amino acids, polysaccharides (without starch), sugar, lipids, polyphenols and alkaloids. Its average energy per 100 g is 376.2 kJ. Starch, a polysaccharide is not homogeneous. It consists of 73 - 86% of Amylose and 14 – 27% of Amylopektin. The molecules of Amylopektin and the molecules of Amylose form mixed crystallites, which are bound together by hydrogen bonds. In cool water the starch is not soluble; they extend at maximum 28 vol%. Above a certain temperature (58-66°C) the starch suspension in the water solution dissolves. This increases the viscosity and the conductivity and heat capacity. 4/4 Experiment 12 – Calorimetry 02/14/2007 3. Materials and methods 3.1. Materials Besides the standard equipment of a laboratory there was used a self made calorimeter (see 2.2.2.), potatoes, a microwave and an onion chopper. 3.2. Methods 3.2.1. Calibrate the calorimeter and determine the correction factor First of all, the empty calorimeter was weighed. To determine the correction factor 150.018g of water was put into the calorimeter. The temperature (ta) was measured. Then an ice cube was dried with a paper towel to take away the water on its surface and put into the water. After the calorimeter was immediately closed, the system’s temperature was continuously observed and the minimal temperature was noted. Also the calorimeter was weighed to determine the weight of the ice cube. 3.2.2. Solution enthalpy of potassium nitrate 150.011g of water was put in the empty calorimeter and the temperature ta was measured. Afterwards 15.032g of potassium nitrate (KNO3) was crushed with a mortar and pestle. The potassium nitrate now was given into the calorimeter and the calorimeter was closed. Constantly the calorimeter was agitated to dissolve the KNO3. The temperature was measured. After continuous observation, the temperature stood still on a certain value (te). Using the following formula, the concentration of the potassium nitrate was calculated and with the given chart of the handout, the specific heat capacity of KNO3 was determined: s H ° = m( Lsg ) c p ( KNO3 ) (t a t e ) f 3.2.3. Specific heat capacity of potatoes Raw potatoes Some potatoes were peeled and chopped with the onion chopper. Afterwards 30g were put into the tared calorimeter. Then approximately 100ml water was put into a 250ml beaker and heated for 20 seconds in the microwave oven (highest level). After the temperature was measured the water was given into the calorimeter. While constantly stirring one waited until the temperature was constant. The temperature tEnd was noted. Afterwards the calorimeter was weighed. After cleaning and drying the calorimeter the test was repeated with heating different heating times (30, 60 and 90 seconds). In the end, the specific heat capacity of the potato was calculated. c p (potato ) = m(water ) c p (water ) (tend twater , hot ) f m(potato ) (tend t potato ) 5/5 (7) Experiment 12 – Calorimetry 02/14/2007 Cooked potatoes Finely chopped potatoes were cooked with maximum power in the microwave oven for one minute. After they cooled down, one proceeded in the same way as described for the raw potatoes. Differently to the method above, the water was heated only for 30, 60 and 90 seconds. 3.2.4. Specific heat capacity of an unknown metal Two metal cubes were weighed. The calorimeter was filled with 120g of water. The temperature (ta) was measured. The two metal cubes were heated in boiling water in a beaker for 10’. After the water bath’s temperature (= metal’s temperature, tmetal) was measured, the cubes were thrown in the calorimeter as quickly as possible. After the calorimeter was closed immediately, one waited until the temperature was stable (tEnd). With these results, the specific heat capacity of the metal could be calculated: c p (metal ) = m(water ) c p (water ) (tend t water ) f m(metal ) (tend tmetal ) (8) This experiment was executed three times. To determine the metal, the cp was inserted in the Dulong-Petit formula. 24 J / °C mol = C p ( Metal ) Molmass( Metal ) (9) In order to have a second identification method the volume (V) of the two metal cubes was measured, so that the density () can be determined. = m V 6/6 Experiment 12 – Calorimetry 02/14/2007 4. Results 4.1. Correction factor Table 1. Calculation of correction factor f tA’ [1] cp (water) [1] mH(ice) [1] ta te m (water) m (ice) t’e f 0°C 4.1868 J*g-1*°C-1 6010 J* mol-1 20.4°C 15.9°C 150.018g 9.502g 14.435°C 1.326 As we see in table 1 the calculated correction factor 1.326 is too high. It should lie between 1.05 and 1.2 [1]. 4.2. Solution enthalpy of potassium nitrate Table 2. Calculation of solution enthalpy m (solution) ta te cp (KNO3) from table [1] f sH° for 15.032g sH° for 1 mol 165.043g 20.4°C 18.1°C 3.75 J*g-1*°C-1 1.326 1911.362 J 12.854 kJ*mol-1 The solution enthalpy (sH°) for 1 mol (12.854 kJ*mol-1) depends on the concentration of the solution. It can be calculated as the difference between the standard enthalpy of solution of a KNO3-solution and the standard enthalpy of formation of solid KNO3 (-494.514 kJ mol-1). The proportion in the used solution is 0.148 mol(KNO3)/8.334 mol(H2O) = 1/56.3. A solution with the proportion 1/50 has a standard building enthalpy of -462.887 kJ*mol-1 one with 1/75 -461.916 kJ*mol-1. For the used solution this value is approximately -462.5 kJ*mol-1. So sH° should theoretically be: -462.5 kJ*mol-1- (-494.514 kJ*mol-1) = 32.014 kJ*mol-1 7/7 Experiment 12 – Calorimetry 02/14/2007 4.3. Specific heat capacity of potatoes Table 3. Specific heat capacity of raw potatoes time in microwave oven [s] temperature water [°C] temperature potato [°C] temperature end [°C] mass water [g] mass potatoes [g] cp (raw potatoes) [Jg-1°C-1] cp(water) [Jg-1°C-1] 2 20 53 18.5 41.4 101.97 29.39 7.358 4.1868 30 60 19 46.4 103.48 30.55 7.039 4.1868 60 94 19.7 68.3 105.02 29.95 7.763 4.1868 90 100 21 69.2 102.27 30.82 8.878 4.1868 As we see in table 3 potatoes tend to have a higher specific heat capacity the hotter the water was. Table 4. Specific heat capacity of cooked potatoes time in microwave oven [s] temperature water [°C] temperature potato [°C] temperature end [°C] mass water [g] mass potatoes [g] 30 51.2 19.7 46.1 105.8 30.87 60 89.1 21.9 68.1 96.29 31.1 90 100 21.5 74.5 108.9 31.65 cp (cooked potatoes) [Jg-1°C-1] 2.772 5.892 6.931 4.1868 4.1868 4.1868 cp(water) [Jg-1°C-1] 2 Table 4 shows that the cooked potatoes have a lower specific heat capacity than the raw ones. They also tend to have higher cp values in hotter water. There is a significant rising of the cp from 30 to 60 seconds long heated water. Figure 2: Heat Capacity of the potato 8/8 Experiment 12 – Calorimetry 02/14/2007 4.4. Specific heat capacity of an unknown metal Table 5. Calculation of metal’s specific heat capacity and molar mass temperature Water [°C] mass calorimeter [g] mass metal [g] mass water [g] temperature metal [g] end temperature [°C] cp metal [Jg-1°C-1] molar mass [gmol-1] 20.4 21.0 21.4 384.18 384.18 384.18 43.4602 120.005 95.0 43.4602 120.060 93.7 43.4602 120.012 92.3 25.3 25.7 26.4 0.812 29.531 0.799 30.022 0.877 27.360 The average calculated molar mass plus standard difference is: x + SD = 28.971 ± 1.4 So the best matching element is silicon (28.09 gmol-1). But silicon is not a metal. Considering all the faults in executing the experiment and measuring, even values that are not included in the standard difference are possible. So it could be aluminium (26.98 gmol-1) as well. The density of the used metal was calculated as 2.716 g*cm-3. The density of silicon is 2.33 g*cm-3, of aluminium it’s 2.7 g*cm-3 [3]. Now the metal can definitively be identified as aluminium. 9/9 Experiment 12 – Calorimetry 02/14/2007 5. Discussion 5.1 Solution enthalpy of potassium nitrate KNO3 dissolves to K+ and NO3-. It is possible that there are further reactions to consider that might affect the result of the solution enthalpy. While K+ stays in the solution as itself, the NO3- is the conjugated base to the strong acid HNO3. It can be concluded that NO3- also stays as itself in the solution without reaction. So there are no chemical processes that influence the result. To break a chemical bond, energy is needed. Having the calorimeter as closed system, the energy for the bond break has to be taken out of the internal energy of the water (see the first rule of thermodynamics: the internal energy of a system is constant), which results in a deeper te for water. Using the formulas for the specific heat capacity, a calorimeter can be used to get approximate specific bond energy. With the used calorimeter in this experiment the result would be quite imprecise. The calculated solution enthalpy of the used solution (12.854 kJ*mol-1) is approximately three times too low (value calculated out of standard data: 32.014 kJ*mol-1 [1]). It is highly probable that the KNO3 did not dissolve completely. Like this, less energy was taken from the system (water) as it would take to dissolve KNO3 entirely. So the measured end temperature (te) of 18.1°C is too high and the value for cp is too small. By testing different values for te it was found that the correct te should be something like 14.7°C. With this value the cp becomes 31.856 kJ*mol-1 which nearly equals the value calculated out of standard data (32.014 kJ*mol-1). To get a better result one should make sure that the KNO3 dissolves completely. It’s not enough to just swing the calorimeter. The solution in the calorimeter should be mixed by using a magnet stirrer. Further one should wait longer until the end temperature is noted. 5.2. Specific heat capacity of potatoes 5.2.1. Raw potatoes The results correspond well with the theory. In water above 60°C the cp is higher. At about 60°C the starch is starting to dissolve in the water. This causes a higher heat capacity. 5.2.2. Cooked potatoes Generally the cp of cooked potatoes is lower than the one for raw potatoes. According to Fig B1 of the Journal of Materials Education [4], it can be seen that heat capacity of the potato increases until it is fully cooked. Then, the heat capacity abruptly falls on a significant deeper level and increases again with alternated temperature, still at a deep level. This is exactly the same as 10/10 Experiment 12 – Calorimetry 02/14/2007 observed in this experiment (fig 2). The bend in the curve of the cp at the state of the cooked potato might be affected by the broken hydrogen bonds. 5.3. Identify a metal by its specific heat capacity The determination of the metals atomic mass by its cp did not lead to a clear result. The only possible metal is aluminium. But its atomic mass (26.98 gmol1 ) is not included in the interval of the calculated atomic mass 28.971± 1.4. Only by determining the metals density (2.716 g*cm-3) it was definitively identified as aluminium (2.7 g*cm-3). The cp of the metal is quite deep with an average value of 0.829 Jg-1°C-1 compared to the cp of water (4.1868 Jg-1°C-1). This means that the metal looses its temperature quickly. An explanation for the problems of identifying the metal is, that the metal lost too much of energy while putting it from the hot water bath to the calorimeter: Before putting it in the calorimter, the metal was allowed to drip down the hot water so that no hot water comes in the calorimeter and falsifies the results. In this period (1-2s) the metal might have lost too much energy. The experiment could be enhanced more exactly using a metal with a higher specific heat capacity. 11/11 Experiment 12 – Calorimetry 02/14/2007 6. References [1] Handout Versuch 12 Kalorimetrie, D-MATL, ETH Zurich, WS 06/07 [2] http://de.wikipedia.org/wiki/Silizium Visited 01/29/2007 [3] http://de.wikipedia.org/wiki/Aluminium Visited 01/26/2007 [4] Journal of Materials Education 14 (1&2), sent as e-mail-attachement by Ashley Harvey 12/12
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