SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P1 Compund: a substance that can be decomposed by chemical action into simpler substance. I.e. ; lime CaO Element: a substance that cannot be decomposed by normal chemical action into simpler substance, i.e. Na (sodium) Molecule: the smallest particles of a compund (i.e.: CO2) or group of elements (i.e.: O2) that can exist by itself. Atom: the smalest particle of an element that has the properties of that element. Subatomic: particles smaller than an atom, i.e.: proton, electron, neutron. + 12 6 Proton Neutron Electron Nucleus of carbon-12 atom: C Z = atomic number = 6 protons 6 Neutrons A= mass number = 12 SCC-CH110/UCD-CH41C A Z Sy 1 1 H 3 2 He 4 2 He Chapter: 5 Instructor: J.T. A= mass number = + Z= atomic number = + + + + + + + P2 SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P3 Alpha (α) particles: The nucleus of a helium atom. + Radioactivity: + The property of spontaneous emission of rays and/or particles from an atomic nucleus. Scintillation Source α,γ Radioactive element Detector Screen A device consisting of a surface coated with zinc sulphide. When alpha particles hit the surface, it scintillates. Results of Rutherford (1911) experiments: Every atom contains an extremely dense nucleus. All of positive charge is concentrate in the nucleus. The nucleus is surrounded by a large volume of empty space that makes up the rest of atoms. SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P4 Electrons very thinly populate the space outside the nucleus. Dalton’s atomic theory (1803): 1) Each element is composed of extremely small particles called atoms (indivisible). 2) All atoms of a given element are identical. 3) Atoms are neither created nor destroyed in chemical reactions. [Low of conservation of matter] 4) A given compound always has the same relative number and kind of atoms. [Low of constant composition] A good theory should also predict new fact! Dalton used his theory to deduce the low of multiple proportions: If two elements A and B combine to form more than one compound, the masses of B that can combine with a given mass of A are in the ratio of small whole numbers. Example: water & hydrogen peroxide H2O : H2O2 8.0 g of oxygen combines with 1.0 g of hydrogen. 8.0/1.0 = 8.0 16.0 g of oxygen combines with 1.0 g of hydrogen. 16.0/1.0=16.0 16.0 : 8.0 = 2:1 SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P5 Using the atomic theory, we can conclude that hydrogen peroxide contains twice as many atoms of oxygen per hydrogen atom as does water. Subatomic particles: Following Faraday, Crookes studies about Cathode rays in 1897 Thomson’s paper is accepted as the discovery of electron. Proton was discovered in 1919 by Rutherford (α particles scattering model). J. Chadwick discovered neutron in 1932. mp me = 1836 ¾ The atom contains a small positively charged nucleus surrounded by electrons. ¾ The nucleus is at least 100,000 times smaller than the atom. SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P6 ¾ The nucleus consists of protons and neutrons (exception H atom). ¾ Atoms of a particular element that differ only in the number of neutrons in the nucleus are called isotopes. Isotopes: Atoms of a particular element that differ only in the number of neutrons in the nucleus are called isotopes. Atomic Mass Units Chemists use an arbitrary unit called the amu or the Dalton. Mass of one carbon-12 is chosen as an arbitrary standard reference mass, as exactly 12 amu. Therefore: 1 amu = 1 Dalton = 1/12 mass of the 12C = 1.6606 x10-24 g The atomic mass of an element: the average mass of all isotopes of an element as they occur in nature. SCC-CH110/UCD-CH41C Chapter: 5 Instructor: J.T. P7 Example: calculate the atomic mass of a Cl atom base on the following information: Isotope amu naturally occurring 34.96885272 75.78% 35 17 37 17 Cl Cl 36.96590262 24.22% 0.7578 x 34.96885272 = 26.4993965912 amu = 26.50 0.2422 x 36.96590262 = 8.95314732564 amu = 8.953 1.000 average atom 35.45 amu
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