Lesson 9 NYS COMMON CORE MATHEMATICS CURRICULUM M1 ALGEBRA I Lesson 9: Multiplying Polynomials Student Outcomes ο§ Students understand that the product of two polynomials produces another polynomial; students multiply polynomials. Classwork Exercise 1 (15 minutes) Exercise 1 a. Gisella computed πππ × ππ as follows: Can you explain what she is doing? What is her final answer? She is using an area model, finding the area of each rectangle and adding them together. Her final answer is π, πππ. Use a geometric diagram to compute the following products: b. (πππ + ππ + π) × (ππ + π) πππ + ππππ + πππ + π c. (πππ + πππ + π)(ππ + π + π) πππ + ππππ + ππππ + πππ + π d. (π β π)(ππ + πππ β π) ππ + πππ β πππ β ππ + π Ask the students: ο§ What do you notice about the terms along the diagonals in the rectangles you drew? Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 98 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 9 M1 ALGEBRA I Encourage students to recognize that in parts (b) and (c), the terms along the diagonals were all like terms; however, in part (d) one of the factors has no π₯-term. Allow students to develop a strategy for dealing with this, concluding with the suggestion of inserting the term + 0π₯, for a model that looks like the following: Students may naturally ask about the division of polynomials. This topic will be covered in Algebra II, Module 1. The extension challenge at the end of the lesson, however, could be of interest to students inquiring about this. ο§ Could we have found this product without the aid of a geometric model? What would that look like? Go through the exercise applying the distributive property and collecting like terms. As a scaffold, remind students that variables are placeholders for numbers. If π₯ = 5, for example, whatever the quantity on the right is (270), you have 5 β 1 of βthat quantity,β or 5 of βthat quantityβ minus 1 of βthat quantity.β Similarly we have π₯ of that quantity, minus 1 of that quantity. (π₯ β 1)(π₯ 3 + 6π₯ 2 β 5) π₯(π₯ 3 + 6π₯ 2 β 5) β 1(π₯ 3 + 6π₯ 2 β 5) π₯ 4 + 6π₯ 3 β 5π₯ β π₯ 3 β 6π₯ 2 + 5 π₯ 4 + 5π₯ 3 β 6π₯ 2 β 5π₯ + 5 Exercise 2 (5 minutes) Have students work Exercise 2 independently and then compare answers with a neighbor. If needed, facilitate agreement on the correct answer by allowing students to discuss their thought processes and justify their solutions. Exercise 2 Multiply the polynomials using the distributive property: (πππ + π β π)(ππ β ππ + π). πππ (ππ β ππ + π) + π(ππ β ππ + π) β π(ππ β ππ + π) πππ β πππ + πππ + ππ β πππ + π β ππ + ππ β π πππ + ππ β ππ β πππ + ππ + ππ β π Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 99 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 9 NYS COMMON CORE MATHEMATICS CURRICULUM M1 ALGEBRA I Exercise 3 (10 minutes) Give students 10 minutes to complete Exercise 3 and compare their answers with a neighbor. Exercise 3 The expression ππππ + πππ is the result of applying the distributive property to the expression πππ (π + ππ). It is also the result of applying the distributive property to π(πππ + πππ ) or to π(πππ + πππ ), for example, or even to π β (ππππ + πππ ). For (a) to (j) below, write an expression such that if you applied the distributive property to your expression, it would give the result presented. Give interesting answers! a. ππ + ππππ b. πππ + πππ + ππππ c. πππ β πππ d. ππππ β πππ + ππππ e. ππ (π + π) + ππ (π + π) f. π π ππ + π π g. ππππ ππ β πππ ππ + πππ ππ + πβπππ ππ h. π. πππ β ππππ i. (ππ + π)(ππ + ππ ) β (ππ + π)(ππ + ππ ) j. (ππ + π)(π β π) β (πππ β ππ)(π β π) Some possible answers: a. ππ(π + ππ) or π(ππ + πππ ) or π(π + πππ) b. πππ (π + π + ππ ) or π(πππ + πππ + πππ ) or π(ππ + ππ + πππ ) c. ππ(ππ β π) or π(πππ β ππ) or π(ππ β ππ) d. ππ(πππ β π + ππππ ) or π(ππππ β ππ + ππππ ) e. ππ ((π + π) + π(π + π)) or π(π(π + π) + ππ (π + π)) f. π π (πππ + π) g. πππ ππ (ππππ β πππ + πππ + βππππ ) or ππ ππ (πππππ β πππ + πππ + πβππππ ) h. π. πππ (π β πππ) or i. (ππ + ππ )((ππ + π) β (ππ + π)) j. (π β π)((ππ + π) β ππ(π β π)) π π π (π β πππ) ππ Choose one (or more) to go through as a class, listing as many different rewrites as possible. Then remark: ο§ The process of making use of the distributive property βbackwardβ is factoring. Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 100 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 9 NYS COMMON CORE MATHEMATICS CURRICULUM M1 ALGEBRA I Exercise 4 (5 minutes) Exercise 4 Sammy wrote a polynomial using only one variable, π, of degree π. Myisha wrote a polynomial in the same variable of degree π. What can you say about the degree of the product of Sammyβs and Myishaβs polynomials? The degree of the product of the two polynomials would be π. Extension Extension Find a polynomial that, when multiplied by πππ + ππ + π, gives the answer πππ + ππ β ππ β π. πβπ Closing (6 minutes) ο§ Is the product of two polynomials sure to be another polynomial? οΊ ο§ Is a polynomial squared sure to be another polynomial? οΊ ο§ Yes, by the definition of polynomial expression given in Lesson 8, the product of any two polynomial expressions is again a polynomial expression, which can then be written in standard polynomial form through application of the distributive property. Yes. The product of any two polynomial expressions is again a polynomial expression, and squaring a polynomial is the same as finding the product of the polynomial times itself. What about a polynomial raised to a larger integer exponent? οΊ It would still be a polynomial because raising a polynomial to a positive integer exponent is the same as finding a series of polynomial products, each of which is guaranteed to be a polynomial. Exit Ticket (4 minutes) Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 101 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 9 M1 ALGEBRA I Name ___________________________________________________ Date____________________ Lesson 9: Multiplying Polynomials Exit Ticket 1. Must the product of three polynomials again be a polynomial? 2. Find (π€ 2 + 1)(π€ 3 β π€ + 1). Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 102 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 9 NYS COMMON CORE MATHEMATICS CURRICULUM M1 ALGEBRA I Exit Ticket Sample Solutions 1. Must the product of three polynomials again be a polynomial? Yes. 2. Find (ππ + π)(ππ β π + π). ππ + ππ β π + π Problem Set Sample Solutions 1. Use the distributive property to write each of the following expressions as the sum of monomials. a. ππ(π + π) b. π ππ + ππ + π ππ + πππ c. π π (πππ + ππππ ) d. (π β π)(π + π) f. ππ + π β ππ g. (πππ β π)(πππ + π) h. π π ππππππ ( ππππ + π. ππππ) j. l. (π β π)(π + π)(ππ + π) n. ππ β π o. (π + π)(ππ β ππ + ππ β π + π) ππ + π π(ππ + π)(ππ β π) π πππ(πππ + π) β πππ(π + π β π) ππππ ππ + ππππ β ππππ β πππ π + ππππ π π β ππ + ππ β π m. (ππ + π)(πππ + π) πππ + πππ + ππ + π (ππ β π + π)(π β π) π (βππ β π)ππ βπππ β πππ πππππ + πππππ k. (ππ β π)(πππ + π) πππ β πππ + ππ β π πππππ β π i. ππ(ππ β ππ) πππ β πππ πππ + ππ e. π(π + π) + π p. π ππππ + ππ π + ππ π + πππ + πππ + ππ π + πππ ππ β π β ππ Lesson 9: (π + π)(π + π)(π + π) Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 103 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 9 NYS COMMON CORE MATHEMATICS CURRICULUM M1 ALGEBRA I q. π+π (πππππ β ππππ ) ÷ π r. π ππππ β πππ π π π+ π π π s. βππ(ππ + π β π) β π(π β ππ ) (π+πβπ)(π+π+π) t. ππ βπππ β πππ + πππ βπ u. (ππ ÷ π + (ππ) ÷ π) ÷ (βπ) β 2. π π π π π π π π + π β π + ππ ππ ππ ππ ππ (βπππ β ππ + π)(ππ β π + π) v. πππ ππ βπππ + πππ β πππ + πππ β ππ + π Use the distributive property (and your wits!) to write each of the following expressions as a sum of monomials. If the resulting polynomial is in one variable, write the polynomial in standard form. a. (π + π)π b. ππ + πππ + ππ d. (π + π)π e. (π + π)π h. (π + π)π ππ + ππ + π (π + π + π)π f. ππ + ππ + ππ + πππ + πππ + πππ ππ + ππ + π j. c. ππ + ππ + π ππ g. (π + π)π (π + π)π (π + π + π)π ππ + ππ + πππ + ππ + ππ + π i. ππ + πππ π + ππππ + ππ (π β π)π ππ β πππ + ππ β π (π + π)π ππ + ππππ + πππ + πππ 3. Use the distributive property (and your wits!) to write each of the following expressions as a polynomial in standard form. a. (ππ + π)(π β π) b. ππ β ππ + ππ β π c. πππ β πππ + πππ β ππ π(ππ + π)(π β π) d. (π β π)(ππ + ππ + ππ + ππ + π + π) π π βπ g. (π + π)(ππ + π)(π β π) ππ + πππ β π ππ β ππ + πππ β ππ e. π(ππ + π)(π β π) f. βπ(π β π)(ππ + ππ + ππ + ππ + π + π) βπππ β βπ (ππ + ππ + π)(π β π)(ππ + ππ + ππ + ππ + π + π) πππ + ππ β ππ + ππ β ππ β π Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 104 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 9 M1 ALGEBRA I Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 105 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 9 M1 ALGEBRA I 4. Beatrice writes down every expression that appears in this Problem Set, one after the other, linking them with + signs between them. She is left with one very large expression on her page. Is that expression a polynomial expression? That is, is it algebraically equivalent to a polynomial? Yes. What if she wrote β signs between the expressions instead? Yes. What if she wrote × signs between the expressions instead? Yes. Lesson 9: Multiplying Polynomials This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG I-M1-TE-1.3.0-07.2015 106 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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