Practice Unit Assessment (1) for National 5 Expressions and Formulae 1. Simplify, giving your answer in surd form: 2. (a) Simplify (b) The number of people attending a football match was 3·12 × 104. If each person paid £27, how much was collected? Give you answer in Scientific Notation. 3. (i) 32 x4 x6 x3 (ii) 5x 4 4 x 52 Expand and simplify where appropriate: (a) d(4d – e) y² – 6y (g + 4)(g + 9) t² – 49 4. Factorise: 5. Express x² + 6x + 7 in the form (x + p)² + q. 6. Write 7. Write each of the following as a single fraction: (a) (a) (b) (b) (c) x² + 7x + 12 (4 x 3)( x 4) ( x 4) in its simplest form. ( x 4) 2 3 5 a b (a, b 0) (b) f e 5 g ( g 0) 8. Points P and Q have coordinates (–5, –4) and (6, 3) respectively. Calculate the gradient of PQ. 9. Calculate the volume of a sphere with radius 2·3 cm, giving your answer correct to 2 significant figures. 2·3 cm Pegasys 2013 10. The logo for Cyril's Cars is shown below. The logo is a sector of a circle of radius 6∙2 cm. The reflex angle at the centre is 240o. A 240o B 11. (a) Calculate the length of the arc AB. (b) Cyril wants to jazz up the logo by outlining it with coloured rope. He buys 20 metres of rope. How many logos would he be able to makeup? Sherbet in a sweet shop is stored in a cylindrical container like the one shown in diagram 1. 20cm 32cm Diagram 1 The sherbet is sold in conical containers with diameter 5 cm and height 6 cm as shown in diagram 2. 5 cm 6 cm Diagram 2 The shop owner thinks he can fill 260 cones from the cylinder. Is he correct? End of Question Paper Pegasys 2013 Practice Unit Assessment (1) for Expressions and Formulae: Marking Scheme Points of reasoning are marked # in the table. Question Main points of expected responses 1 2 1 2 3 4 5 start of process simplified surd simplify numerator correct answer correct coefficient simplify indices calculation of amount 1 2 1 2 3 6 express in standard form 4 (a) (b) 2 3 1 2 (c) 3 4 multiply out brackets multiply out the brackets collect like terms factorise expression factorise difference of two squares start to factorise trinomial expression complete factorisation 6 1 2 3 1 2 5 1 2 6 1 2 (a) (i) (ii) (b) 3 (a) (b) 1 4 5 3 √16√2 (or equivalent) 4√2 x10 x7 20 3 3 x 2 in answer 20 x 2 27 × 3·12 × 104 =84·24 × 104 £8·424 × 105 4d2 – de g2 + 4g + 9g + 36 g2 + 13g + 36 y(y – 6) (t + 7)(t – 57) 4 (x 3)(x 4) ie evidence of brackets, x, 3 and 4 (x + 3)(x + 4) start of process complete process 1 2 (x + 3)2 (x + 3)2 – 2 1 reduce to simplest form 1 4x 3 x4 7 (a) 1 denominator correct 1 (b) 2 numerator correct 3 multiply by inversion of fraction correct answer 3 1 evidence of gradient calculation 1 Uses 2 correct gradient 2 7 11 4 8 Pegasys 2013 2 4 /// ab 3b 5a ab g e fg 5e y 2 y1 or equivalent x 2 x1 9 10 (a) (b) 11 1 substitute and start calculation 1 2 complete calculation 2 4 2 33 3 4 12 167 or 3 equivalent 50·939 cm³ or equivalent 3 round calculation to 2 significant figures 3 51 cm3 1 correct ratio and substitution 1 2 240 12 4 360 calculate arc length 2 25·957 cm or equivalent #2.1 #2.2 valid strategy interpretation of answer #2.1 uses valid strategy to find volumes of cone and cylinder 1 2 calculate volume of cylinder calculate volume of cone # 2.2 states conclusion Pegasys 2013 #2.1 eg 2 000 ÷ 38 #2.2 (for 52∙63) 52 logos can be made. # 2.1 Substitutes relevant values into correct formulae 1 2 10 048 cm3 or equivalent 39∙25 cm3 or equivalent # 2.2 Shop owner is wrong because only 256 cones can be filled Practice Unit Assessment (2) for National 5 Expressions and Formulae 1. Simplify, giving your answer in surd form: 2. (a) Simplify (b) The number of people attending a musical was 2·64 × 103. If each person paid £34, how much was collected. Give you answer in Scientific Notation. 3. (i) 54 x 7 x 3 x2 1 (ii) 2 x 2 3 x 3 Expand and simplify where appropriate: (a) g(6g – h) k² – 7k (d + 3)(d – 7) x² – 81 4. Factorise: 5. Express x² – 8x + 1 in the form (x + p)² + q. 6. Write 7. Write each of the following as a single fraction: (a) (a) (b) (b) (c) z² + 10z + 21 (3x 1)( x 3) ( x 3) in its simplest form. ( x 3) 2 5 7 c d (c, d 0) (b) k k 7 h (h 0) 8. Points R and S have coordinates (3, –2) and (–6, –3) respectively. Calculate the gradient of RS. 9. Calculate the volume of a sphere with radius 3·7 cm, giving your answer correct to 2 significant figures. 3·7 cm Pegasys 2013 10. The diagram shows a sector of a circle with radius 5·6 cm and angle at the centre 230o. A 230o B 11. (a) Calculate the length of the arc AB. (b) The sector has to be made up into a cone with a fur trim round its base. How many cones could be trimmed from 40 metres of fur? During a cross country race, juice is distributed to the runners in conical containers with diameter 6 cm and height 8 cm as shown in diagram 1. 6 cm 8 cm Diagram 1 At the end of the race juice from 60 cones is poured into a cylinderical container with dimensions as shown in Diagram 2. 15cm 25cm Diagram 2 Will this container be large enough to hold the juice? End of Question Paper Pegasys 2013 Practice Unit Assessment (2) for Expressions and Formulae: Marking Scheme Points of reasoning are marked # in the table. Question Main points of expected responses 1 1 simplify surd 1 3√6 2 (a) (i) 2 3 4 5 simplify numerator correct answer correct coefficient simplify indices calculation of amount 2 3 4 5 x4 x2 6 6 express in standard form 4 (a) (b) 1 2 3 1 2 (c) 3 4 multiply out brackets multiply out the brackets collect like terms factorise expression factorise difference of two squares start to factorise trinomial expression complete factorisation 6 1 2 3 1 2 5 1 2 6 (ii) (b) 3 (a) (b) 1 1 3 5 52 x 2 in answer 6 x 34 × 2·64 × 103 =89·76 × 103 8·976 × 104 6g2 – gh d2 – 7d + 3d – 21 d2 – 4d – 21 k(k – 7) (x + 9)(x – 9) 4 (z 3)(z 7) ie evidence of brackets, z, 3 and 7 (z + 3)(z + 7) start of process complete process 1 2 (x – 4)2 (x – 4)2 – 15 1 reduce to simplest form 1 3x 1 x3 7 (a) 1 denominator correct 1 (b) 2 numerator correct 3 multiply by inversion of fraction correct answer 3 1 evidence of gradient calculation 1 Uses 2 correct gradient 2 1 9 4 8 Pegasys 2013 2 4 /// cd 5d 7c cd h k k 7 y 2 y1 or equivalent x 2 x1 9 10 (a) 1 substitute and start calculation 1 2 complete calculation 2 4 3 73 3 4 50 653 or 3 equivalent 212·067 cm³ or equivalent 3 round calculation to 2 significant figures 3 210 cm3 1 correct ratio and substitution 1 230 11 2 360 2 calculate arc length 2 22·468 cm or equivalent (b) 11 #2.1 #2.2 valid strategy interpretation of answer #2.1 eg 4 000 ÷ 22·468 #2.2 (for 178∙02) 178 cones can be trimmed. #2.1 uses valid strategy to find volumes of cone and cylinder # 2.1 Substitutes relevant values into correct formulae 1 2 calculate volume of cone calculate volume of cylinder # 2.2 states conclusion Pegasys 2013 1 2 75·36 cm3 or equivalent 4415∙625 cm3 or equivalent # 2.2 cylinder is not big enough since 75·36 × 60 > volume of cylinder Practice Unit Assessment (3) for National 5 Expressions and Formulae 1. Simplify, giving your answer in surd form: 2. (a) Simplify (b) A factory produces 2·4 × 104 cakes every day. How many cakes will it produce in the month of April? Give you answer in Scientific Notation. 3. (i) 147 x 2 x8 x 3 1 (ii) 6 x 3 3x 2 Expand and simplify where appropriate: (a) m(3m – n) (p + 5)(p + 8) h² – 11h (b) q² – 144 4. Factorise: 5. Express x² + 7x + 9 in the form (x + p)² + q. 6. Write 7. Write each of the following as a single fraction: (a) (a) (b) (c) a² – 12z + 32 (2 x 5)( x 7) ( x 2 5) in its simplest form. (2 x 5) 2 4 9 m n (m, n 0) (b) 4 k k l (h 0) 8. Points C and D have coordinates (–8, –2) and (6, –4) respectively. Calculate the gradient of CD. 9. Calculate the volume of a cone with diameter 4·6 cm and height 7 cm giving your answer correct to 2 significant figures. 4·6 cm 7 cm Pegasys 2013 10. (a) Calculate the area of the sector of a circle in the diagram which has radius 6∙8cm. o O135 42o (b) These sectors have to be cut from a piece of card with an area of 6500 cm². Assuming there is not waste, how many sectors can be cut from the card? 11. A candle is in the shape of a sphere with a diameter of 10 cm. (a) Calculate the volume of the candle. The candle was melted down and poured into a conical container like the one shown in this diagram. 11 cm 18 cm (b) Will the cone be big enough to hold the wax? [assume there is no wax lost during the melting process] End of Question Paper Pegasys 2013 Practice Unit Assessment (3) for Expressions and Formulae: Marking Scheme Points of reasoning are marked # in the table. Question Main points of expected responses 1 1 simplify surd 1 7√3 2 (a) (i) 2 3 4 5 simplify numerator correct answer correct coefficient simplify indices calculation of distance 2 3 x10 x13 18 4 5 6 express in standard form 4 (a) (b) 1 2 3 1 2 (c) 3 4 multiply out brackets multiply out the brackets collect like terms factorise expression factorise difference of two squares start to factorise trinomial expression complete factorisation 6 1 2 3 1 2 x 3 in answer 18 x 30 × 2·4 × 104 =72 × 104 7·2 × 105 3m2 – mn p2 + 8p + 5p + 40 p2 + 13p + 40 h(h – 11) (q + 12)(q – 12) 5 1 2 6 (ii) (b) 3 (a) (b) 1 1 3 5 53 4 (a 4)(a 8) ie evidence of brackets, a, 4 and 8 (a – 4)(a – 8) start of process complete process 1 2 (x + 3·5)2 (x + 3·5)2 – 3·25 1 reduce to simplest form 1 x7 2x 5 7 (a) 1 denominator correct 1 (b) 2 numerator correct 3 multiply by inversion of fraction correct answer 3 1 evidence of gradient calculation 1 Uses 2 correct gradient 2 4 8 Pegasys 2013 2 4 /// mn 4n 9m mn l k 4l k2 1 7 y 2 y1 or equivalent x 2 x1 9 10 (a) 1 substitute and start calculation 1 2 complete calculation 2 1 2 32 7 3 1 37 03 or 3 equivalent 37·75806 cm³ or equivalent 3 round calculation to 2 significant figures 3 38 cm3 1 correct ratio and substitution 1 135 6 82 360 2 calculate sector area 2 54·4476 cm or equivalent (b) 11 #2.1 #2.2 valid strategy interpretation of answer #2.1 eg 6 500 ÷ 54·4476 #2.2 (for 119∙38) 119 sectors can be cut. #2.1 uses valid strategy to find volumes of cone and sphere # 2.1 Substitutes relevant values into correct formulae 1 2 calculate volume of sphere calculate volume of cone # 2.2 states conclusion Pegasys 2013 1 2 523·33 cm3 or equivalent 569∙91 cm3 or equivalent # 2.2 cone is big enough since 523·33 < 569∙91
© Copyright 2026 Paperzz