CHEMISTRY 12 – PREDICTING PRECIPITATE FORMATION &
MAXIMUM [ION] WORKSHEET
1) Will a precipitate form when 25.0 mL of 0.15 M AgNO3 is added to 15.0 mL of 0.20 M NaCl?
Support your answer with appropriate calculations. (4 marks)
[ AGNOD
[ NACD
0.20
-
Mx
0.15
=
M
Tm
Agdcs)
Trial
Nad
Agttcl
=
Ksp
=
=
Ksp
.
}
Natta
→
0
'
0.075N
0.075N
=
>
oosm
=
Tu
0.094N
0.094N
0.094 M
=
15.0mL
x
}→Ag+tN05
AGNO
Trial Ksp
25.0mL
0
CAGDCCIJ
(0.094×0.075)
7.0×10-30
(1.8×100)
.
:
a
Ppt
forms
D
2) Does a precipitate form when 3.0 mL of 1.0 x 10-3 M NaBr is added to 2.0 mL of 1.0 x 10-3 M
Pb(NO3)2? (4 marks)
[ NaBr]=
1.0×10
'3Mx
3.0mA
=
6.0×10
'm
CPbw03bifl.0xlo3Mx2.qmf.4.oxl04nB0NaBroNattBr-pbwosbnsPb2tt2N056.0x1o4M6.0xl04M4.oxw4M4.Ox104MPbBr2cDFpb2tt2Br-0TrialKsp-CPb2tXBrT2-C4Ox1o4k6.Ox1092-1.4x1ot0@TrialKspcKspC6.6x109i.n
oppt
forms
0
3) Will a precipitate form when 90.0 mL of 1.00 x 10-2 M Cu(NO3)2 and 10.0 mL of 1.00 x 10-2 M
NaIO3 are mixed? Explain using appropriate calculations. (4 marks)
4) Will a precipitate form if 30.0 mL of 0.054 M Ca(NO3)2 is mixed with 60.0 mL of 8.1 x 10-4 M
Na2SO4? (4 marks)
5) Calculate the maximum [CO32-] that can exist in 0.0010 M Mg(NO3)2. (3 marks)
6) Calculate the maximum mass of BaCl2 (s) that can be added to 250.0 mL of 0.50 M Pb(NO3)2 (aq)
without forming a precipitate of PbCl2 (s). (6 marks)
7) Calculate the mass of NaI necessary to begin precipitation of Cu+ from a 250.0 mL sample of 0.010
M CuNO3. (4 marks)
8) A container is filled with 10.0 L of 0.050 M NaI. Calculate the maximum mass of solid Pb(NO3)2
that can be dissolved without forming a precipitate. (3 marks)
9) What is the maximum [Ag+] that can exist in 0.20 M NaBrO3? (2 marks)
10) A solution contains 0.020 M Ba2+ and an unknown concentration of Sr2+. When dilute Na2CO3 is
slowly added to the mixture, both Ba2+ and Sr2+ start to precipitate at the same time.
(a) Calculate the [CO32-] when BaCO3 starts to precipitate. (3 marks)
(b) Calculate the initial [Sr2+]. (3 marks)
SRCO }
Ksp
5.6×10+0
(
→←
)
sr2+][
[
=
X
s
×
=
=
Sr*t
Cost
Cog -]
0
( 1.3×03
4.3×10
-
3M
D
0